Dijkstra's algorithm: Difference between revisions
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=={{header|Tcl}}== |
=={{header|Tcl}}== |
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This solution is incorrect. Since the path is directed and f is only a sink, f cannot be in the middle of a path. |
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Note that this code traverses the entire set of unrouted nodes at each step, as this is simpler than computing the subset that are reachable at each stage. |
Note that this code traverses the entire set of unrouted nodes at each step, as this is simpler than computing the subset that are reachable at each stage. |
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<lang tcl>proc dijkstra {graph origin} { |
<lang tcl>proc dijkstra {graph origin} { |
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