Anonymous user
Five weekends: Difference between revisions
Added extra credit requirement and added it to Java. Also scrolling the output.
(Added suggestions for how to do the task) |
(Added extra credit requirement and added it to Java. Also scrolling the output.) |
||
Line 4:
'''The task'''
# Write a program to show all months that have this same characteristic of five full weekends from the year 1900 through 2100 (Gregorian calendar).
# Show the ''number'' of months with this property (there should be 201).
# Show at least the first and last five dates, in order.
Line 11:
*Find all of the 31-day months that begin on Friday.
'''Extra credit'''
Show all of the years which do not have at least one five-weekend month (there should be 29).
=={{header|D}}==
<lang d>import std.stdio ;
Line 69 ⟶ 71:
import java.util.GregorianCalendar;
public class FiveFSS {
private static boolean[] years = new boolean[201];
//dreizig tage habt september...
private static int[] month31 = {Calendar.JANUARY, Calendar.MARCH, Calendar.MAY,
Line 77 ⟶ 80:
StringBuilder months = new StringBuilder();
int numMonths = 0;
for (int year = 1900; year <= 2100; year++) {
for (int month : month31) {
Calendar date = new GregorianCalendar(year, month, 1);
if (date.get(Calendar.DAY_OF_WEEK) == Calendar.FRIDAY) {
years[year - 1900] = true;
numMonths++;
//months are 0-indexed in Calendar
months.append((date.get(Calendar.MONTH) + 1) + "-" + year +
}
}
}
System.out.println("There are "
System.out.println(months);
System.out.println("Years with no five-weekend months:");
for (int year = 1900; year <= 2100; year++) {
if(!years[year - 1900]){
System.out.println(year);
}
}
}
}</lang>
Output (middle results cut out):
<pre style="height:30ex;overflow:scroll"> There are 201 with five weekends from 1900 through 2100:
3-1901
8-1902
Line 115 ⟶ 125:
5-2099
1-2100
10-2100
Years with no five-weekend months:
1900
1906
1917
1923
1928
1934
1945
1951
1956
1962
1973
1979
1984
1990
2001
2007
2012
2018
2029
2035
2040
2046
2057
2063
2068
2074
2085
2091
2096</pre>
=={{header|Python}}==
| |||