Anonymous user
File size distribution: Difference between revisions
added zkl
(mark as draft) |
(added zkl) |
||
Line 2:
Beginning from the current directory, or optionally from a directory specified as a command-line argument, determine how many files there are of various sizes in a directory hierarchy. My suggestion is to sort by logarithmn of file size, since a few bytes here or there, or even a factor of two or three, may not be that significant. Don't forget that empty files may exist, to serve as a marker. Is your file system predominantly devoted to a large number of smaller files, or a smaller number of huge files?
=={{header|zkl}}==
<lang zkl>pipe:=Thread.Pipe();
// hoover all files in tree, don't return directories
fcn(pipe,dir){ File.globular(dir,"*",True,8,pipe); }
.launch(pipe,vm.arglist[0]); // thread
dist,N,SZ,maxd:=List.createLong(50,0),0,0,0;
foreach fnm in (pipe){
sz,szd:=File.len(fnm), sz.numDigits;
dist[szd]+=1;
N+=1; SZ+=sz; maxd=maxd.max(szd);
}
println("Found %d files, %,d bytes, %,d mean.".fmt(N,SZ,SZ/N));
scale:=50.0/(0.0).max(dist);
println("%15s %s (* = %.2f)".fmt("File size","Number of files",1.0/scale));
foreach sz,cnt in ([0..].zip(dist[0,maxd])){
z:="%,d".fmt((10).pow(sz)).replace("1","n").replace("0","n");
println("%15s : %s".fmt(z,"*"*(scale*cnt).round().toInt()));
}</lang>
{{out}}
<pre>
$ zkl flSzDist.zkl ..
Found 1832 files, 108,667,806 bytes, 59,316 mean.
File size Number of files (* = 13.44)
n : *
nn : ***
nnn : ********
n,nnn : **********************************
nn,nnn : **************************************************
nnn,nnn : ********************************
n,nnn,nnn : *******
$ zkl flSzDist.zkl /media/Tunes/
Found 4320 files, 67,627,849,052 bytes, 15,654,594 mean.
File size Number of files (* = 69.84)
n :
nn :
nnn :
n,nnn : *
nn,nnn :
nnn,nnn :
n,nnn,nnn : *
nn,nnn,nnn : **************************************************
nnn,nnn,nnn : ********
n,nnn,nnn,nnn : *
</pre>
| |||