Egyptian division: Difference between revisions

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@@ Line 1,807: / Line 1,807: @@
     | until( .i < 0 or .accumulator == $dividend;
         if (.accumulator + .doublings[.i] <= $dividend)
-	then .accumulator += .doublings[.i]
+        then .accumulator += .doublings[.i]
         | .answer += .powersOfTwo[.i]
         else .
-	end
+	    end
-	| .i += -1)
+        | .i += -1)
     | [.answer, $dividend - .accumulator]
     end;