Fractran: Difference between revisions
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And no, fraction #9 is not always the one with the power of two. So, even a 64-bit integer is not enough, and with a 32-bit integer, |
And no, fraction #9 is not always the one with the power of two only, for instance step 130 with N = 2<sup>4</sup>x7. So, even a 64-bit integer is not enough, and with a 32-bit integer, |
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<pre> |
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Integer overflow! |
Integer overflow! |
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