Eban numbers: Difference between revisions
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Line 1:
{{
;Definition:
An '''eban''' number is a number that has no letter <big> '''e''' </big> in it when the number is spelled in
Or more literally, spelled numbers that contain the letter '''e''' are banned.
Line 24:
:::* show a count of all eban numbers up and including '''10,000'''
:::* show a count of all eban numbers up and including '''100,000'''
:::* show a count of all eban numbers up and including
:::* show a count of all eban numbers up and including
:::* show all output here.
Line 32:
:* The MathWorld entry: [http://mathworld.wolfram.com/EbanNumber.html eban numbers].
:* The OEIS entry: [http://oeis.org/A006933 A6933, eban numbers].
:* [[Number names]].
<br><br>
=={{header|11l}}==
{{trans|Nim}}
<syntaxhighlight lang="11l">F iseban(n)
I n == 0
R 0B
V (b, r) = divmod(n, 1'000'000'000)
(V m, r) = divmod(r, 1'000'000)
(V t, r) = divmod(r, 1'000)
m = I m C 30..66 {m % 10} E m
t = I t C 30..66 {t % 10} E t
r = I r C 30..66 {r % 10} E r
R Set([b, m, t, r]) <= Set([0, 2, 4, 6])
print(‘eban numbers up to and including 1000:’)
L(i) 0..100
I iseban(i)
print(i, end' ‘ ’)
print("\n\neban numbers between 1000 and 4000 (inclusive):")
L(i) 1000..4000
I iseban(i)
print(i, end' ‘ ’)
print()
L(maxn) (10'000, 100'000, 1'000'000, 10'000'000)
V count = 0
L(i) 0..maxn
I iseban(i)
count++
print("\nNumber of eban numbers up to and including #8: #4".format(maxn, count))</syntaxhighlight>
{{out}}
<pre>
eban numbers up to and including 1000:
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
eban numbers between 1000 and 4000 (inclusive):
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
Number of eban numbers up to and including 10000: 79
Number of eban numbers up to and including 100000: 399
Number of eban numbers up to and including 1000000: 399
Number of eban numbers up to and including 10000000: 1599
</pre>
=={{header|ALGOL 68}}==
{{Trans|Lua|for the eban number enumerating code}}
{{Trans|Phix|for the eban number counting code}}
<syntaxhighlight lang="algol68">
BEGIN # Eban numbers - translated from the Lua and Phix samples #
MODE INTERVAL = STRUCT( INT start, end, BOOL print );
[]INTERVAL intervals = ( ( 2, 1000, TRUE )
, ( 1000, 4000, TRUE )
, ( 2, 10000, FALSE )
, ( 2, 1000000, FALSE )
, ( 2, 10000000, FALSE )
, ( 2, 100000000, FALSE )
, ( 2, 1000000000, FALSE )
);
FOR intp FROM LWB intervals TO UPB intervals DO
INTERVAL intv = intervals[ intp ];
IF start OF intv = 2 THEN
print( ( "eban numbers up to and including ", whole( end OF intv, 0 ), ":" ) )
ELSE
print( ( "eban numbers between ", whole( start OF intv, 0 )
, " and ", whole( end OF intv, 0 ), " (inclusive)"
)
)
FI;
print( ( newline ) );
IF NOT print OF intv THEN
# calculate the count, as in the Phix sample #
# end OF intv must be a power of 10 #
INT p10 := 0;
INT v := end OF intv;
WHILE v > p10 DO
p10 +:= 1;
v OVERAB 10
OD;
INT n = p10 - ( p10 OVER 3 );
INT p5 = n OVER 2;
INT p4 = ( n + 1 ) OVER 2;
print( ( "count = ", whole( ( ( 5 ^ p5 ) * ( 4 ^ p4 ) ) - 1, 0 ), newline ) )
ELSE
# enumerate the eban numbers, as in the Lua and other samples #
INT count := 0;
FOR i FROM start OF intv BY 2 TO end OF intv DO
INT b = i OVER 1 000 000 000;
INT r := i MOD 1 000 000 000;
INT m := r OVER 1 000 000;
r := i MOD 1 000 000;
INT t := r OVER 1 000;
r := r MOD 1 000;
IF m >= 30 AND m <= 66 THEN m MODAB 10 FI;
IF t >= 30 AND t <= 66 THEN t MODAB 10 FI;
IF r >= 30 AND r <= 66 THEN r MODAB 10 FI;
IF b = 0 OR b = 2 OR b = 4 OR b = 6 THEN
IF m = 0 OR m = 2 OR m = 4 OR m = 6 THEN
IF t = 0 OR t = 2 OR t = 4 OR t = 6 THEN
IF r = 0 OR r = 2 OR r = 4 OR r = 6 THEN
print( ( whole( i, 0 ), " " ) );
count +:= 1
FI
FI
FI
FI
OD;
print( ( newline, "count = ", whole( count, 0 ), newline ) )
FI;
print( ( newline ) )
OD
END
</syntaxhighlight>
{{out}}
<pre>
eban numbers up to and including 1000:
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers between 1000 and 4000 (inclusive)
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to and including 10000:
count = 79
eban numbers up to and including 1000000:
count = 399
eban numbers up to and including 10000000:
count = 1599
eban numbers up to and including 100000000:
count = 7999
eban numbers up to and including 1000000000:
count = 7999
</pre>
=={{header|AppleScript}}==
<syntaxhighlight lang="applescript">(*
Quickly generate all the (positive) eban numbers up to and including the
specified end number, then lose those before the start number.
0 is taken as "zero" rather than as "nought" or "nil".
WARNING: The getEbans() handler returns a potentially very long list of numbers.
Don't let such a list get assigned to a persistent variable or be the end result displayed in an editor!
*)
on getEbans(startNumber, endNumber)
script o
property output : {}
property listCollector : missing value
property temp : missing value
end script
if (startNumber > endNumber) then set {startNumber, endNumber} to {endNumber, startNumber}
-- The range is limited to between 0 and 10^15 to keep within AppleScript's current number precision.
-- Even so, some of the numbers may not /look/ right when displayed in a editor.
set limit to 10 ^ 15 - 1
if (endNumber > limit) then set endNumber to limit
if (startNumber > limit) then set startNumber to limit
-- Initialise the output list with 0 and the sub-1000 ebans, stopping if the end number's reached.
-- The 0's needed for rest of the process, but is removed at the end.
repeat with tens in {0, 30, 40, 50, 60}
repeat with units in {0, 2, 4, 6}
set thisEban to tens + units
if (thisEban ≤ endNumber) then set end of o's output to thisEban
end repeat
end repeat
-- Repeatedly sweep the output list, adding new ebans formed from the addition of those found previously
-- to a suitable power of 1000 times each one. Stop when the end number's reached or exceeded.
-- The output list may become very long and appending items to it individually take forever, so results are
-- collected in short, 1000-item lists, which are concatenated to the output at the end of each sweep.
set sweepLength to (count o's output)
set multiplier to 1000
repeat while (thisEban < endNumber) -- Per sweep.
set o's temp to {}
set o's listCollector to {o's temp}
repeat with i from 2 to sweepLength -- Per eban found already. (Not the 0.)
set baseAmount to (item i of o's output) * multiplier
repeat with j from 1 to sweepLength by 1000 -- Per 1000-item list.
set z to j + 999
if (z > sweepLength) then set z to sweepLength
repeat with k from j to z -- Per new eban.
set thisEban to baseAmount + (item k of o's output)
if (thisEban ≤ endNumber) then set end of o's temp to thisEban
if (thisEban ≥ endNumber) then exit repeat
end repeat
if (thisEban ≥ endNumber) then exit repeat
set o's temp to {}
set end of o's listCollector to o's temp
end repeat
if (thisEban ≥ endNumber) then exit repeat
end repeat
-- Concatentate this sweep's new lists together
set listCount to (count o's listCollector)
repeat until (listCount is 1)
set o's temp to {}
repeat with i from 2 to listCount by 2
set end of o's temp to (item (i - 1) of o's listCollector) & (item i of o's listCollector)
end repeat
if (listCount mod 2 is 1) then set item -1 of o's temp to (end of o's temp) & (end of o's listCollector)
set o's listCollector to o's temp
set o's temp to {}
set listCount to (count o's listCollector)
end repeat
-- Concatenate the result to the output list and prepare to go round again.
set o's output to o's output & (beginning of o's listCollector)
set sweepLength to sweepLength * sweepLength
set multiplier to multiplier * multiplier
end repeat
-- Lose the initial 0 and any ebans before the specified start number.
set resultCount to (count o's output)
if (resultCount is 1) then
set o's output to {}
else
repeat with i from 2 to resultCount
if (item i of o's output ≥ startNumber) then exit repeat
end repeat
set o's output to items i thru resultCount of o's output
end if
if (endNumber = limit) then set end of o's output to "(Limit of AppleScript's number precision.)"
return o's output
end getEbans
-- Task code:
on runTask()
set output to {}
set astid to AppleScript's text item delimiters
set AppleScript's text item delimiters to ", "
set ebans to getEbans(0, 1000)
set end of output to ((count ebans) as text) & " eban numbers between 0 and 1,000:" & (linefeed & " " & ebans)
set ebans to getEbans(1000, 4000)
set end of output to ((count ebans) as text) & " between 1,000 and 4,000:" & (linefeed & " " & ebans)
set end of output to ((count getEbans(0, 10000)) as text) & " up to and including 10,000"
set end of output to ((count getEbans(0, 100000)) as text) & " up to and including 100,000"
set end of output to ((count getEbans(0, 1000000)) as text) & " up to and including 1,000,000"
set end of output to ((count getEbans(0, 10000000)) as text) & " up to and including 10,000,000"
set ebans to getEbans(6.606606602E+10, 1.0E+12)
set end of output to ((count ebans) as text) & " between 66,066,066,020 and 1,000,000,000,000:" & (linefeed & " " & ebans)
set AppleScript's text item delimiters to linefeed
set output to output as text
set AppleScript's text item delimiters to astid
return output
end runTask
runTask()</syntaxhighlight>
{{output}}
<syntaxhighlight lang="applescript">"19 eban numbers between 0 and 1,000:
2, 4, 6, 30, 32, 34, 36, 40, 42, 44, 46, 50, 52, 54, 56, 60, 62, 64, 66
21 between 1,000 and 4,000:
2000, 2002, 2004, 2006, 2030, 2032, 2034, 2036, 2040, 2042, 2044, 2046, 2050, 2052, 2054, 2056, 2060, 2062, 2064, 2066, 4000
79 up to and including 10,000
399 up to and including 100,000
399 up to and including 1,000,000
1599 up to and including 10,000,000
16 between 66,066,066,020 and 1,000,000,000,000:
6.606606603E+10, 6.6066066032E+10, 6.6066066034E+10, 6.6066066036E+10, 6.606606604E+10, 6.6066066042E+10, 6.6066066044E+10, 6.6066066046E+10, 6.606606605E+10, 6.6066066052E+10, 6.6066066054E+10, 6.6066066056E+10, 6.606606606E+10, 6.6066066062E+10, 6.6066066064E+10, 6.6066066066E+10"</syntaxhighlight>
=={{header|AutoHotkey}}==
<syntaxhighlight lang="autohotkey">eban_numbers(min, max, show:=0){
counter := 0, output := ""
i := min
while ((i+=2) <= max)
{
b := floor(i / 1000000000)
r := Mod(i, 1000000000)
m := floor(r / 1000000)
r := Mod(i, 1000000)
t := floor(r / 1000)
r := Mod(r, 1000)
if (m >= 30 && m <= 66)
m := Mod(m, 10)
if (t >= 30 && t <= 66)
t := Mod(t, 10)
if (r >= 30 && r <= 66)
r := Mod(r, 10)
if (b = 0 || b = 2 || b = 4 || b = 6)
&& (m = 0 || m = 2 || m = 4 || m = 6)
&& (t = 0 || t = 2 || t = 4 || t = 6)
&& (r = 0 || r = 2 || r = 4 || r = 6)
counter++, (show ? output .= i " " : "")
}
return min "-" max " : " output " Count = " counter
}</syntaxhighlight>
Examples:<syntaxhighlight lang="autohotkey">MsgBox, 262144, , % eban_numbers(0, 1000, 1)
MsgBox, 262144, , % eban_numbers(1000, 4000, 1)
MsgBox, 262144, , % eban_numbers(0, 10000)
MsgBox, 262144, , % eban_numbers(0, 100000)
MsgBox, 262144, , % eban_numbers(0, 1000000)
MsgBox, 262144, , % eban_numbers(0, 100000000)</syntaxhighlight>
{{out}}
<pre>2-1000 : 2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66 Count = 19
1000-4000 : 2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000 Count = 21
2-10000 : Count = 79
2-100000 : Count = 399
2-1000000 : Count = 399
2-10000000 : Count = 1599
2-100000000 : Count = 7999</pre>
=={{header|AWK}}==
<syntaxhighlight lang="awk">
# syntax: GAWK -f EBAN_NUMBERS.AWK
# converted from FreeBASIC
BEGIN {
main(2,1000,1)
main(1000,4000,1)
main(2,10000,0)
main(2,100000,0)
main(2,1000000,0)
main(2,10000000,0)
main(2,100000000,0)
exit(0)
}
function main(start,stop,printable, b,count,i,m,r,t) {
printf("%d-%d:",start,stop)
for (i=start; i<=stop; i+=2) {
b = int(i / 1000000000)
r = i % 1000000000
m = int(r / 1000000)
r = i % 1000000
t = int(r / 1000)
r = r % 1000
if (m >= 30 && m <= 66) { m %= 10 }
if (t >= 30 && t <= 66) { t %= 10 }
if (r >= 30 && r <= 66) { r %= 10 }
if (x(b) && x(m) && x(t) && x(r)) {
count++
if (printable) {
printf(" %d",i)
}
}
}
printf(" (count=%d)\n",count)
}
function x(n) {
return(n == 0 || n == 2 || n == 4 || n == 6)
}
</syntaxhighlight>
{{out}}
<pre>
2-1000: 2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66 (count=19)
1000-4000: 2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000 (count=21)
2-10000: (count=79)
2-100000: (count=399)
2-1000000: (count=399)
2-10000000: (count=1599)
2-100000000: (count=7999)
</pre>
=={{header|C}}==
{{trans|D}}
<syntaxhighlight lang="c">#include "stdio.h"
#include "stdbool.h"
#define ARRAY_LEN(a,T) (sizeof(a) / sizeof(T))
struct Interval {
int start, end;
bool print;
};
int main() {
struct Interval intervals[] = {
{2, 1000, true},
{1000, 4000, true},
{2, 10000, false},
{2, 100000, false},
{2, 1000000, false},
{2, 10000000, false},
{2, 100000000, false},
{2, 1000000000, false},
};
int idx;
for (idx = 0; idx < ARRAY_LEN(intervals, struct Interval); ++idx) {
struct Interval intv = intervals[idx];
int count = 0, i;
if (intv.start == 2) {
printf("eban numbers up to and including %d:\n", intv.end);
} else {
printf("eban numbers between %d and %d (inclusive:)", intv.start, intv.end);
}
for (i = intv.start; i <= intv.end; i += 2) {
int b = i / 1000000000;
int r = i % 1000000000;
int m = r / 1000000;
int t;
r = i % 1000000;
t = r / 1000;
r %= 1000;
if (m >= 30 && m <= 66) m %= 10;
if (t >= 30 && t <= 66) t %= 10;
if (r >= 30 && r <= 66) r %= 10;
if (b == 0 || b == 2 || b == 4 || b == 6) {
if (m == 0 || m == 2 || m == 4 || m == 6) {
if (t == 0 || t == 2 || t == 4 || t == 6) {
if (r == 0 || r == 2 || r == 4 || r == 6) {
if (intv.print) printf("%d ", i);
count++;
}
}
}
}
}
if (intv.print) {
printf("\n");
}
printf("count = %d\n\n", count);
}
return 0;
}</syntaxhighlight>
{{out}}
<pre>eban numbers up to and including 1000:
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers between 1000 and 4000 (inclusive:)2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to and including 10000:
count = 79
eban numbers up to and including 100000:
count = 399
eban numbers up to and including 1000000:
count = 399
eban numbers up to and including 10000000:
count = 1599
eban numbers up to and including 100000000:
count = 7999
eban numbers up to and including 1000000000:
count = 7999</pre>
=={{header|C sharp|C#}}==
{{trans|D}}
<syntaxhighlight lang="csharp">using System;
namespace EbanNumbers {
struct Interval {
public int start, end;
public bool print;
public Interval(int start, int end, bool print) {
this.start = start;
this.end = end;
this.print = print;
}
}
class Program {
static void Main() {
Interval[] intervals = {
new Interval(2, 1_000, true),
new Interval(1_000, 4_000, true),
new Interval(2, 10_000, false),
new Interval(2, 100_000, false),
new Interval(2, 1_000_000, false),
new Interval(2, 10_000_000, false),
new Interval(2, 100_000_000, false),
new Interval(2, 1_000_000_000, false),
};
foreach (var intv in intervals) {
if (intv.start == 2) {
Console.WriteLine("eban numbers up to and including {0}:", intv.end);
} else {
Console.WriteLine("eban numbers between {0} and {1} (inclusive):", intv.start, intv.end);
}
int count = 0;
for (int i = intv.start; i <= intv.end; i += 2) {
int b = i / 1_000_000_000;
int r = i % 1_000_000_000;
int m = r / 1_000_000;
r = i % 1_000_000;
int t = r / 1_000;
r %= 1_000;
if (m >= 30 && m <= 66) m %= 10;
if (t >= 30 && t <= 66) t %= 10;
if (r >= 30 && r <= 66) r %= 10;
if (b == 0 || b == 2 || b == 4 || b == 6) {
if (m == 0 || m == 2 || m == 4 || m == 6) {
if (t == 0 || t == 2 || t == 4 || t == 6) {
if (r == 0 || r == 2 || r == 4 || r == 6) {
if (intv.print) Console.Write("{0} ", i);
count++;
}
}
}
}
}
if (intv.print) {
Console.WriteLine();
}
Console.WriteLine("count = {0}\n", count);
}
}
}
}</syntaxhighlight>
{{out}}
<pre>eban numbers up to and including 1000:
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers between 1000 and 4000 (inclusive):
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to and including 10000:
count = 79
eban numbers up to and including 100000:
count = 399
eban numbers up to and including 1000000:
count = 399
eban numbers up to and including 10000000:
count = 1599
eban numbers up to and including 100000000:
count = 7999
eban numbers up to and including 1000000000:
count = 7999</pre>
=={{header|C++}}==
{{trans|D}}
<syntaxhighlight lang="cpp">#include <iostream>
struct Interval {
int start, end;
bool print;
};
int main() {
Interval intervals[] = {
{2, 1000, true},
{1000, 4000, true},
{2, 10000, false},
{2, 100000, false},
{2, 1000000, false},
{2, 10000000, false},
{2, 100000000, false},
{2, 1000000000, false},
};
for (auto intv : intervals) {
if (intv.start == 2) {
std::cout << "eban numbers up to and including " << intv.end << ":\n";
} else {
std::cout << "eban numbers bwteen " << intv.start << " and " << intv.end << " (inclusive):\n";
}
int count = 0;
for (int i = intv.start; i <= intv.end; i += 2) {
int b = i / 1000000000;
int r = i % 1000000000;
int m = r / 1000000;
r = i % 1000000;
int t = r / 1000;
r %= 1000;
if (m >= 30 && m <= 66) m %= 10;
if (t >= 30 && t <= 66) t %= 10;
if (r >= 30 && r <= 66) r %= 10;
if (b == 0 || b == 2 || b == 4 || b == 6) {
if (m == 0 || m == 2 || m == 4 || m == 6) {
if (t == 0 || t == 2 || t == 4 || t == 6) {
if (r == 0 || r == 2 || r == 4 || r == 6) {
if (intv.print) std::cout << i << ' ';
count++;
}
}
}
}
}
if (intv.print) {
std::cout << '\n';
}
std::cout << "count = " << count << "\n\n";
}
return 0;
}</syntaxhighlight>
{{out}}
<pre>eban numbers up to and including 1000:
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers bwteen 1000 and 4000 (inclusive):
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to and including 10000:
count = 79
eban numbers up to and including 100000:
count = 399
eban numbers up to and including 1000000:
count = 399
eban numbers up to and including 10000000:
count = 1599
eban numbers up to and including 100000000:
count = 7999
eban numbers up to and including 1000000000:
count = 7999</pre>
=={{header|CLU}}==
<syntaxhighlight lang="clu">eban = cluster is numbers
rep = null
% Next valid E-ban number in the range [0..999]
next = proc (n: int) returns (int) signals (no_more)
if n>=66 then signal no_more end
if n<0 then return(0) end
% advance low digit (two four six)
if (n//10=0) then n := (n/10)*10 + 2
elseif (n//10=2) then n := (n/10)*10 + 4
elseif (n//10=4) then n := (n/10)*10 + 6
elseif (n//10=6) then n := (n/10)*10 + 10
end
% this might put us into tEn, twEnty which are invalid
if (n//100/10 = 1) then n := n + 20 % ten + 20 = 30
elseif (n//100/10 = 2) then n := n + 10 % twEnty + 10 = 30
end
return(n)
end next
% Yield all valid E_ban numbers
% (sextillion and upwards aren't handled)
numbers = iter () yields (int)
parts: array[int] := array[int]$[0: 2]
while true do
num: int := 0
for m: int in array[int]$indexes(parts) do
num := num + parts[m] * 1000 ** m
end
yield(num)
for m: int in array[int]$indexes(parts) do
begin
parts[m] := next(parts[m])
break
end except when no_more:
parts[m] := 0
end
end
if array[int]$top(parts) = 0 then
array[int]$addh(parts,2)
end
end
end numbers
end eban
start_up = proc ()
maxmagn = 1000000000000
po: stream := stream$primary_output()
count: int := 0
upto_1k: int := 0
between_1k_4k: int := 0
disp_1k: bool := false
disp_4k: bool := false
nextmagn: int := 10000
for i: int in eban$numbers() do
while i>nextmagn do
stream$putl(po, int$unparse(count)
|| " eban numbers <= "
|| int$unparse(nextmagn))
nextmagn := nextmagn * 10
end
count := count + 1
if i<1000 then upto_1k := upto_1k + 1
elseif i<=4000 then between_1k_4k := between_1k_4k + 1
end
if i>1000 & ~disp_1k then
disp_1k := true
stream$putl(po, "\n" || int$unparse(upto_1k)
|| " eban numbers <= 1000\n")
end
if i<=4000 then stream$putright(po, int$unparse(i), 5) end
if i>4000 & ~disp_4k then
disp_4k := true
stream$putl(po, "\n" || int$unparse(between_1k_4k)
|| " eban numbers 1000 <= x <= 4000\n")
end
if nextmagn>maxmagn then break end
end
end start_up </syntaxhighlight>
{{out}}
<pre> 2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
19 eban numbers <= 1000
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
21 eban numbers 1000 <= x <= 4000
79 eban numbers <= 10000
399 eban numbers <= 100000
399 eban numbers <= 1000000
1599 eban numbers <= 10000000
7999 eban numbers <= 100000000
7999 eban numbers <= 1000000000
31999 eban numbers <= 10000000000
159999 eban numbers <= 100000000000
159999 eban numbers <= 1000000000000</pre>
=={{header|D}}==
{{trans|Kotlin}}
<syntaxhighlight lang="d">import std.stdio;
struct Interval {
int start, end;
bool print;
}
void main() {
Interval[] intervals = [
{2, 1_000, true},
{1_000, 4_000, true},
{2, 10_000, false},
{2, 100_000, false},
{2, 1_000_000, false},
{2, 10_000_000, false},
{2, 100_000_000, false},
{2, 1_000_000_000, false},
];
foreach (intv; intervals) {
if (intv.start == 2) {
writeln("eban numbers up to an including ", intv.end, ':');
} else {
writeln("eban numbers between ", intv.start ," and ", intv.end, " (inclusive):");
}
int count;
for (int i = intv.start; i <= intv.end; i = i + 2) {
int b = i / 1_000_000_000;
int r = i % 1_000_000_000;
int m = r / 1_000_000;
r = i % 1_000_000;
int t = r / 1_000;
r %= 1_000;
if (m >= 30 && m <= 66) m %= 10;
if (t >= 30 && t <= 66) t %= 10;
if (r >= 30 && r <= 66) r %= 10;
if (b == 0 || b == 2 || b == 4 || b == 6) {
if (m == 0 || m == 2 || m == 4 || m == 6) {
if (t == 0 || t == 2 || t == 4 || t == 6) {
if (r == 0 || r == 2 || r == 4 || r == 6) {
if (intv.print) write(i, ' ');
count++;
}
}
}
}
}
if (intv.print) {
writeln();
}
writeln("count = ", count);
writeln;
}
}</syntaxhighlight>
{{out}}
<pre>eban numbers up to an including 1000:
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers between 1000 and 4000 (inclusive):
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to an including 10000:
count = 79
eban numbers up to an including 100000:
count = 399
eban numbers up to an including 1000000:
count = 399
eban numbers up to an including 10000000:
count = 1599
eban numbers up to an including 100000000:
count = 7999
eban numbers up to an including 1000000000:
count = 7999</pre>
=={{header|EasyLang}}==
{{trans|AWK}}
<syntaxhighlight lang=easylang>
func x n .
if n = 0 or n = 2 or n = 4 or n = 6
return 1
.
.
proc go start stop printable . .
write start & " - " & stop & ":"
for i = start step 2 to stop
b = i div 1000000000
r = i mod 1000000000
m = r div 1000000
r = i mod 1000000
t = r div 1000
r = r mod 1000
if m >= 30 and m <= 66
m = m mod 10
.
if t >= 30 and t <= 66
t = t mod 10
.
if r >= 30 and r <= 66
r = r mod 10
.
if x b = 1 and x m = 1 and x t = 1 and x r = 1
count += 1
if printable = 1
write " " & i
.
.
.
print " (count=" & count & ")"
.
go 2 1000 1
go 1000 4000 1
go 2 10000 0
go 2 100000 0
go 2 1000000 0
go 2 10000000 0
go 2 100000000 0
</syntaxhighlight>
=={{header|Factor}}==
{{trans|Julia}}
<syntaxhighlight lang="factor">USING: arrays formatting fry io kernel math math.functions
math.order math.ranges prettyprint sequences ;
: eban? ( n -- ? )
1000000000 /mod 1000000 /mod 1000 /mod
[ dup 30 66 between? [ 10 mod ] when ] tri@ 4array
[ { 0 2 4 6 } member? ] all? ;
: .eban ( m n -- ) "eban numbers in [%d, %d]: " printf ;
: eban ( m n q -- o ) '[ 2dup .eban [a,b] [ eban? ] @ ] call ; inline
: .eban-range ( m n -- ) [ filter ] eban "%[%d, %]\n" printf ;
: .eban-count ( m n -- ) "count of " write [ count ] eban . ;
1 1000 1000 4000 [ .eban-range ] 2bi@
4 9 [a,b] [ [ 1 10 ] dip ^ .eban-count ] each</syntaxhighlight>
{{out}}
<pre>
eban numbers in [1, 1000]: { 2, 4, 6, 30, 32, 34, 36, 40, 42, 44, 46, 50, 52, 54, 56, 60, 62, 64, 66 }
eban numbers in [1000, 4000]: { 2000, 2002, 2004, 2006, 2030, 2032, 2034, 2036, 2040, 2042, 2044, 2046, 2050, 2052, 2054, 2056, 2060, 2062, 2064, 2066, 4000 }
count of eban numbers in [1, 10000]: 79
count of eban numbers in [1, 100000]: 399
count of eban numbers in [1, 1000000]: 399
count of eban numbers in [1, 10000000]: 1599
count of eban numbers in [1, 100000000]: 7999
count of eban numbers in [1, 1000000000]: 7999
</pre>
=={{header|FreeBASIC}}==
<syntaxhighlight lang="freebasic">
' Eban_numbers
' Un número eban es un número que no tiene la letra e cuando el número está escrito en inglés.
' O más literalmente, los números escritos que contienen la letra e están prohibidos.
'
' Usaremos la versión americana de los números de ortografía (a diferencia de los británicos).
' 2000000000 son dos billones, no dos millardos (mil millones).
'
Data 2, 1000, 1
Data 1000, 4000, 1
Data 2, 10000, 0
Data 2, 100000, 0
Data 2, 1000000, 0
Data 2, 10000000, 0
Data 2, 100000000, 0
Data 0, 0, 0
Dim As Double tiempo = Timer
Dim As Integer start, ended, printable, count
Dim As Long i, b, r, m, t
Do
Read start, ended, printable
If start = 0 Then Exit Do
If start = 2 Then
Print "eban numbers up to and including"; ended; ":"
Else
Print "eban numbers between "; start; " and "; ended; " (inclusive):"
End If
count = 0
For i = start To ended Step 2
b = Int(i / 1000000000)
r = (i Mod 1000000000)
m = Int(r / 1000000)
r = (i Mod 1000000)
t = Int(r / 1000)
r = (r Mod 1000)
If m >= 30 And m <= 66 Then m = (m Mod 10)
If t >= 30 And t <= 66 Then t = (t Mod 10)
If r >= 30 And r <= 66 Then r = (r Mod 10)
If b = 0 Or b = 2 Or b = 4 Or b = 6 Then
If m = 0 Or m = 2 Or m = 4 Or m = 6 Then
If t = 0 Or t = 2 Or t = 4 Or t = 6 Then
If r = 0 Or r = 2 Or r = 4 Or r = 6 Then
If printable Then Print i;
count += 1
End If
End If
End If
End If
Next i
If printable Then Print
Print "count = "; count & Chr(10)
Loop
tiempo = Timer - tiempo
Print "Run time: " & (tiempo) & " seconds."
End
</syntaxhighlight>
{{out}}
<pre>
eban numbers up to and including 100:
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers between 1000 and 4000 (inclusive):
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to and including 10000:
count = 79
eban numbers up to and including 100000:
count = 399
eban numbers up to and including 1000000:
count = 399
eban numbers up to and including 10000000:
count = 1599
eban numbers up to and including 100000000:
count = 7999
Run time: 1.848286400010693 seconds.
</pre>
=={{header|Fōrmulæ}}==
{{FormulaeEntry|page=https://formulae.org/?script=examples/Eban_numbers}}
=={{header|Go}}==
<
import "fmt"
Line 96 ⟶ 1,094:
fmt.Println("count =", count, "\n")
}
}</
{{out}}
Line 127 ⟶ 1,125:
</pre>
=={{header|
{{trans|Java}}
<syntaxhighlight lang="groovy">class Main {
private static class Range {
int start
int end
boolean print
Range(int s, int e, boolean p) {
start = s
end = e
print = p
}
}
static void main(String[] args) {
List<Range> rgs = Arrays.asList(
new Range(2, 1000, true),
new Range(1000, 4000, true),
new Range(2, 10_000, false),
new Range(2, 100_000, false),
new Range(2, 1_000_000, false),
new Range(2, 10_000_000, false),
new Range(2, 100_000_000, false),
new Range(2, 1_000_000_000, false)
)
for (Range rg : rgs) {
if (rg.start == 2) {
println("eban numbers up to and including $rg.end")
} else {
println("eban numbers between $rg.start and $rg.end")
}
int count = 0
for (int i = rg.start; i <= rg.end; ++i) {
int b = (int) (i / 1_000_000_000)
int r = i % 1_000_000_000
int m = (int) (r / 1_000_000)
r = i % 1_000_000
int t = (int) (r / 1_000)
r %= 1_000
if (m >= 30 && m <= 66) m %= 10
if (t >= 30 && t <= 66) t %= 10
if (r >= 30 && r <= 66) r %= 10
if (b == 0 || b == 2 || b == 4 || b == 6) {
if (m == 0 || m == 2 || m == 4 || m == 6) {
if (t == 0 || t == 2 || t == 4 || t == 6) {
if (r == 0 || r == 2 || r == 4 || r == 6) {
if (rg.print) {
print("$i ")
}
count++
}
}
}
}
}
if (rg.print) {
println()
}
println("count = $count")
println()
}
}
}</syntaxhighlight>
{{out}}
<pre>Same as the Java entry</pre>
=={{header|Haskell}}==
{{trans|Julia}}
<syntaxhighlight lang="haskell">{-# LANGUAGE NumericUnderscores #-}
import Data.List (intercalate)
import Text.Printf (printf)
import Data.List.Split (chunksOf)
isEban :: Int -> Bool
isEban n = all (`elem` [0, 2, 4, 6]) z
where
(b, r1) = n `quotRem` (10 ^ 9)
(m, r2) = r1 `quotRem` (10 ^ 6)
(t, r3) = r2 `quotRem` (10 ^ 3)
z = b : map (\x -> if x >= 30 && x <= 66 then x `mod` 10 else x) [m, t, r3]
ebans = map f
where
f x = (thousands x, thousands $ length $ filter isEban [1..x])
thousands:: Int -> String
thousands = reverse . intercalate "," . chunksOf 3 . reverse . show
main :: IO ()
main = do
uncurry (printf "eban numbers up to and including 1000: %2s\n%s\n\n") $ r [1..1000]
uncurry (printf "eban numbers between 1000 and 4000: %2s\n%s\n\n") $ r [1000..4000]
mapM_ (uncurry (printf "eban numbers up and including %13s: %5s\n")) ebanCounts
where
ebanCounts = ebans [ 10_000
, 100_000
, 1_000_000
, 10_000_000
, 100_000_000
, 1_000_000_000 ]
r = ((,) <$> thousands . length <*> show) . filter isEban</syntaxhighlight>
{{out}}
<pre>
eban numbers up to and including 1000: 19
[2,4,6,30,32,34,36,40,42,44,46,50,52,54,56,60,62,64,66]
eban numbers between 1000 and 4000: 21
[2000,2002,2004,2006,2030,2032,2034,2036,2040,2042,2044,2046,2050,2052,2054,2056,2060,2062,2064,2066,4000]
eban numbers up and including 10,000: 79
eban numbers up and including 100,000: 399
eban numbers up and including 1,000,000: 399
eban numbers up and including 10,000,000: 1,599
eban numbers up and including 100,000,000: 7,999
eban numbers up and including 1,000,000,000: 7,999
</pre>
=={{header|J}}==
<syntaxhighlight lang="j">
Filter =: (#~`)(`:6)
itemAmend =: (29&< *. <&67)`(,: 10&|)}
iseban =: [: *./ 0 2 4 6 e.~ [: itemAmend [: |: (4#1000)&#:
(;~ #) iseban Filter >: i. 1000
┌──┬─────────────────────────────────────────────────────┐
│19│2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66│
└──┴─────────────────────────────────────────────────────┘
NB. INPUT are the correct integers, head and tail shown
({. , {:) INPUT =: 1000 + i. 3001
1000 4000
(;~ #) iseban Filter INPUT
┌──┬────────────────────────────────────────────────────────────────────────────────────────────────────────┐
│21│2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000│
└──┴────────────────────────────────────────────────────────────────────────────────────────────────────────┘
(, ([: +/ [: iseban [: >: i.))&> 10000 * 10 ^ i. +:2
10000 79
100000 399
1e6 399
1e7 1599
</syntaxhighlight>
Alternatively we could construct a sequence of eban numbers sufficient to satisfy some limit and then filter out any which exceed our limit:
<syntaxhighlight lang=J>ebanseq=: {{ (#~ y>:])}.,@([+/~1000*])^:(6<.<.1000^.y)~(,0 2 4 6+/~10*0 3 4 5 6) }}
(,:&":~ #) ebanseq 1000
19
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
(,:&":~ #) (#~ 1000<])ebanseq 4000
21
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
# ebanseq 1e4
79
# ebanseq 1e5
399
# ebanseq 1e6
399
# ebanseq 1e7
1599
# ebanseq 1e8
7999
# ebanseq 1e9
7999
# ebanseq 1e10
31999
# ebanseq 1e11
159999
# ebanseq 1e12
159999
# ebanseq 1e13
639999
# ebanseq 1e14
3199999
# ebanseq 1e15
3199999
# ebanseq 1e16
12799999
# ebanseq 1e17
63999999</syntaxhighlight>
=={{header|Java}}==
{{trans|Kotlin}}
<syntaxhighlight lang="java">import java.util.List;
public class Main {
private static class Range {
int start;
int end;
boolean print;
public Range(int s, int e, boolean p) {
start = s;
end = e;
print = p;
}
}
public static void main(String[] args) {
List<Range> rgs = List.of(
new Range(2, 1000, true),
new Range(1000, 4000, true),
new Range(2, 10_000, false),
new Range(2, 100_000, false),
new Range(2, 1_000_000, false),
new Range(2, 10_000_000, false),
new Range(2, 100_000_000, false),
new Range(2, 1_000_000_000, false)
);
for (Range rg : rgs) {
if (rg.start == 2) {
System.out.printf("eban numbers up to and including %d\n", rg.end);
} else {
System.out.printf("eban numbers between %d and %d\n", rg.start, rg.end);
}
int count = 0;
for (int i = rg.start; i <= rg.end; ++i) {
int b = i / 1_000_000_000;
int r = i % 1_000_000_000;
int m = r / 1_000_000;
r = i % 1_000_000;
int t = r / 1_000;
r %= 1_000;
if (m >= 30 && m <= 66) m %= 10;
if (t >= 30 && t <= 66) t %= 10;
if (r >= 30 && r <= 66) r %= 10;
if (b == 0 || b == 2 || b == 4 || b == 6) {
if (m == 0 || m == 2 || m == 4 || m == 6) {
if (t == 0 || t == 2 || t == 4 || t == 6) {
if (r == 0 || r == 2 || r == 4 || r == 6) {
if (rg.print) System.out.printf("%d ", i);
count++;
}
}
}
}
}
if (rg.print) {
System.out.println();
}
System.out.printf("count = %d\n\n", count);
}
}
}</syntaxhighlight>
{{out}}
<pre>eban numbers up to and including 1000
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers between 1000 and 4000
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to and including 10000
count = 79
eban numbers up to and including 100000
count = 399
eban numbers up to and including 1000000
count = 399
eban numbers up to and including 10000000
count = 1599
eban numbers up to and including 100000000
count = 7999
eban numbers up to and including 1000000000
count = 7999</pre>
=={{header|jq}}==
'''Adapted from Julia and Wren'''
{{works with|jq}}
'''Works with gojq, the Go implementation of jq''' (*)
(*) gojq's memory requirements are rather extravagent and may prevent
completion of the task beyond 1E+7; the output shown below was
obtained using the C implementation of jq.
<syntaxhighlight lang="jq"># quotient and remainder
def quotient($a; $b; f; g): f = (($a/$b)|floor) | g = $a % $b;
def tasks:
[2, 1000, true],
[1000, 4000, true],
(1e4, 1e5, 1e6, 1e7, 1e8 | [2, ., false]) ;
def task:
def update(f): if (f >= 30 and f <= 66) then f %= 10 else . end;
tasks as $rg
| if $rg[0] == 2
then "eban numbers up to and including \($rg[1]):"
else "eban numbers between \($rg[0]) and \($rg[1]) (inclusive):"
end,
( foreach (range( $rg[0]; 1 + $rg[1]; 2), null) as $i ( { count: 0 };
.emit = false
| if $i == null then .total = .count
else quotient($i; 1e9; .b; .r)
| quotient(.r; 1e6; .m; .r)
| quotient(.r; 1e3; .t; .r)
| update(.m) | update(.t) | update(.r)
| if all(.b, .m, .t, .r; IN(0, 2, 4, 6))
then .count += 1
| if ($rg[2]) then .emit=$i else . end
else .
end
end;
if .emit then .emit else empty end,
if .total then "count = \(.count)\n" else empty end) );
task</syntaxhighlight>
{{out}}
<pre>
eban numbers up to and including 1000:
2
4
6
30
32
34
36
40
42
44
46
50
52
54
56
60
62
64
66
count = 19
eban numbers between 1000 and 4000 (inclusive):
2000
2002
2004
2006
2030
2032
2034
2036
2040
2042
2044
2046
2050
2052
2054
2056
2060
2062
2064
2066
4000
count = 21
eban numbers up to and including 1E+4:
count = 79
eban numbers up to and including 1E+5:
count = 399
eban numbers up to and including 1E+6:
count = 399
eban numbers up to and including 1E+7:
count = 1599
eban numbers up to and including 1E+8:
count = 7999
</pre>
=={{header|Julia}}==
<syntaxhighlight lang="julia">
function iseban(n::Integer)
b, r = divrem(n, oftype(n, 10 ^ 9))
m, r = divrem(r, oftype(n, 10 ^ 6))
t, r = divrem(r, oftype(n, 10 ^ 3))
m, t, r = (30 <= x <= 66 ? x % 10 : x for x in (m, t, r))
return all(in((0, 2, 4, 6)), (b, m, t, r))
end
println("eban numbers up to and including 1000:")
println(join(filter(iseban, 1:100), ", "))
println("eban numbers between 1000 and 4000 (inclusive):")
println(join(filter(iseban, 1000:4000), ", "))
println("eban numbers up to and including 10000: ", count(iseban, 1:10000))
println("eban numbers up to and including 100000: ", count(iseban, 1:100000))
println("eban numbers up to and including 1000000: ", count(iseban, 1:1000000))
println("eban numbers up to and including 10000000: ", count(iseban, 1:10000000))
println("eban numbers up to and including 100000000: ", count(iseban, 1:100000000))
println("eban numbers up to and including 1000000000: ", count(iseban, 1:1000000000))
</syntaxhighlight>
{{out}}
<pre>eban numbers up to and including 1000:
2, 4, 6, 30, 32, 34, 36, 40, 42, 44, 46, 50, 52, 54, 56, 60, 62, 64, 66
eban numbers between 1000 and 4000 (inclusive):
2000, 2002, 2004, 2006, 2030, 2032, 2034, 2036, 2040, 2042, 2044, 2046, 2050, 2052, 2054, 2056, 2060, 2062, 2064, 2066, 4000
eban numbers up to and including 10000: 79
eban numbers up to and including 100000: 399
eban numbers up to and including 1000000: 399
eban numbers up to and including 10000000: 1599
eban numbers up to and including 100000000: 7999
eban numbers up to and including 1000000000: 7999</pre>
=={{header|K}}==
{{works with|ngn/k}}
<syntaxhighlight lang=K>eban: {1_((x<)_,/(,/(2*!4)+/:10*0,3+!4)+/:1000*)/0}@_:
#eban 1000
19
#(1000>)_eban 4000
21
#eban 1e4
79
#eban 1e5
399
#eban 1e6
399
#eban 1e7
1599
#eban 1e8
7999
#eban 1e9
7999
#eban 1e10
31999
#eban 1e11
159999
#eban 1e12
159999
#eban 1e13
639999
#eban 1e14
3199999</syntaxhighlight>
=={{header|Kotlin}}==
{{trans|Go}}
<syntaxhighlight lang="scala">// Version 1.3.21
typealias Range = Triple<Int, Int, Boolean>
fun main() {
val rgs = listOf<Range>(
Range(2, 1000, true),
Range(1000, 4000, true),
Range(2, 10_000, false),
Range(2, 100_000, false),
Range(2, 1_000_000, false),
Range(2, 10_000_000, false),
Range(2, 100_000_000, false),
Range(2, 1_000_000_000, false)
)
for (rg in rgs) {
val (start, end, prnt) = rg
if (start == 2) {
println("eban numbers up to and including $end:")
} else {
println("eban numbers between $start and $end (inclusive):")
}
var count = 0
for (i in start..end step 2) {
val b = i / 1_000_000_000
var r = i % 1_000_000_000
var m = r / 1_000_000
r = i % 1_000_000
var t = r / 1_000
r %= 1_000
if (m >= 30 && m <= 66) m %= 10
if (t >= 30 && t <= 66) t %= 10
if (r >= 30 && r <= 66) r %= 10
if (b == 0 || b == 2 || b == 4 || b == 6) {
if (m == 0 || m == 2 || m == 4 || m == 6) {
if (t == 0 || t == 2 || t == 4 || t == 6) {
if (r == 0 || r == 2 || r == 4 || r == 6) {
if (prnt) print("$i ")
count++
}
}
}
}
}
if (prnt) println()
println("count = $count\n")
}
}</syntaxhighlight>
{{output}}
<pre>
Same as Go example.
</pre>
=={{header|Lua}}==
{{trans|lang}}
<syntaxhighlight lang="lua">function makeInterval(s,e,p)
return {start=s, end_=e, print_=p}
end
function main()
local intervals = {
makeInterval( 2, 1000, true),
makeInterval(1000, 4000, true),
makeInterval( 2, 10000, false),
makeInterval( 2, 1000000, false),
makeInterval( 2, 10000000, false),
makeInterval( 2, 100000000, false),
makeInterval( 2, 1000000000, false)
}
for _,intv in pairs(intervals) do
if intv.start == 2 then
print("eban numbers up to and including " .. intv.end_ .. ":")
else
print("eban numbers between " .. intv.start .. " and " .. intv.end_ .. " (inclusive)")
end
local count = 0
for i=intv.start,intv.end_,2 do
local b = math.floor(i / 1000000000)
local r = i % 1000000000
local m = math.floor(r / 1000000)
r = i % 1000000
local t = math.floor(r / 1000)
r = r % 1000
if m >= 30 and m <= 66 then m = m % 10 end
if t >= 30 and t <= 66 then t = t % 10 end
if r >= 30 and r <= 66 then r = r % 10 end
if b == 0 or b == 2 or b == 4 or b == 6 then
if m == 0 or m == 2 or m == 4 or m == 6 then
if t == 0 or t == 2 or t == 4 or t == 6 then
if r == 0 or r == 2 or r == 4 or r == 6 then
if intv.print_ then io.write(i .. " ") end
count = count + 1
end
end
end
end
end
if intv.print_ then
print()
end
print("count = " .. count)
print()
end
end
main()</syntaxhighlight>
{{out}}
<pre>eban numbers up to and including 1000:
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers between 1000 and 4000 (inclusive)
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to and including 10000:
count = 79
eban numbers up to and including 1000000:
count = 399
eban numbers up to and including 10000000:
count = 1599
eban numbers up to and including 100000000:
count = 7999
eban numbers up to and including 1000000000:
count = 7999</pre>
=={{header|Mathematica}}/{{header|Wolfram Language}}==
<syntaxhighlight lang="mathematica">ClearAll[ZeroTwoFourSixQ, EbanNumbers]
ZeroTwoFourSixQ[n_Integer] := (n == 0 || n == 2 || n == 4 || n == 6)
EbanNumbers[min_, max_, show : (False | True)] :=
Module[{counter, output, i, b, r, t, m},
counter = 0;
output = "";
i = min;
While[(i += 2) <= max,
{b, r} = QuotientRemainder[i, 10^9];
{m, r} = QuotientRemainder[r, 10^6];
{t, r} = QuotientRemainder[r, 10^3];
If[30 <= m <= 66,
m = Mod[m, 10];
];
If[30 <= t <= 66,
t = Mod[t, 10];
];
If[30 <= r <= 66,
r = Mod[r, 10];
];
If[ZeroTwoFourSixQ[b] && ZeroTwoFourSixQ[m] && ZeroTwoFourSixQ[t] &&
ZeroTwoFourSixQ[r],
counter++;
If[show,
output = output <> ToString[i] <> " ";
]
]
];
Print[min, "-", max, ": ", output, " count = ", counter]
]
EbanNumbers[0, 1000, True]
EbanNumbers[1000, 4000, True]
EbanNumbers[0, 10^4, False]
EbanNumbers[0, 10^5, False]
EbanNumbers[0, 10^6, False]
EbanNumbers[0, 10^7, False]</syntaxhighlight>
{{out}}
<pre>0-1000: 2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66 count = 19
1000-4000: 2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000 count = 21
0-10000: count = 79
0-100000: count = 399
0-1000000: count = 399
0-10000000: count = 1599</pre>
=={{header|Nim}}==
===Exhaustive search===
{{trans|Julia}}
<syntaxhighlight lang="nim">import strformat
proc iseban(n: int): bool =
if n == 0:
return false
var b = n div 1_000_000_000
var r = n mod 1_000_000_000
var m = r div 1_000_000
r = r mod 1_000_000
var t = r div 1_000
r = r mod 1_000
m = if m in 30..66: m mod 10 else: m
t = if t in 30..66: t mod 10 else: t
r = if r in 30..66: r mod 10 else: r
return {b, m, t, r} <= {0, 2, 4, 6}
echo "eban numbers up to and including 1000:"
for i in 0..100:
if iseban(i):
stdout.write(&"{i} ")
echo "\n\neban numbers between 1000 and 4000 (inclusive):"
for i in 1_000..4_000:
if iseban(i):
stdout.write(&"{i} ")
var count = 0
for i in 0..10_000:
if iseban(i):
inc count
echo &"\n\nNumber of eban numbers up to and including {10000:8}: {count:4}"
count = 0
for i in 0..100_000:
if iseban(i):
inc count
echo &"\nNumber of eban numbers up to and including {100000:8}: {count:4}"
count = 0
for i in 0..1_000_000:
if iseban(i):
inc count
echo &"\nNumber of eban numbers up to and including {1000000:8}: {count:4}"
count = 0
for i in 0..10_000_000:
if iseban(i):
inc count
echo &"\nNumber of eban numbers up to and including {10000000:8}: {count:4}"
count = 0
for i in 0..100_000_000:
if iseban(i):
inc count
echo &"\nNumber of eban numbers up to and including {100000000:8}: {count:4}"</syntaxhighlight>
{{out}}
<pre>
eban numbers up to and including 1000:
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
eban numbers between 1000 and 4000 (inclusive):
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
Number of eban numbers up to and including 10000: 79
Number of eban numbers up to and including 100000: 399
Number of eban numbers up to and including 1000000: 399
Number of eban numbers up to and including 10000000: 1599
</pre>
===Algorithmic computation===
{{trans|Phix}}
<syntaxhighlight lang="nim">import math, strutils, strformat
#---------------------------------------------------------------------------------------------------
func ebanCount(p10: Natural): Natural =
## Return the count of eban numbers 1..10^p10.
let
n = p10 - p10 div 3
p5 = n div 2
p4 = (n + 1) div 2
result = 5^p5 * 4^p4 - 1
#---------------------------------------------------------------------------------------------------
func eban(n: Natural): bool =
## Return true if n is an eban number (only fully tested to 10e9).
if n == 0: return false
var n = n
while n != 0:
let thou = n mod 1000
if thou div 100 != 0: return false
if thou div 10 notin {0, 3, 4, 5, 6}: return false
if thou mod 10 notin {0, 2, 4, 6}: return false
n = n div 1000
result = true
#———————————————————————————————————————————————————————————————————————————————————————————————————
var s: seq[Natural]
for i in 0..1000:
if eban(i): s.add(i)
echo fmt"Eban to 1000: {s.join("", "")} ({s.len} items)"
s.setLen(0)
for i in 1000..4000:
if eban(i): s.add(i)
echo fmt"Eban 1000..4000: {s.join("", "")} ({s.len} items)"
import times
let t0 = getTime()
for i in 0..21:
echo fmt"ebanCount(10^{i}): {ebanCount(i)}"
echo ""
echo fmt"Time: {getTime() - t0}"</syntaxhighlight>
{{out}}
<pre>Eban to 1000: 2, 4, 6, 30, 32, 34, 36, 40, 42, 44, 46, 50, 52, 54, 56, 60, 62, 64, 66 (19 items)
Eban 1000..4000: 2000, 2002, 2004, 2006, 2030, 2032, 2034, 2036, 2040, 2042, 2044, 2046, 2050, 2052, 2054, 2056, 2060, 2062, 2064, 2066, 4000 (21 items)
ebanCount(10^0): 0
ebanCount(10^1): 3
ebanCount(10^2): 19
ebanCount(10^3): 19
ebanCount(10^4): 79
ebanCount(10^5): 399
ebanCount(10^6): 399
ebanCount(10^7): 1599
ebanCount(10^8): 7999
ebanCount(10^9): 7999
ebanCount(10^10): 31999
ebanCount(10^11): 159999
ebanCount(10^12): 159999
ebanCount(10^13): 639999
ebanCount(10^14): 3199999
ebanCount(10^15): 3199999
ebanCount(10^16): 12799999
ebanCount(10^17): 63999999
ebanCount(10^18): 63999999
ebanCount(10^19): 255999999
ebanCount(10^20): 1279999999
ebanCount(10^21): 1279999999
Time: 189 microseconds and 491 nanoseconds</pre>
=={{header|Odin}}==
<syntaxhighlight lang="Go">
package eban_numbers
/* imports */
import "core:fmt"
/* globals */
Range :: struct {
start: i32,
end: i32,
print: bool,
}
printcounter: i32 = 0
/* main block */
main :: proc() {
rgs := [?]Range{
{2, 1000, true},
{1000, 4000, true},
{2, 1e4, false},
{2, 1e5, false},
{2, 1e6, false},
{2, 1e7, false},
{2, 1e8, false},
{2, 1e9, false},
}
for rg in rgs {
if rg.start == 2 {
fmt.printf("eban numbers up to and including %d:\n", rg.end)
} else {
fmt.printf("eban numbers between %d and %d (inclusive):\n", rg.start, rg.end)
}
count := i32(0)
for i := rg.start; i <= i32(rg.end); i += i32(2) {
b := i / 1000000000
r := i % 1000000000
m := r / 1000000
r = i % 1000000
t := r / 1000
r %= 1000
if m >= 30 && m <= 66 {
m %= 10
}
if t >= 30 && t <= 66 {
t %= 10
}
if r >= 30 && r <= 66 {
r %= 10
}
if b == 0 || b == 2 || b == 4 || b == 6 {
if m == 0 || m == 2 || m == 4 || m == 6 {
if t == 0 || t == 2 || t == 4 || t == 6 {
if r == 0 || r == 2 || r == 4 || r == 6 {
if rg.print {
fmt.printf("%d ", i)
}
count += 1
}
}
}
}
}
if rg.print {
fmt.println()
}
fmt.println("count =", count, "\n")
}
}
</syntaxhighlight>
{{out}}
<pre>
eban numbers up to and including 1000:
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers between 1000 and 4000 (inclusive):
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to and including 10000:
count = 79
eban numbers up to and including 100000:
count = 399
eban numbers up to and including 1000000:
count = 399
eban numbers up to and including 10000000:
count = 1599
eban numbers up to and including 100000000:
count = 7999
eban numbers up to and including 1000000000:
count = 7999
</pre>
=={{header|Perl}}==
===Exhaustive search===
A couple of 'e'-specific optimizations keep the running time reasonable.
<syntaxhighlight lang="perl">use strict;
use warnings;
use feature 'say';
use Lingua::EN::Numbers qw(num2en);
sub comma { reverse ((reverse shift) =~ s/(.{3})/$1,/gr) =~ s/^,//r }
sub e_ban {
my($power) = @_;
my @n;
for (1..10**$power) {
next unless 0 == $_%2;
next if $_ =~ /[789]/ or /[12].$/ or /[135]..$/ or /[135]...$/ or /[135].....$/;
push @n, $_ unless num2en($_) =~ /e/;
}
@n;
}
my @OK = e_ban(my $max = 7);
my @a = grep { $_ <= 1000 } @OK;
say "Number of eban numbers up to and including 1000: @{[1+$#a]}";
say join(', ',@a);
say '';
my @b = grep { $_ >= 1000 && $_ <= 4000 } @OK;
say "Number of eban numbers between 1000 and 4000 (inclusive): @{[1+$#b]}";
say join(', ',@b);
say '';
for my $exp (4..$max) {
my $n = + grep { $_ <= 10**$exp } @OK;
printf "Number of eban numbers and %10s: %d\n", comma(10**$exp), $n;
}</syntaxhighlight>
{{out}}
<pre>eban numbers up to and including 1000:
2, 4, 6, 30, 32, 34, 36, 40, 42, 44, 46, 50, 52, 54, 56, 60, 62, 64, 66
eban numbers between 1000 and 4000 (inclusive):
2000, 2002, 2004, 2006, 2030, 2032, 2034, 2036, 2040, 2042, 2044, 2046, 2050, 2052, 2054, 2056, 2060, 2062, 2064, 2066, 4000
Number of eban numbers up to 10,000: 79
Number of eban numbers up to 100,000: 399
Number of eban numbers up to 1,000,000: 399
Number of eban numbers up to 10,000,000: 1599</pre>
===Algorithmically generate / count===
Alternately, a partial translation of Raku. Does not need to actually generate the e-ban numbers to count them. Display counts up to 10**21.
<syntaxhighlight lang="perl">use strict;
use warnings;
use bigint;
use feature 'say';
use Lingua::EN::Nums2Words 'num2word';
use List::AllUtils 'sum';
sub comma { reverse ((reverse shift) =~ s/(.{3})/$1,/gr) =~ s/^,//r }
sub nban {
my ($n, @numbers) = @_;
grep { lc(num2word($_)) !~ /[$n]/i } @numbers;
}
sub enumerate {
my ($n, $upto) = @_;
my @ban = nban($n, 1 .. 99);
my @orders;
for my $o (2 .. $upto) {
push @orders, [nban($n, map { $_ * 10**$o } 1 .. 9)];
}
for my $oom (@orders) {
next unless +@$oom;
my @these;
for my $num (@$oom) {
push @these, $num, map { $_ + $num } @ban;
}
push @ban, @these;
}
unshift @ban, 0 if nban($n, 0);
@ban
}
sub count {
my ($n, $upto) = @_;
my @orders;
for my $o (2 .. $upto) {
push @orders, [nban($n, map { $_ * 10**$o } 1 .. 9)];
}
my @count = scalar nban($n, 1 .. 99);
for my $o ( 0 .. $#orders - 1 ) {
push @count, sum(@count) * (scalar @{$orders[$o]}) + (scalar @{$orders[$o]});
}
++$count[0] if nban($n, 0);
for my $m ( 0 .. $#count - 1 ) {
next unless scalar $orders[$m];
if (nban($n, 10**($m+2))) { $count[$m]++; $count[$m + 1]-- }
}
map { sum( @count[0..$_] ) } 0..$#count;
}
for my $t ('e') {
my @bans = enumerate($t, 4);
my @count = count($t, my $max = 21);
my @j = grep { $_ <= 10 } @bans;
unshift @count, @{[1+$#j]};
say "\n============= $t-ban: =============";
my @a = grep { $_ <= 1000 } @bans;
say "$t-ban numbers up to 1000: @{[1+$#a]}";
say '[', join(' ',@a), ']';
say '';
my @b = grep { $_ >= 1000 && $_ <= 4000 } @bans;
say "$t-ban numbers between 1,000 & 4,000 (inclusive): @{[1+$#b]}";
say '[', join(' ',@b), ']';
say '';
say "Counts of $t-ban numbers up to ", lc(num2word(10**$max));
for my $exp (1..$max) {
my $nu = $count[$exp-1];
printf "Up to and including %23s: %s\n", lc(num2word(10**$exp)), comma($nu);
}
}</syntaxhighlight>
<pre>============= e-ban: =============
e-ban numbers up to 1000: 19
[2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66]
e-ban numbers between 1,000 & 4,000 (inclusive): 21
[2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000]
Counts of e-ban numbers up to one sextillion
Up to and including ten: 3
Up to and including one hundred: 19
Up to and including one thousand: 19
Up to and including ten thousand: 79
Up to and including one hundred thousand: 399
Up to and including one million: 399
Up to and including ten million: 1,599
Up to and including one hundred million: 7,999
Up to and including one billion: 7,999
Up to and including ten billion: 31,999
Up to and including one hundred billion: 159,999
Up to and including one trillion: 159,999
Up to and including ten trillion: 639,999
Up to and including one hundred trillion: 3,199,999
Up to and including one quadrillion: 3,199,999
Up to and including ten quadrillion: 12,799,999
Up to and including one hundred quadrillion: 63,999,999
Up to and including one quintillion: 63,999,999
Up to and including ten quintillion: 255,999,999
Up to and including one hundred quintillion: 1,279,999,999
Up to and including one sextillion: 1,279,999,999</pre>
=={{header|Phix}}==
Why count when you can calculate?
<!--<syntaxhighlight lang="phix">(phixonline)-->
<span style="color: #008080;">with</span> <span style="color: #008080;">javascript_semantics</span>
<span style="color: #008080;">function</span> <span style="color: #000000;">count_eban</span><span style="color: #0000FF;">(</span><span style="color: #004080;">integer</span> <span style="color: #000000;">p10</span><span style="color: #0000FF;">)</span>
<span style="color: #000080;font-style:italic;">-- returns the count of eban numbers 1..power(10,p10)</span>
<span style="color: #004080;">integer</span> <span style="color: #000000;">n</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">p10</span><span style="color: #0000FF;">-</span><span style="color: #7060A8;">floor</span><span style="color: #0000FF;">(</span><span style="color: #000000;">p10</span><span style="color: #0000FF;">/</span><span style="color: #000000;">3</span><span style="color: #0000FF;">),</span>
<span style="color: #000000;">p5</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">floor</span><span style="color: #0000FF;">(</span><span style="color: #000000;">n</span><span style="color: #0000FF;">/</span><span style="color: #000000;">2</span><span style="color: #0000FF;">),</span>
<span style="color: #000000;">p4</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">floor</span><span style="color: #0000FF;">((</span><span style="color: #000000;">n</span><span style="color: #0000FF;">+</span><span style="color: #000000;">1</span><span style="color: #0000FF;">)/</span><span style="color: #000000;">2</span><span style="color: #0000FF;">)</span>
<span style="color: #008080;">return</span> <span style="color: #7060A8;">power</span><span style="color: #0000FF;">(</span><span style="color: #000000;">5</span><span style="color: #0000FF;">,</span><span style="color: #000000;">p5</span><span style="color: #0000FF;">)*</span><span style="color: #7060A8;">power</span><span style="color: #0000FF;">(</span><span style="color: #000000;">4</span><span style="color: #0000FF;">,</span><span style="color: #000000;">p4</span><span style="color: #0000FF;">)-</span><span style="color: #000000;">1</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #008080;">function</span> <span style="color: #000000;">eban</span><span style="color: #0000FF;">(</span><span style="color: #004080;">integer</span> <span style="color: #000000;">n</span><span style="color: #0000FF;">)</span>
<span style="color: #000080;font-style:italic;">-- returns true if n is an eban number (only fully tested to 10e9)</span>
<span style="color: #008080;">if</span> <span style="color: #000000;">n</span><span style="color: #0000FF;">=</span><span style="color: #000000;">0</span> <span style="color: #008080;">then</span> <span style="color: #008080;">return</span> <span style="color: #004600;">false</span> <span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #008080;">while</span> <span style="color: #000000;">n</span> <span style="color: #008080;">do</span>
<span style="color: #004080;">integer</span> <span style="color: #000000;">thou</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">remainder</span><span style="color: #0000FF;">(</span><span style="color: #000000;">n</span><span style="color: #0000FF;">,</span><span style="color: #000000;">1000</span><span style="color: #0000FF;">)</span>
<span style="color: #008080;">if</span> <span style="color: #7060A8;">floor</span><span style="color: #0000FF;">(</span><span style="color: #000000;">thou</span><span style="color: #0000FF;">/</span><span style="color: #000000;">100</span><span style="color: #0000FF;">)!=</span><span style="color: #000000;">0</span> <span style="color: #008080;">then</span> <span style="color: #008080;">return</span> <span style="color: #004600;">false</span> <span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #008080;">if</span> <span style="color: #008080;">not</span> <span style="color: #7060A8;">find</span><span style="color: #0000FF;">(</span><span style="color: #7060A8;">floor</span><span style="color: #0000FF;">(</span><span style="color: #000000;">thou</span><span style="color: #0000FF;">/</span><span style="color: #000000;">10</span><span style="color: #0000FF;">),{</span><span style="color: #000000;">0</span><span style="color: #0000FF;">,</span><span style="color: #000000;">3</span><span style="color: #0000FF;">,</span><span style="color: #000000;">4</span><span style="color: #0000FF;">,</span><span style="color: #000000;">5</span><span style="color: #0000FF;">,</span><span style="color: #000000;">6</span><span style="color: #0000FF;">})</span> <span style="color: #008080;">then</span> <span style="color: #008080;">return</span> <span style="color: #004600;">false</span> <span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #008080;">if</span> <span style="color: #008080;">not</span> <span style="color: #7060A8;">find</span><span style="color: #0000FF;">(</span><span style="color: #7060A8;">remainder</span><span style="color: #0000FF;">(</span><span style="color: #000000;">thou</span><span style="color: #0000FF;">,</span><span style="color: #000000;">10</span><span style="color: #0000FF;">),{</span><span style="color: #000000;">0</span><span style="color: #0000FF;">,</span><span style="color: #000000;">2</span><span style="color: #0000FF;">,</span><span style="color: #000000;">4</span><span style="color: #0000FF;">,</span><span style="color: #000000;">6</span><span style="color: #0000FF;">})</span> <span style="color: #008080;">then</span> <span style="color: #008080;">return</span> <span style="color: #004600;">false</span> <span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #000000;">n</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">floor</span><span style="color: #0000FF;">(</span><span style="color: #000000;">n</span><span style="color: #0000FF;">/</span><span style="color: #000000;">1000</span><span style="color: #0000FF;">)</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">while</span>
<span style="color: #008080;">return</span> <span style="color: #004600;">true</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #004080;">sequence</span> <span style="color: #000000;">s</span> <span style="color: #0000FF;">=</span> <span style="color: #0000FF;">{}</span>
<span style="color: #008080;">for</span> <span style="color: #000000;">i</span><span style="color: #0000FF;">=</span><span style="color: #000000;">0</span> <span style="color: #008080;">to</span> <span style="color: #000000;">1000</span> <span style="color: #008080;">do</span>
<span style="color: #008080;">if</span> <span style="color: #000000;">eban</span><span style="color: #0000FF;">(</span><span style="color: #000000;">i</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">then</span> <span style="color: #000000;">s</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">append</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">,</span><span style="color: #7060A8;">sprint</span><span style="color: #0000FF;">(</span><span style="color: #000000;">i</span><span style="color: #0000FF;">))</span> <span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">for</span>
<span style="color: #7060A8;">printf</span><span style="color: #0000FF;">(</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #008000;">"eban to 1000 : %s\n\n"</span><span style="color: #0000FF;">,{</span><span style="color: #7060A8;">join</span><span style="color: #0000FF;">(</span><span style="color: #7060A8;">shorten</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">,</span><span style="color: #008000;">"items"</span><span style="color: #0000FF;">,</span><span style="color: #000000;">8</span><span style="color: #0000FF;">))})</span>
<span style="color: #000000;">s</span> <span style="color: #0000FF;">=</span> <span style="color: #0000FF;">{}</span>
<span style="color: #008080;">for</span> <span style="color: #000000;">i</span><span style="color: #0000FF;">=</span><span style="color: #000000;">1000</span> <span style="color: #008080;">to</span> <span style="color: #000000;">4000</span> <span style="color: #008080;">do</span>
<span style="color: #008080;">if</span> <span style="color: #000000;">eban</span><span style="color: #0000FF;">(</span><span style="color: #000000;">i</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">then</span> <span style="color: #000000;">s</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">append</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">,</span><span style="color: #7060A8;">sprint</span><span style="color: #0000FF;">(</span><span style="color: #000000;">i</span><span style="color: #0000FF;">))</span> <span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">for</span>
<span style="color: #7060A8;">printf</span><span style="color: #0000FF;">(</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #008000;">"eban 1000..4000 : %s\n\n"</span><span style="color: #0000FF;">,{</span><span style="color: #7060A8;">join</span><span style="color: #0000FF;">(</span><span style="color: #7060A8;">shorten</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">,</span><span style="color: #008000;">"items"</span><span style="color: #0000FF;">,</span><span style="color: #000000;">4</span><span style="color: #0000FF;">))})</span>
<span style="color: #004080;">atom</span> <span style="color: #000000;">t0</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">time</span><span style="color: #0000FF;">()</span>
<span style="color: #008080;">for</span> <span style="color: #000000;">i</span><span style="color: #0000FF;">=</span><span style="color: #000000;">0</span> <span style="color: #008080;">to</span> <span style="color: #000000;">21</span> <span style="color: #008080;">do</span>
<span style="color: #7060A8;">printf</span><span style="color: #0000FF;">(</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #008000;">"count_eban(10^%d) : %,d\n"</span><span style="color: #0000FF;">,{</span><span style="color: #000000;">i</span><span style="color: #0000FF;">,</span><span style="color: #000000;">count_eban</span><span style="color: #0000FF;">(</span><span style="color: #000000;">i</span><span style="color: #0000FF;">)})</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">for</span>
<span style="color: #0000FF;">?</span><span style="color: #7060A8;">elapsed</span><span style="color: #0000FF;">(</span><span style="color: #7060A8;">time</span><span style="color: #0000FF;">()-</span><span style="color: #000000;">t0</span><span style="color: #0000FF;">)</span>
<!--</syntaxhighlight>-->
{{out}}
<pre>
eban to 1000 : 2 4 6 30 32 34 36 40 ... 50 52 54 56 60 62 64 66 (19 items)
eban 1000..4000 : 2000 2002 2004 2006 ... 2062 2064 2066 4000 (21 items)
count_eban(10^0) : 0
count_eban(10^1) : 3
count_eban(10^2) : 19
count_eban(10^3) : 19
count_eban(10^4) : 79
count_eban(10^5) : 399
count_eban(10^6) : 399
count_eban(10^7) : 1,599
count_eban(10^8) : 7,999
count_eban(10^9) : 7,999
count_eban(10^10) : 31,999
count_eban(10^11) : 159,999
count_eban(10^12) : 159,999
count_eban(10^13) : 639,999
count_eban(10^14) : 3,199,999
count_eban(10^15) : 3,199,999
count_eban(10^16) : 12,799,999
count_eban(10^17) : 63,999,999
count_eban(10^18) : 63,999,999
count_eban(10^19) : 255,999,999
count_eban(10^20) : 1,279,999,999
count_eban(10^21) : 1,279,999,999
"0s"
</pre>
=={{header|PicoLisp}}==
<syntaxhighlight lang="picolisp">(de _eban? (N)
(let
(B (/ N 1000000000)
R (% N 1000000000)
M (/ R 1000000)
R (% N 1000000)
Z (/ R 1000)
R (% R 1000) )
(and
(>= M 30)
(<= M 66)
(setq M (% M 10)) )
(and
(>= Z 30)
(<= Z 66)
(setq Z (% Z 10)) )
(and
(>= R 30)
(<= R 66)
(setq R (% R 10)) )
(fully
'((S)
(unless (bit? 1 (val S))
(>= 6 (val S)) ) )
'(B M Z R) ) ) )
(de eban (B A)
(default A 2)
(let R (cons 0 (cons))
(for (N A (>= B N) (+ N 2))
(and
(_eban? N)
(inc R)
(push (cdr R) N) ) )
(con R (flip (cadr R)))
R ) )
(off R)
(prinl "eban numbers up to an including 1000:")
(setq R (eban 1000))
(println (cdr R))
(prinl "count: " (car R))
(prinl)
(prinl "eban numbers between 1000 and 4000")
(setq R (eban 4000 1000))
(println (cdr R))
(prinl "count: " (car R))
(prinl)
(prinl "eban numbers up to an including 10000:")
(prinl "count: " (car (eban 10000)))
(prinl)
(prinl "eban numbers up to an including 100000:")
(prinl "count: " (car (eban 100000)))
(prinl)
(prinl "eban numbers up to an including 1000000:")
(prinl "count: " (car (eban 1000000)))
(prinl)
(prinl "eban numbers up to an including 10000000:")
(prinl "count: " (car (eban 10000000)))</syntaxhighlight>
{{out}}
<pre>
eban numbers up to an including 1000:
(2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66)
count: 19
eban numbers between 1000 and 4000
(2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000)
count: 21
eban numbers up to an including 10000:
count: 79
eban numbers up to an including 100000:
count: 399
eban numbers up to an including 1000000:
count: 399
eban numbers up to an including 10000000:
count: 1599
</pre>
=={{header|Python}}==
<syntaxhighlight lang="python">
# Use inflect
"""
show all eban numbers <= 1,000 (in a horizontal format), and a count
show all eban numbers between 1,000 and 4,000 (inclusive), and a count
show a count of all eban numbers up and including 10,000
show a count of all eban numbers up and including 100,000
show a count of all eban numbers up and including 1,000,000
show a count of all eban numbers up and including 10,000,000
"""
import inflect
import time
before = time.perf_counter()
p = inflect.engine()
# eban numbers <= 1000
print(' ')
print('eban numbers up to and including 1000:')
print(' ')
count = 0
for i in range(1,1001):
if not 'e' in p.number_to_words(i):
print(str(i)+' ',end='')
count += 1
print(' ')
print(' ')
print('count = '+str(count))
print(' ')
# eban numbers 1000 to 4000
print(' ')
print('eban numbers between 1000 and 4000 (inclusive):')
print(' ')
count = 0
for i in range(1000,4001):
if not 'e' in p.number_to_words(i):
print(str(i)+' ',end='')
count += 1
print(' ')
print(' ')
print('count = '+str(count))
print(' ')
# eban numbers up to 10000
print(' ')
print('eban numbers up to and including 10000:')
print(' ')
count = 0
for i in range(1,10001):
if not 'e' in p.number_to_words(i):
count += 1
print(' ')
print('count = '+str(count))
print(' ')
# eban numbers up to 100000
print(' ')
print('eban numbers up to and including 100000:')
print(' ')
count = 0
for i in range(1,100001):
if not 'e' in p.number_to_words(i):
count += 1
print(' ')
print('count = '+str(count))
print(' ')
# eban numbers up to 1000000
print(' ')
print('eban numbers up to and including 1000000:')
print(' ')
count = 0
for i in range(1,1000001):
if not 'e' in p.number_to_words(i):
count += 1
print(' ')
print('count = '+str(count))
print(' ')
# eban numbers up to 10000000
print(' ')
print('eban numbers up to and including 10000000:')
print(' ')
count = 0
for i in range(1,10000001):
if not 'e' in p.number_to_words(i):
count += 1
print(' ')
print('count = '+str(count))
print(' ')
after = time.perf_counter()
print(" ")
print("Run time in seconds: "+str(after - before))
</syntaxhighlight>
Output:
<pre>
eban numbers up to and including 1000:
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers between 1000 and 4000 (inclusive):
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to and including 10000:
count = 79
eban numbers up to and including 100000:
count = 399
eban numbers up to and including 1000000:
count = 399
eban numbers up to and including 10000000:
count = 1599
Run time in seconds: 1134.289519125
</pre>
=={{header|Quackery}}==
<syntaxhighlight lang="Quackery"> [ 20 /mod
4 /mod
[ table 0 2 4 6 ]
swap
[ table 0 30 40 50 60 ]
+
over 0 = iff nip done
swap recurse 1000 * + ] is n->eban ( n --> n )
[] 1
[ dup n->eban
dup 10000001 < while
swap dip join
1+ again ]
2drop
dup dup
say "eban numbers up to and including 1000:"
cr
findwith [ 1000 > ] [ ]
split drop dup echo cr
say "count: " size echo
cr cr
say "eban numbers between 1000 and 4000 (inclusive):"
cr
dup dup
findwith [ 999 > ] [ ]
split nip
dup
findwith [ 4001 > ] [ ]
split drop dup echo cr
say "count: " size echo
cr cr
say "number of eban numbers up to and including 10000: "
dup findwith [ 10001 > ] [ ]
echo
cr cr
say "number of eban numbers up to and including 100000: "
dup findwith [ 100001 > ] [ ]
echo
cr cr
say "number of eban numbers up to and including 1000000: "
dup findwith [ 1000001 > ] [ ]
echo
cr cr
say "number of eban numbers up to and including 10000000: "
findwith [ 10000001 > ] [ ]
echo</syntaxhighlight>
{{out}}
<pre>eban numbers up to and including 1000
[ 2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66 ]
count: 19
eban numbers between 1000 and 4000 (inclusive):
[ 2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000 ]
count: 21
number of eban numbers up to and including 10000: 79
number of eban numbers up to and including 100000: 399
number of eban numbers up to and including 1000000: 399
number of eban numbers up to and including 10000000: 1599</pre>
=={{header|Raku}}==
(formerly Perl 6)
{{works with|Rakudo|2018.12}}
Modular approach, very little is hard coded. Change the $upto order-of-magnitude limit to adjust the search/display ranges. Change the letter(s) given to the
Will handle multi-character 'bans'. Demonstrate for e-ban, t-ban and subur-ban.
Line 135 ⟶ 2,558:
Directly find :
:* [[oeis:A006933|OEIS:A006933 Numbers without e]]: Eban
:* [[oeis:A008521|OEIS:A008521 Numbers without o]]: Oban
:* [[oeis:A008523|OEIS:A008523 Numbers without t]]: Tban
:* [[oeis:A072954|OEIS:A072954 Numbers without a, i, l, t]]: TALIban
:* [[oeis:A072955|OEIS:A072955 Numbers without b, r, s, u]]: SUBURban
:* [[oeis:A072956|OEIS:A072956 Numbers without r, t, u]]: TURban
:* [[oeis:A072957|OEIS:A072957 Numbers without r, u]]: URban
:* [[oeis:A072958|OEIS:A072958 Numbers without a, c, i, l]]: CALIban
:* [[oeis:A089589|OEIS:A089589 Numbers without i]]: Iban
:* [[oeis:A089590|OEIS:A089590 Numbers without u]]: Uban
:* ''and so on...''
Considering numbers up to <strong>10<sup>21</sup></strong>, as the task directions suggest.
<syntaxhighlight lang="raku" line>use Lingua::EN::Numbers;
sub nban ($seq, $n = 'e') { ($seq).map: { next if .&cardinal.contains(any($n.lc.comb)); $_ } }
sub enumerate ($n, $upto) {
my
(2 .. $upto).map: -> $o {
given $o % 3 { # Compensate for irregulars: 11 - 19
when 1 { @orders.push: [flat (10**($o - 1) X* 10 .. 19).map(*.&nban($n)), |(10**$o X* 2 .. 9).map: *.&nban($n)] }
default { @orders.push: [flat (10**$o X* 1 .. 9).map: *.&nban($n)] }
}
}
^@orders .map: -> $o {
@ban.push: [] and next unless +@orders[$o];
my @these;
@
@
for ^@ban -> $b {
next unless +@ban[$b];
@these.push: $_ for (flat @ban[$b]) »+» $m ;
}
}
@ban.push: @these;
}
@ban.unshift(0) if
flat @ban.map: *.flat;
}
sub count ($n, $upto) {
my @orders;
(2 .. $upto).map: -> $o {
given $o % 3 { # Compensate for irregulars: 11 - 19
when 1 { @orders.push: [flat (10**($o - 1) X* 10 .. 19).map(*.&nban($n)), |(10**$o X* 2 .. 9).map: *.&nban($n)] }
default { @orders.push: [flat (10**$o X* 1 .. 9).map: *.&nban($n)] }
}
}
my @count = +nban(1 .. 99, $n);
^@orders .map: -> $o {
@count.push: 0 and next unless +@orders[$o];
my $prev = so (@orders[$o].first( { $_ ~~ /^ '1' '0'+ $/ } ) // 0 );
my $sum = @count.sum;
my $these = +@orders[$o] * $sum + @orders[$o];
$these-- if $prev;
@count[1 + $o] += $these;
++@count[$o] if $prev;
}
++@count[0] if nban(0, $n);
[\+] @count;
}
#for
for < e t subur > -> $n { # An assortment for demonstration
my
my @bans = enumerate($n, 4);
my @counts = count($n, $upto);
# DISPLAY
Line 173 ⟶ 2,632:
my @j = @bans.grep: 1000 <= * <= 4000;
put "\n============= {$n}-ban: =============\n" ~
"{$n}-ban numbers up to 1000: {+@k}\n[{@k».&comma
"{$n}-ban numbers between 1,000 & 4,000: {+@j}\n[{@j».&comma
"\nCounts of {$n}-ban numbers up to {cardinal 10**$upto}"
;
for ^$upto -> $c {
printf "Up to and including %{$s}s: %s\n", cardinal(10**($c+1)), comma(@counts[$c]);
}
}</
{{out}}
<pre>============= e-ban: =============
Line 189 ⟶ 2,651:
[2,000 2,002 2,004 2,006 2,030 2,032 2,034 2,036 2,040 2,042 2,044 2,046 2,050 2,052 2,054 2,056 2,060 2,062 2,064 2,066 4,000]
Counts of e-ban numbers up to one sextillion
Up to and including
Up to and including
Up to and including
Up to and including
Up to and including
Up to and including
Up to and including
Up to and
Up to
Up to and including ten billion: 31,999
Up to and including one hundred billion: 159,999
Up to and including one trillion: 159,999
Up to and including ten trillion: 639,999
Up to and including one hundred trillion: 3,199,999
Up to and including one quadrillion: 3,199,999
Up to and including ten quadrillion: 12,799,999
Up to and including one hundred quadrillion: 63,999,999
Up to and including one quintillion: 63,999,999
Up to and including ten quintillion: 255,999,999
Up to and including one hundred quintillion: 1,279,999,999
Up to and including one sextillion: 1,279,999,999
============= t-ban: =============
Line 207 ⟶ 2,681:
[]
Counts of t-ban numbers up to one sextillion
Up to and including
Up to and including
Up to and including
Up to and including
Up to and including
Up to and including
Up to and including
Up to and including one hundred million: 785
Up to and including one billion: 5,489
Up to and including ten billion: 38,416
Up to and including one hundred billion: 76,833
Up to and including one trillion: 537,824
Up to and including ten trillion: 537,824
Up to and including one hundred trillion: 537,824
Up to and including one quadrillion: 537,825
Up to and including ten quadrillion: 3,764,768
Up to and including one hundred quadrillion: 7,529,537
Up to and including one quintillion: 52,706,752
Up to and including ten quintillion: 52,706,752
Up to and including one hundred quintillion: 52,706,752
Up to and including one sextillion: 52,706,752
============= subur-ban: =============
Line 225 ⟶ 2,711:
[]
Counts of subur-ban numbers up to one sextillion
Up to and including
Up to and including
Up to and including
Up to and including
Up to and including
Up to and including
Up to and including
Up to and including one hundred million: 2,375
Up to and including one billion: 2,375
Up to and including ten billion: 2,375
Up to and including one hundred billion: 2,375
Up to and including one trillion: 2,375
Up to and including ten trillion: 2,375
Up to and including one hundred trillion: 2,375
Up to and including one quadrillion: 2,375
Up to and including ten quadrillion: 2,375
Up to and including one hundred quadrillion: 2,375
Up to and including one quintillion: 2,375
Up to and including ten quintillion: 2,375
Up to and including one hundred quintillion: 2,375
Up to and including one sextillion: 2,375</pre>
Note that the limit to one sextillion is somewhat arbitrary and is just to match the task parameters.
This will quite happily count *-bans up to one hundred centillion. (10<sup>305</sup>) It takes longer, but still on the order of seconds, not minutes.
<pre>Counts of e-ban numbers up to one hundred centillion
...
Up to and including one hundred centillion: 35,184,372,088,831,999,999,999,999,999,999,999,999,999,999,999,999,999,999,999</pre>
=={{header|REXX}}==
Programming note: REXX has no shortcuts for '''if''' statements, so the multiple '''if''' statements weren't combined into one.
<
numeric digits 20 /*support some gihugic numbers for pgm.*/
parse arg $ /*obtain optional arguments from the cL*/
Line 275 ⟶ 2,780:
if hun\==' ' then return 1 /*any hundrEd (not zero) has an "e". */
end /*k*/ /*A "period" is a group of 3 dec. digs */
return 0 /*in the number, grouped from the right*/</
{{out|output|text= when using the default inputs:}}
<pre>
Line 298 ⟶ 2,803:
1599 eban numbers found for: 1 -10000000
═════════════════════════════════════════════════════════════════════════════════════════════════════════
</pre>
=={{header|RPL}}==
{{trans|Julia}}
{{works with|HP|49}}
« '''IF''' DUP '''THEN'''
1000000000 IDIV2
1000000 IDIV2
1000 IDIV2
3 →LIST
« → x « 30 x ≤ x 66 ≤ AND x 10 MOD x IFTE » » MAP
+
« { 0 2 4 6 } SWAP POS » MAP ΠLIST
'''END'''
» » '<span style="color:blue">EBAN?</span>' STO
« { }
UNROT '''FOR''' j
'''IF''' j <span style="color:blue">EBAN?</span> '''THEN''' j + '''END'''
'''NEXT'''
» » '<span style="color:blue">TASK1</span>' STO
« 0
1 ROT '''FOR''' j
'''IF''' j <span style="color:blue">EBAN?</span> '''THEN''' 1 + '''END'''
'''NEXT'''
» » '<span style="color:blue">TASK2</span>' STO
1 1000 <span style="color:blue">TASK1</span>
1000 4000 <span style="color:blue">TASK1</span>
10000 <span style="color:blue">TASK2</span>
{{out}}
<pre>
3: { 2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66 }
2: { 2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000 }
1: 79
</pre>
=={{header|Ruby}}==
{{trans|C#}}
<syntaxhighlight lang="ruby">def main
intervals = [
[2, 1000, true],
[1000, 4000, true],
[2, 10000, false],
[2, 100000, false],
[2, 1000000, false],
[2, 10000000, false],
[2, 100000000, false],
[2, 1000000000, false]
]
for intv in intervals
(start, ending, display) = intv
if start == 2 then
print "eban numbers up to and including %d:\n" % [ending]
else
print "eban numbers between %d and %d (inclusive):\n" % [start, ending]
end
count = 0
for i in (start .. ending).step(2)
b = (i / 1000000000).floor
r = (i % 1000000000)
m = (r / 1000000).floor
r = (r % 1000000)
t = (r / 1000).floor
r = (r % 1000)
if m >= 30 and m <= 66 then
m = m % 10
end
if t >= 30 and t <= 66 then
t = t % 10
end
if r >= 30 and r <= 66 then
r = r % 10
end
if b == 0 or b == 2 or b == 4 or b == 6 then
if m == 0 or m == 2 or m == 4 or m == 6 then
if t == 0 or t == 2 or t == 4 or t == 6 then
if r == 0 or r == 2 or r == 4 or r == 6 then
if display then
print ' ', i
end
count = count + 1
end
end
end
end
end
if display then
print "\n"
end
print "count = %d\n\n" % [count]
end
end
main()</syntaxhighlight>
{{out}}
<pre>eban numbers up to and including 1000:
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers between 1000 and 4000 (inclusive):
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to and including 10000:
count = 79
eban numbers up to and including 100000:
count = 399
eban numbers up to and including 1000000:
count = 399
eban numbers up to and including 10000000:
count = 1599
eban numbers up to and including 100000000:
count = 7999
eban numbers up to and including 1000000000:
count = 7999</pre>
=={{header|Scala}}==
{{trans|Java}}
<syntaxhighlight lang="scala">object EbanNumbers {
class ERange(s: Int, e: Int, p: Boolean) {
val start: Int = s
val end: Int = e
val print: Boolean = p
}
def main(args: Array[String]): Unit = {
val rgs = List(
new ERange(2, 1000, true),
new ERange(1000, 4000, true),
new ERange(2, 10000, false),
new ERange(2, 100000, false),
new ERange(2, 1000000, false),
new ERange(2, 10000000, false),
new ERange(2, 100000000, false),
new ERange(2, 1000000000, false)
)
for (rg <- rgs) {
if (rg.start == 2) {
println(s"eban numbers up to an including ${rg.end}")
} else {
println(s"eban numbers between ${rg.start} and ${rg.end}")
}
var count = 0
for (i <- rg.start to rg.end) {
val b = i / 1000000000
var r = i % 1000000000
var m = r / 1000000
r = i % 1000000
var t = r / 1000
r %= 1000
if (m >= 30 && m <= 66) {
m %= 10
}
if (t >= 30 && t <= 66) {
t %= 10
}
if (r >= 30 && r <= 66) {
r %= 10
}
if (b == 0 || b == 2 || b == 4 || b == 6) {
if (m == 0 || m == 2 || m == 4 || m == 6) {
if (t == 0 || t == 2 || t == 4 || t == 6) {
if (r == 0 || r == 2 || r == 4 || r == 6) {
if (rg.print) {
print(s"$i ")
}
count += 1
}
}
}
}
}
if (rg.print) {
println()
}
println(s"count = $count")
println()
}
}
}</syntaxhighlight>
{{out}}
<pre>eban numbers up to an including 1000
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers between 1000 and 4000
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to an including 10000
count = 79
eban numbers up to an including 100000
count = 399
eban numbers up to an including 1000000
count = 399
eban numbers up to an including 10000000
count = 1599
eban numbers up to an including 100000000
count = 7999
eban numbers up to an including 1000000000
count = 7999</pre>
=={{header|Tailspin}}==
<syntaxhighlight lang="tailspin">
templates isEban
def number: $;
'$;' -> \(<'([246]|[3456][0246])(0[03456][0246])*'> $ !\) -> $number !
end isEban
</syntaxhighlight>
Alternatively, if regex is not your thing, we can do it numerically, which actually runs faster
<syntaxhighlight lang="tailspin">
templates isEban
def number: $;
$ -> \(<1..> $!\) -> #
when <=0> do $number !
when <?($ mod 1000 <=0|=2|=4|=6|30..66?($ mod 10 <=0|=2|=4|=6>)>)> do $ ~/ 1000 -> #
end isEban
</syntaxhighlight>
Either version is called by the following code
<syntaxhighlight lang="tailspin">
def small: [1..1000 -> isEban];
$small -> !OUT::write
'
There are $small::length; eban numbers up to and including 1000
' -> !OUT::write
def next: [1000..4000 -> isEban];
$next -> !OUT::write
'
There are $next::length; eban numbers between 1000 and 4000 (inclusive)
' -> !OUT::write
'
There are $:[1..10000 -> isEban] -> $::length; eban numbers up to and including 10 000
' -> !OUT::write
'
There are $:[1..100000 -> isEban] -> $::length; eban numbers up to and including 100 000
' -> !OUT::write
'
There are $:[1..1000000 -> isEban] -> $::length; eban numbers up to and including 1 000 000
' -> !OUT::write
'
There are $:[1..10000000 -> isEban] -> $::length; eban numbers up to and including 10 000 000
' -> !OUT::write
</syntaxhighlight>
{{out}}
<pre>
[2, 4, 6, 30, 32, 34, 36, 40, 42, 44, 46, 50, 52, 54, 56, 60, 62, 64, 66]
There are 19 eban numbers up to and including 1000
[2000, 2002, 2004, 2006, 2030, 2032, 2034, 2036, 2040, 2042, 2044, 2046, 2050, 2052, 2054, 2056, 2060, 2062, 2064, 2066, 4000]
There are 21 eban numbers between 1000 and 4000 (inclusive)
There are 79 eban numbers up to and including 10 000
There are 399 eban numbers up to and including 100 000
There are 399 eban numbers up to and including 1 000 000
There are 1599 eban numbers up to and including 10 000 000
</pre>
=={{header|uBasic/4tH}}==
{{trans|Yabasic}}
<syntaxhighlight lang="qbasic">Push 2, 10^7, 0
Push 2, 10^6, 0
Push 2, 10^5, 0
Push 2, 10^4, 0
Push 1000, 4000, 1
Push 2, 1000, 1
z = XOR(NOT(0), 6)
Do While Used()
p = Pop() : e = Pop() : s = Pop()
If s = 2 Then
Print "eban numbers up to and including ";e
Else
Print "eban numbers between ";s;" and ";e;" (inclusive):"
EndIf
c = 0
For i = s To e Step 2
b = i / 1000000000
m = (i % 1000000000) / 1000000
r = i % 1000000
t = r / 1000
r = r % 1000
If ((m < 30) = 0) * ((m > 66) = 0) Then m = m % 10
If ((t < 30) = 0) * ((t > 66) = 0) Then t = t % 10
If ((r < 30) = 0) * ((r > 66) = 0) Then r = r % 10
If (AND(b, z) = 0) * (AND(m, z) = 0) * (AND(t, z) = 0) * (AND(r, z) = 0) Then
If p Then Print i;" "; : Fi
c = c + 1
EndIf
Next
If p Then Print
Print "count = ";c : Print
Loop</syntaxhighlight >
=={{header|Visual Basic .NET}}==
{{trans|D}}
<syntaxhighlight lang="vbnet">Module Module1
Structure Interval
Dim start As Integer
Dim last As Integer
Dim print As Boolean
Sub New(s As Integer, l As Integer, p As Boolean)
start = s
last = l
print = p
End Sub
End Structure
Sub Main()
Dim intervals As Interval() = {
New Interval(2, 1_000, True),
New Interval(1_000, 4_000, True),
New Interval(2, 10_000, False),
New Interval(2, 100_000, False),
New Interval(2, 1_000_000, False),
New Interval(2, 10_000_000, False),
New Interval(2, 100_000_000, False),
New Interval(2, 1_000_000_000, False)
}
For Each intv In intervals
If intv.start = 2 Then
Console.WriteLine("eban numbers up to and including {0}:", intv.last)
Else
Console.WriteLine("eban numbers between {0} and {1} (inclusive):", intv.start, intv.last)
End If
Dim count = 0
For i = intv.start To intv.last Step 2
Dim b = i \ 1_000_000_000
Dim r = i Mod 1_000_000_000
Dim m = r \ 1_000_000
r = i Mod 1_000_000
Dim t = r \ 1_000
r = r Mod 1_000
If m >= 30 AndAlso m <= 66 Then
m = m Mod 10
End If
If t >= 30 AndAlso t <= 66 Then
t = t Mod 10
End If
If r >= 30 AndAlso r <= 66 Then
r = r Mod 10
End If
If b = 0 OrElse b = 2 OrElse b = 4 OrElse b = 6 Then
If m = 0 OrElse m = 2 OrElse m = 4 OrElse m = 6 Then
If t = 0 OrElse t = 2 OrElse t = 4 OrElse t = 6 Then
If r = 0 OrElse r = 2 OrElse r = 4 OrElse r = 6 Then
If intv.print Then
Console.Write("{0} ", i)
End If
count += 1
End If
End If
End If
End If
Next
If intv.print Then
Console.WriteLine()
End If
Console.WriteLine("count = {0}", count)
Console.WriteLine()
Next
End Sub
End Module</syntaxhighlight>
{{out}}
<pre>eban numbers up to and including 1000:
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers between 1000 and 4000 (inclusive):
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to and including 10000:
count = 79
eban numbers up to and including 100000:
count = 399
eban numbers up to and including 1000000:
count = 399
eban numbers up to and including 10000000:
count = 1599
eban numbers up to and including 100000000:
count = 7999
eban numbers up to and including 1000000000:
count = 7999</pre>
=={{header|V (Vlang)}}==
{{trans|Go}}
<syntaxhighlight lang="v (vlang)">
struct Range {
start i64
end i64
print bool
}
fn main() {
rgs := [
Range{2, 1000, true},
Range{1000, 4000, true},
Range{2, 10000, false},
Range{2, 100000, false},
Range{2, 1000000, false},
Range{2, 10000000, false},
Range{2, 100000000, false},
Range{2, 1000000000, false}
]
for rg in rgs {
if rg.start == 2 {
println("eban numbers up to and including $rg.end:")
} else {
println("eban numbers between $rg.start and $rg.end (inclusive):")
}
mut count := 0
for i := rg.start; i <= rg.end; i += 2 {
b := i / 1000000000
mut r := i % 1000000000
mut m := r / 1000000
r = i % 1000000
mut t := r / 1000
r %= 1000
if m >= 30 && m <= 66 {
m %= 10
}
if t >= 30 && t <= 66 {
t %= 10
}
if r >= 30 && r <= 66 {
r %= 10
}
if b == 0 || b == 2 || b == 4 || b == 6 {
if m == 0 || m == 2 || m == 4 || m == 6 {
if t == 0 || t == 2 || t == 4 || t == 6 {
if r == 0 || r == 2 || r == 4 || r == 6 {
if rg.print {
print("$i ")
}
count++
}
}
}
}
}
if rg.print {
println('')
}
println("count = $count\n")
}
}</syntaxhighlight>
{{out}}
<pre>
eban numbers up to and including 1000:
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers between 1000 and 4000 (inclusive):
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to and including 10000:
count = 79
eban numbers up to and including 100000:
count = 399
eban numbers up to and including 1000000:
count = 399
eban numbers up to and including 10000000:
count = 1599
eban numbers up to and including 100000000:
count = 7999
eban numbers up to and including 1000000000:
count = 7999
</pre>
=={{header|Wren}}==
{{trans|Go}}
<syntaxhighlight lang="wren">var rgs = [
[2, 1000, true],
[1000, 4000, true],
[2, 1e4, false],
[2, 1e5, false],
[2, 1e6, false],
[2, 1e7, false],
[2, 1e8, false],
[2, 1e9, false]
]
for (rg in rgs) {
if (rg[0] == 2) {
System.print("eban numbers up to and including %(rg[1])")
} else {
System.print("eban numbers between %(rg[0]) and %(rg[1]) (inclusive):")
}
var count = 0
var i = rg[0]
while (i <= rg[1]) {
var b = (i/1e9).floor
var r = i % 1e9
var m = (r/1e6).floor
r = i % 1e6
var t = (r/1000).floor
r = r % 1000
if (m >= 30 && m <= 66) m = m % 10
if (t >= 30 && t <= 66) t = t % 10
if (r >= 30 && r <= 66) r = r % 10
if (b == 0 || b == 2 || b == 4 || b == 6) {
if (m == 0 || m == 2 || m == 4 || m == 6) {
if (t == 0 || t == 2 || t == 4 || t == 6) {
if (r == 0 || r == 2 || r == 4 || r == 6) {
if (rg[2]) System.write("%(i) ")
count = count + 1
}
}
}
}
i = i + 2
}
if (rg[2]) System.print()
System.print("count = %(count)\n")
}</syntaxhighlight>
{{out}}
<pre>
eban numbers up to and including 1000
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers between 1000 and 4000 (inclusive):
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to and including 10000
count = 79
eban numbers up to and including 100000
count = 399
eban numbers up to and including 1000000
count = 399
eban numbers up to and including 10000000
count = 1599
eban numbers up to and including 100000000
count = 7999
eban numbers up to and including 1000000000
count = 7999
</pre>
=={{header|XPL0}}==
{{trans|Wren}}
<syntaxhighlight lang "XPL0">include xpllib; \for Print
int Rgs, Rg, Count, I, B, R, M, T;
[Rgs:= [
[2, 1000, true],
[1000, 4000, true],
[2, 10000, false],
[2, 100000, false],
[2, 1000000, false],
[2, 10000000, false],
[2, 100000000, false],
[2, 1000000000, false] ];
for Rg:= 0 to 8-1 do
[if Rgs(Rg,0) = 2 then
Print("eban numbers up to and including %d\n", Rgs(Rg,1))
else
Print("eban numbers between %d and %d (inclusive):\n", Rgs(Rg,0), Rgs(Rg,1));
Count:= 0;
I:= Rgs(Rg,0);
while I <= Rgs(Rg,1) do
[B:= (I/1_000_000_000);
M:= rem(0) / 1_000_000;
T:= rem(0) / 1_000;
R:= rem(0);
if M >= 30 and M <= 66 then M:= rem(M/10);
if T >= 30 and T <= 66 then T:= rem(T/10);
if R >= 30 and R <= 66 then R:= rem(R/10);
if B = 0 or B = 2 or B = 4 or B = 6 then
if M = 0 or M = 2 or M = 4 or M = 6 then
if T = 0 or T = 2 or T = 4 or T = 6 then
if R = 0 or R = 2 or R = 4 or R = 6 then
[if Rgs(Rg,2) then Print("%d ", I);
Count:= Count+1;
];
I:= I+2;
];
if Rgs(Rg,2) then CrLf(0);
Print("count = %d\n", Count);
];
]</syntaxhighlight>
{{out}}
<pre>
eban numbers up to and including 1000
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers between 1000 and 4000 (inclusive):
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to and including 10000
count = 79
eban numbers up to and including 100000
count = 399
eban numbers up to and including 1000000
count = 399
eban numbers up to and including 10000000
count = 1599
eban numbers up to and including 100000000
count = 7999
eban numbers up to and including 1000000000
count = 7999
</pre>
=={{header|Yabasic}}==
{{trans|Go}}
<syntaxhighlight lang="yabasic">data 2, 100, true
data 1000, 4000, true
data 2, 1e4, false
data 2, 1e5, false
data 2, 1e6, false
data 2, 1e7, false
data 2, 1e8, false
REM data 2, 1e9, false // it takes a lot of time
data 0, 0, false
do
read start, ended, printable
if not start break
if start = 2 then
Print "eban numbers up to and including ", ended
else
Print "eban numbers between ", start, " and ", ended, " (inclusive):"
endif
count = 0
for i = start to ended step 2
b = int(i / 1000000000)
r = mod(i, 1000000000)
m = int(r / 1000000)
r = mod(i, 1000000)
t = int(r / 1000)
r = mod(r, 1000)
if m >= 30 and m <= 66 m = mod(m, 10)
if t >= 30 and t <= 66 t = mod(t, 10)
if r >= 30 and r <= 66 r = mod(r, 10)
if b = 0 or b = 2 or b = 4 or b = 6 then
if m = 0 or m = 2 or m = 4 or m = 6 then
if t = 0 or t = 2 or t = 4 or t = 6 then
if r = 0 or r = 2 or r = 4 or r = 6 then
if printable Print i;
count = count + 1
endif
endif
endif
endif
next
if printable Print
Print "count = ", count, "\n"
loop</syntaxhighlight>
=={{header|zkl}}==
{{trans|Go}}
<syntaxhighlight lang="zkl">rgs:=T( T(2, 1_000, True), // (start,end,print)
T(1_000, 4_000, True),
T(2, 1e4, False), T(2, 1e5, False), T(2, 1e6, False), T(2, 1e7, False),
T(2, 1e8, False), T(2, 1e9, False), // slow and very slow
);
foreach start,end,pr in (rgs){
if(start==2) println("eban numbers up to and including %,d:".fmt(end));
else println("eban numbers between %,d and %,d (inclusive):".fmt(start,end));
count:=0;
foreach i in ([start..end,2]){
b,r := i/100_0000_000, i%1_000_000_000;
m,r := r/1_000_000, i%1_000_000;
t,r := r/1_000, r%1_000;
if(30<=m<=66) m=m%10;
if(30<=t<=66) t=t%10;
if(30<=r<=66) r=r%10;
if(magic(b) and magic(m) and magic(t) and magic(r)){
if(pr) print(i," ");
count+=1;
}
}
if(pr) println();
println("count = %,d\n".fmt(count));
}
fcn magic(z){ z.isEven and z<=6 }</syntaxhighlight>
{{out}}
<pre style="height:35ex">
eban numbers up to and including 1,000:
2 4 6 30 32 34 36 40 42 44 46 50 52 54 56 60 62 64 66
count = 19
eban numbers between 1,000 and 4,000 (inclusive):
2000 2002 2004 2006 2030 2032 2034 2036 2040 2042 2044 2046 2050 2052 2054 2056 2060 2062 2064 2066 4000
count = 21
eban numbers up to and including 10,000:
count = 79
eban numbers up to and including 100,000:
count = 399
eban numbers up to and including 1,000,000:
count = 399
eban numbers up to and including 10,000,000:
count = 1,599
eban numbers up to and including 100,000,000:
count = 7,999
eban numbers up to and including 1,000,000,000:
count = 7,999
</pre>
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