Dinesman's multiple-dwelling problem: Difference between revisions
m
→Using Amp function
Line 2,611:
if Baker=Cooper or Baker=Fletcher or Baker=Miller or Baker=Smith then =true:exit
if Cooper=Fletcher or Cooper =Miller or Cooper=Smith then =true:exit
if Fletcher=Miller or Fletcher=Smith or Miller=Smith then
if Miller<Cooper or abs(Cooper-Fletcher)=1 or
}
all=amb(Any, failure, Baker, Cooper, Fletcher, Miller, Smith)
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