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Dinesman's multiple-dwelling problem: Difference between revisions
Dinesman's multiple-dwelling problem (view source)
Revision as of 17:50, 25 June 2011
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auto c3 = (int[] s){ return s[Fletcher] != 0 && s[Fletcher] != s.length-1; };
auto c4 = (int[] s){ return s[Miller] > s[Cooper]; };
auto c5 = (int[] s){ return abs(s[
auto c6 = (int[] s){ return abs(s[
if (auto sol = solve(Floors, c1, c2, c3, c4, c5, c6))
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