Find limit of recursion: Difference between revisions

Content added Content deleted
(jq)
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if (. % 1000000 == 0) then . else empty end, ((.+1)| zero_arity);
if (. % 1000000 == 0) then . else empty end, ((.+1)| zero_arity);


with_arity(0)</lang>
1|zero_arity</lang>
'''Arity-1 Function'''
'''Arity-1 Function'''
<lang jq>def with_arity(n):
<lang jq>def with_arity(n):