Determine if a string has all unique characters: Difference between revisions

Content added Content deleted
No edit summary
Line 2,171: Line 2,171:
if (numelems([index]) > 1) then
if (numelems([index]) > 1) then
printf("The given string has duplicated characters.\n");
printf("The given string has duplicated characters.\n");
printf("The first duplicated character is %a (0x%x) which appears at index %a.\n",
printf("The first duplicated character is %a (0x%x) which appears at index %a.\n\n",
s[i], convert(s[i], 'bytes')[1], {index});
s[i], convert(s[i], 'bytes')[1], {index});
return;
return;
Line 2,177: Line 2,177:
end do;
end do;
# if no repeated found
# if no repeated found
printf("The given string has all unique characters.\n");
printf("The given string has all unique characters.\n\n");
end proc:
end proc:


Line 2,190: Line 2,190:
input: "", length: 0
input: "", length: 0
The given string has all unique characters.
The given string has all unique characters.

input: ".", length: 1
input: ".", length: 1
The given string has all unique characters.
The given string has all unique characters.

input: "abcABC", length: 6
input: "abcABC", length: 6
The given string has all unique characters.
The given string has all unique characters.

input: "XYZ ZYX", length: 7
input: "XYZ ZYX", length: 7
The given string has duplicated characters.
The given string has duplicated characters.
The first duplicated character is "X" (0x58) which appears at index {1, 7}.
The first duplicated character is "X" (0x58) which appears at index {1, 7}.

input: "1234567890ABCDEFGHIJKLMN0PQRSTUVWXYZ", length: 36
input: "1234567890ABCDEFGHIJKLMN0PQRSTUVWXYZ", length: 36
The given string has duplicated characters.
The given string has duplicated characters.
Retrieved from "https://rosettacode.org/wiki/Determine_if_a_string_has_all_unique_characters"