Fermat numbers: Difference between revisions
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=={{header|langur}}==
{{trans|Python}}
<syntaxhighlight lang="langur">val .fermat =
val .factors =
for[.f=[]] .i, .s = 2, trunc .x ^/ 2; .i < .s; .i += 1 {
if .x div .i {
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writeln $"F\(.i + 16x2080:cp) factors: ", .fac
}
}
{{out}}
<pre>first 10 Fermat numbers
F₀ = 3
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