Dinesman's multiple-dwelling problem: Difference between revisions

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@@ Line 1,336: / Line 1,336: @@
 ===Simpler Version===
-<syntaxhighlight lang="d">void main() {
+<syntaxhighlight lang="d">
+void main() {
-    import std.stdio, std.math, std.algorithm, permutations2;
+    import std.stdio, std.math, std.algorithm, permutations2:permutations;
     ["Baker", "Cooper", "Fletcher", "Miller", "Smith"]
-    .permutations
+ 	.permutations
-    .filter!(s =>
+ 	.filter!(s =>
-        s.countUntil("Baker") != 4 && s.countUntil("Cooper") &&
+        s.countUntil("Baker") != 4 && s.countUntil("Cooper")  != 0  &&
-        s.countUntil("Fletcher") && s.countUntil("Fletcher") != 4 &&
+        s.countUntil("Fletcher") != 0 && s.countUntil("Fletcher") != 4 &&
         s.countUntil("Miller") > s.countUntil("Cooper") &&
         abs(s.countUntil("Smith") - s.countUntil("Fletcher")) != 1 &&
         abs(s.countUntil("Cooper") - s.countUntil("Fletcher")) != 1)
-    .writeln;
+	.writeln;
 }</syntaxhighlight>
 The output is the same.