First class environments: Difference between revisions
→{{header|Perl 6}}: Added an entry for Perl 6
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Thundergnat (talk | contribs) (→{{header|Perl 6}}: Added an entry for Perl 6) |
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0 1 7 2 5 8 16 3 19 6 14 9</pre>
=={{header|Perl 6}}==
Fairly straightforward. Set up an array of hashes containing the current values and iteration counts then pass each hash in turn with a code reference to a routine to calculate the next iteration.
<lang perl6>my $calculator = sub ($n is rw) {
return ($n == 1) ?? 1 !! $n %% 2 ?? $n div 2 !! $n * 3 + 1
};
sub next (%this is rw, &get_next) {
return %this if %this.<value> == 1;
%this.<value>.=&get_next;
%this.<count>++;
return %this;
};
my @hailstones = map { $_ = %(value => $_, count => 0) }, 1 .. 12;
while not all( map { $_.<value> }, @hailstones ) == 1 {
say [~] map { $_.<value>.fmt("%4s") }, @hailstones;
@hailstones[$_].=&next($calculator) for ^@hailstones;
}
say 'Counts';
say [~] map { $_.<count>.fmt("%4s") }, @hailstones;</lang>
{{out}}
<pre> 1 2 3 4 5 6 7 8 9 10 11 12
1 1 10 2 16 3 22 4 28 5 34 6
1 1 5 1 8 10 11 2 14 16 17 3
1 1 16 1 4 5 34 1 7 8 52 10
1 1 8 1 2 16 17 1 22 4 26 5
1 1 4 1 1 8 52 1 11 2 13 16
1 1 2 1 1 4 26 1 34 1 40 8
1 1 1 1 1 2 13 1 17 1 20 4
1 1 1 1 1 1 40 1 52 1 10 2
1 1 1 1 1 1 20 1 26 1 5 1
1 1 1 1 1 1 10 1 13 1 16 1
1 1 1 1 1 1 5 1 40 1 8 1
1 1 1 1 1 1 16 1 20 1 4 1
1 1 1 1 1 1 8 1 10 1 2 1
1 1 1 1 1 1 4 1 5 1 1 1
1 1 1 1 1 1 2 1 16 1 1 1
1 1 1 1 1 1 1 1 8 1 1 1
1 1 1 1 1 1 1 1 4 1 1 1
1 1 1 1 1 1 1 1 2 1 1 1
Counts
0 1 7 2 5 8 16 3 19 6 14 9
</pre>
=={{header|Python}}==
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