EKG sequence convergence: Difference between revisions

Added solution for Action!
m (→‎{{header|Haskell}}: Applied Ormolu, tidied.)
(Added solution for Action!)
Line 82:
EKG(10): 1, 10, 2, 4, 6, 3, 9, 12, 8, 14
EKG(5) and EKG(7) converge at index 21.
</pre>
 
=={{header|Action!}}==
{{libheader|Action! Tool Kit}}
<lang Action!>INCLUDE "D2:SORT.ACT" ;from the Action! Tool Kit
 
BYTE FUNC Contains(BYTE ARRAY a BYTE len,b)
BYTE i
 
IF len=0 THEN
RETURN (0)
FI
FOR i=0 TO len-1
DO
IF a(i)=b THEN
RETURN (1)
FI
OD
RETURN (0)
 
BYTE FUNC Gcd(BYTE a,b)
BYTE tmp
 
IF a<b THEN
tmp=a a=b b=tmp
FI
 
WHILE b#0
DO
tmp=a MOD b
a=b b=tmp
OD
RETURN (a)
 
BYTE FUNC AreSame(BYTE ARRAY a,b BYTE len)
BYTE i
 
IF len=0 THEN
RETURN (1)
FI
 
SortB(a,len,0)
SortB(b,len,0)
FOR i=0 TO len-1
DO
IF a(i)#b(i) THEN
RETURN (0)
FI
OD
RETURN (1)
 
PROC CalcEkg(BYTE start,limit BYTE ARRAY ekg)
BYTE len,i
 
ekg(0)=1 ekg(1)=start
FOR len=2 TO limit-1
DO
i=2
DO
IF Contains(ekg,len,i)=0 AND Gcd(ekg(len-1),i)>1 THEN
ekg(len)=i
EXIT
FI
i==+1
OD
OD
RETURN
 
BYTE FUNC CalcConvergence(BYTE ARRAY a,b BYTE len)
BYTE i
 
FOR i=2 TO len-1
DO
IF a(i)=b(i) AND AreSame(a,b,i)=1 THEN
RETURN (i+1)
FI
OD
RETURN (0)
 
PROC PrintSeq(BYTE start BYTE ARRAY ekg BYTE len)
BYTE i
 
PrintF("EKG(%B)=",start)
FOR i=0 TO len-1
DO
IF i>0 THEN Put(32) FI
PrintB(ekg(i))
OD
PrintE("...")
RETURN
 
PROC Main()
DEFINE LIMIT="100"
DEFINE SEQCOUNT="5"
DEFINE PART="10"
DEFINE EKG1="1"
DEFINE EKG2="2"
BYTE ARRAY buf(500),starts=[2 5 7 9 10]
CARD ARRAY ekg(SEQCOUNT)
BYTE i,conv
 
Put(125) PutE() ;clear the screen
 
FOR i=0 TO SEQCOUNT-1
DO
ekg(i)=buf+LIMIT*i
CalcEkg(starts(i),LIMIT,ekg(i))
PrintSeq(starts(i),ekg(i),PART)
OD
 
conv=CalcConvergence(ekg(EKG1),ekg(EKG2),LIMIT)
PrintF("%EEKG(%B) and EKG(%B) ",starts(EKG1),starts(EKG2))
IF conv=0 THEN
PrintF("do not converge within %B items",LIMIT)
ELSE
PrintF("converge at index %B",conv)
FI
RETURN</lang>
{{out}}
[https://gitlab.com/amarok8bit/action-rosetta-code/-/raw/master/images/EKG_sequence_convergence.png Screenshot from Atari 8-bit computer]
<pre>
EKG(2)=1 2 4 6 3 9 12 8 10 5...
EKG(5)=1 5 10 2 4 6 3 9 12 8...
EKG(7)=1 7 14 2 4 6 3 9 12 8...
EKG(9)=1 9 3 6 2 4 8 10 5 15...
EKG(10)=1 10 2 4 6 3 9 12 8 14...
 
EKG(5) and EKG(7) converge at index 21
</pre>
 
Anonymous user