Fibonacci word: Difference between revisions

m
(Added 11l)
Line 40:
L(n) 1..37
L fwords.len < n
fwords [+]= (reversed(fwords[(len)-2 ..][(0..).step(-1)]).join(‘’)
V v = fwords[n - 1]
print(‘#3.0 #10.0 #2.7 #.’.format(n, v.len, entropy(v), I v.len < 56 {v} E ‘<too long>’))</lang>
1,480

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