Flatten a list: Difference between revisions

===Recursive working with any type of iterable object===

<lang python>>>> def flatten(itr):

>>> try:

>>> t = sum((flatten(e) for e in itr), list())

>>> except:

>>> t = [itr]

>>> return t

>>> lst = [[1], 2, [[3,4], 5], [[[]]], [[[6]]], 7, 8, []]

>>> flatten(lst)

[1, 2, 3, 4, 5, 6, 7, 8]</lang>