Dinesman's multiple-dwelling problem: Difference between revisions

function notAdjacent(Integer a, Integer b) => (a - b).magnitude >= 2;

function allDifferent(Integer* ints) => ints.distinct.size == ints.size;

value solutionsolutions = [

for (baker in 1..4)

for (cooper in 2..5)

for (fletcher in 2..4)

for (miller in 2..5)

for (smith in 1..5)

if (miller > cooper &&

notAdjacent(smith, fletcher) &&

notAdjacent(fletcher, cooper) &&

allDifferent(baker, cooper, fletcher, miller, smith))

"baker lives on ``baker``

cooper lives on ``cooper``

fletcher lives on ``fletcher``

miller lives on ``miller``

smith lives on ``smith``"

];

print(solutions.first else "No solution.each(print!");