Anonymous user
Five weekends: Difference between revisions
→{{header|Python}}: Add extra credit answer.
(Count rather than show years without 5 weekend months, for extra credit.) |
(→{{header|Python}}: Add extra credit answer.) |
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Line 163:
DAY = timedelta(days=1)
START, STOP = date(1900, 1, 1), date(2101, 1, 1)
WEEKEND = {6, 5, 4} # Sunday is day 6
FMT = '%Y %m(%B)'
def fiveweekendspermonth(start=
'Compute months with five weekends between dates'
Line 189 ⟶ 190:
print(indent +('\n'+indent).join(d.strftime(FMT) for d in dates[:5]))
print(indent +'...')
print(indent +('\n'+indent).join(d.strftime(FMT) for d in dates[-5:]))
print('\nThere are %i years in the range that do not have months with five weekends'
% len(set(range(START.year, STOP.year)) - {d.year for d in dates}))</lang>
'''Sample Output'''
Line 203 ⟶ 207:
2099 05(May)
2100 01(January)
2100 10(October)
There are 29 years in the range that do not have months with five weekends</pre>
=={{header|Ruby}}==
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