Floyd's triangle: Difference between revisions

=={{header|Icon}} and {{header|Unicon}}==

The following solution works in both languages:

<lang unicon>procedure main(a)

n := integer(a[1]) | 5

w := *string((n*(n+1))/2)+1

c := create seq()

every i := 1 to n do {

every writes(right(|@c\i,w))

write()

}

end</lang>

Sample outputs:

<pre>

->ft

1

2 3

4 5 6

7 8 9 10

11 12 13 14 15

->

</pre>

<pre>

->ft 14

1

2 3

4 5 6

7 8 9 10

11 12 13 14 15

16 17 18 19 20 21

22 23 24 25 26 27 28

29 30 31 32 33 34 35 36

37 38 39 40 41 42 43 44 45

46 47 48 49 50 51 52 53 54 55

56 57 58 59 60 61 62 63 64 65 66

67 68 69 70 71 72 73 74 75 76 77 78

79 80 81 82 83 84 85 86 87 88 89 90 91

92 93 94 95 96 97 98 99 100 101 102 103 104 105

->

</pre>