Determine if a string has all unique characters: Difference between revisions
Determine if a string has all unique characters (view source)
Revision as of 00:01, 14 March 2020
, 4 years ago→{{header|Nanoquery}}
Line 1,607:
🐠🐟🐡🦈🐬🐳🐋🐡 8 no 🐡 (1f421) 3 8
</pre>
=={{header|Kotlin}}==
{{trans|Java}}
<lang scala>import java.util.HashMap
fun main() {
System.out.printf("%-40s %2s %10s %8s %s %s%n", "String", "Length", "All Unique", "1st Diff", "Hex", "Positions")
System.out.printf("%-40s %2s %10s %8s %s %s%n", "------------------------", "------", "----------", "--------", "---", "---------")
for (s in arrayOf("", ".", "abcABC", "XYZ ZYX", "1234567890ABCDEFGHIJKLMN0PQRSTUVWXYZ")) {
processString(s)
}
}
private fun processString(input: String) {
val charMap: MutableMap<Char, Int?> = HashMap()
var dup = 0.toChar()
var index = 0
var pos1 = -1
var pos2 = -1
for (key in input.toCharArray()) {
index++
if (charMap.containsKey(key)) {
dup = key
pos1 = charMap[key]!!
pos2 = index
break
}
charMap[key] = index
}
val unique = if (dup.toInt() == 0) "yes" else "no"
val diff = if (dup.toInt() == 0) "" else "'$dup'"
val hex = if (dup.toInt() == 0) "" else Integer.toHexString(dup.toInt()).toUpperCase()
val position = if (dup.toInt() == 0) "" else "$pos1 $pos2"
System.out.printf("%-40s %-6d %-10s %-8s %-3s %-5s%n", input, input.length, unique, diff, hex, position)
}</lang>
{{out}}
<pre>String Length All Unique 1st Diff Hex Positions
------------------------ ------ ---------- -------- --- ---------
0 yes
. 1 yes
abcABC 6 yes
XYZ ZYX 7 no 'Z' 5A 3 5
1234567890ABCDEFGHIJKLMN0PQRSTUVWXYZ 36 no '0' 30 10 25</pre>
=={{header|Nanoquery}}==
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