Fast Fourier transform: Difference between revisions

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N≤1:⍵
(1|2⍟N)≠0:'Argument must be a power of 2 in length'
even←ffteven←∇(N⍴0 1)/⍵
odd←fftodd←∇(N⍴1 0)/⍵
k←N÷2
T←even×*(0J¯2×(○1)×(¯1+⍳k)÷N)