Evaluate binomial coefficients: Difference between revisions
→{{header|Perl 6}}: div can actually be used here to solve the type issue
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=={{header|Perl 6}}==
<lang perl6>sub infix:<choose> { [*] ($^n ... 0)
say 5 choose 3;</lang>
{{out}}
<pre>10</pre>
=={{header|PL/I}}==
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