Fortunate numbers: Difference between revisions

m
simpler
(julia example)
m (simpler)
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primorial = primorials(800)
 
fortunate(n) = findfirst(m -> isprimenextprime(primorial[n] + m), 3:2:2000) *- 2 + 1primorial[n]
 
foreach(p -> print(rpad(last(p), 5), first(p) % 10 == 0 ? "\n" : ""),
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373 379 383 397 401 409 419 421 439 443
</pre>
 
 
=={{header|Nim}}==
4,105

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