Find the missing permutation: Difference between revisions
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x = char(a) + char(b) + char(c)+ char(d) |
x = char(a) + char(b) + char(c)+ char(d) |
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if a!=b and a!=c and a!=d and b!=c and b!=d and c!=d |
if a!=b and a!=c and a!=d and b!=c and b!=d and c!=d |
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if substr(list,x) = 0 see x + " missing" + nl ok ok |
if substr(list,x) = 0 see x + " missing" + nl ok ok |
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next |
next |
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next |
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