Day of the week of Christmas and New Year: Difference between revisions
Day of the week of Christmas and New Year (view source)
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<br>
Determine programatically and show on this page on what weekday Christmas Day, 2021 and New Year's Day, 2022 will fall or did fall.
=={{header|11l}}==
{{trans|Python}}
<syntaxhighlight lang="11l">V weekDays = [‘Sunday’, ‘Monday’, ‘Tuesday’, ‘Wednesday’, ‘Thursday’, ‘Friday’, ‘Saturday’]
V thisXMas = Time(2021, 12, 25)
V thisXMasDay = Int(thisXMas.strftime(‘%w’))
V thisXMasDayAsString = weekDays[thisXMasDay]
print(‘This year's Christmas is on a ’thisXMasDayAsString)
V nextNewYear = Time(2022, 1, 1)
V nextNewYearDay = Int(nextNewYear.strftime(‘%w’))
V nextNewYearDayAsString = weekDays[nextNewYearDay]
print(‘Next new year is on a ’nextNewYearDayAsString)</syntaxhighlight>
{{out}}
<pre>
This year's Christmas is on a Saturday
Next new year is on a Saturday
</pre>
=={{header|Ada}}==
<syntaxhighlight lang="ada">with Ada.Text_Io;
with Ada.Calendar.Formatting;
procedure Weekdays is
use Ada.Text_Io;
use Ada.Calendar.Formatting;
subtype Time is Ada.Calendar.Time;
procedure Info (Date : Time) is
begin
Put (Image (Date));
Put (" is a ");
Put (Day_Name'Image (Day_Of_Week (Date)));
Put (".");
New_Line;
end Info;
Christmas_Day : constant Time := Time_Of (Year => 2021, Month => 12, Day => 25);
New_Years_Day : constant Time := Time_Of (Year => 2022, Month => 01, Day => 01);
begin
Info (Christmas_Day);
Info (New_Years_Day);
end Weekdays;</syntaxhighlight>
{{out}}
<pre>
2021-12-25 00:00:00 is a SATURDAY.
2022-01-01 00:00:00 is a SATURDAY.
</pre>
=={{header|ALGOL 68}}==
{{Trans|ALGOL W}}
<syntaxhighlight lang="algol68">
BEGIN # find the day of the week 25/12/2021 and 01/01/2022 fall on #
[]STRING day name =
[]STRING( "Saturday", "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday" )[ AT 0 ];
PROC day of week = ( INT d, m, y )INT:
BEGIN
INT mm := m;
INT yy := y;
IF mm <= 2 THEN
mm +:= 12;
yy -:= 1
FI;
INT j = yy OVER 100;
INT k = yy MOD 100;
( d + ( ( mm + 1 ) * 26 ) OVER 10 + k + k OVER 4 + j OVER 4 + 5 * j ) MOD 7
END # day of week # ;
print( ( "25th of December 2021 is a ", day name[ day of week( 25, 12, 2021 ) ], newline ) );
print( ( " 1st of January 2022 is a ", day name[ day of week( 1, 1, 2022 ) ], newline ) )
END
</syntaxhighlight>
{{out}}
<pre>
25th of December 2021 is a Saturday
1st of January 2022 is a Saturday
</pre>
=={{header|ALGOL W}}==
Re-using code from the [[Day of the week]] task.
<
string(10) array dayName( 0 :: 6 );
integer procedure Day_of_week ( integer value d, m, y );
Line 27 ⟶ 107:
write( "25th of December 2021 is a ", dayName( Day_of_week( 25, 12, 2021 ) ) );
write( " 1st of January 2022 is a ", dayName( Day_of_week( 1, 1, 2022 ) ) )
end.</
{{out}}
<pre>
Line 33 ⟶ 113:
1st of January 2022 is a Saturday
</pre>
=={{header|AutoHotkey}}==
<syntaxhighlight lang="autohotkey">FormatTime, xmas , 20211225, dddd
FormatTime, newYear , 20220101, dddd
MsgBox % result := "Christmas Day, 2021 : " xmas "`nNew Year's Day, 2022 : " newYear</syntaxhighlight>
{{out}}
<pre>Christmas Day, 2021 : Saturday
New Year's Day, 2022 : Saturday</pre>
=={{header|AWK}}==
<syntaxhighlight lang="awk">
# syntax: GAWK -f WHAT_WEEKDAYS_WILL_CHRISTMAS_AND_NEW_YEAR.AWK
BEGIN {
Line 47 ⟶ 135:
exit(0)
}
</syntaxhighlight>
{{out}}
<pre>
Line 55 ⟶ 143:
25 Dec 2021 is Saturday
01 Jan 2022 is Saturday
</pre>
=={{header|BASIC}}==
<syntaxhighlight lang="gwbasic">10 DEFINT A-Z
20 DIM D$(6)
30 FOR I=0 TO 6: READ D$(I): NEXT
40 FOR I=1 TO 2
50 READ Y,M,D
60 PRINT USING "##/##/#### is a ";M;D;Y;
70 IF M<=2 THEN M=M+12: Y=Y-1
80 J=Y\100
90 K=Y MOD 100
100 D=(D+((M+1)*26)\10+K+K\4+J\4+5*J) MOD 7
110 PRINT D$(D)
120 NEXT
130 DATA Saturday,Sunday,Monday,Tuesday,Wednesday,Thursday,Friday
140 DATA 2021,12,25
150 DATA 2022,1,1</syntaxhighlight>
{{out}}
<pre>12/25/2021 is a Saturday
1/ 1/2022 is a Saturday</pre>
==={{header|BASIC256}}===
<syntaxhighlight lang="freebasic">print "Christmas Day 2021 is on a "; diasemana$(2021, 12, 25)
print "New Year's Day 2022 is on a "; diasemana$(2022, 1, 1)
end
function diasemana$(anno, mes, dia)
dim nombre$(6)
nombre$ = {"Saturday", "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday"}
if mes <= 2 then
mes += 12
anno -= 1
end if
dia = (dia-1 + ((mes+1)*26)\10 + anno + anno\4 + anno\400 + anno*6\100) mod 7
return nombre$[dia]
end function</syntaxhighlight>
==={{header|Chipmunk Basic}}===
{{works with|Chipmunk Basic|3.6.4}}
{{works with|QBasic}}
{{trans|QBasic}}
<syntaxhighlight lang="qbasic">100 REM Day of the week of Christmas and New Year
110 CLS
120 DIM d$(6)
130 FOR i = 0 TO 6 : READ d$(i) : NEXT i
140 FOR i = 1 TO 2
150 READ y,m,d
160 PRINT m;"/";d;"/";y;" is a ";
170 IF m <= 2 THEN LET m = m+12 : LET y = y-1
180 LET j = INT(y/100)
190 LET k = y-INT(y/100)*100
200 LET t = (d+INT((m+1)*26)/10+k+k/4+j/4+5*j)
210 LET d = t-INT(t/7)*7
211 rem LET d = INT(d + ((m + 1) * 26) / 10 + K + K / 4 + J \ 4 + 5 * J) MOD 7
220 PRINT d$(d)
230 NEXT i
240 DATA "Saturday","Sunday","Monday","Tuesday","Wednesday","Thursday","Friday"
250 DATA 2021,12,25
260 DATA 2022,1,1
270 END</syntaxhighlight>
==={{header|GW-BASIC}}===
{{works with|PC-BASIC|any}}
{{works with|MSX BASIC}}
{{works with|QBasic}}
{{trans|QBasic}}
<syntaxhighlight lang="qbasic">100 REM Day of the week of Christmas and New Year
110 CLS
120 DIM d$(6)
130 FOR i = 0 TO 6: READ d$(i): NEXT i
140 FOR i = 1 TO 2
150 READ y, m, d
160 PRINT USING "##/##/#### is a "; m; d; y;
170 IF m <= 2 THEN m = m + 12: y = y - 1
180 j = y \ 100
190 k = y MOD 100
200 d = (d + ((m + 1) * 26) \ 10 + k + k \ 4 + j \ 4 + 5 * j) MOD 7
210 PRINT d$(d)
220 NEXT i
230 DATA Saturday, Sunday, Monday, Tuesday, Wednesday, Thursday, Friday
240 DATA 2021, 12, 25
250 DATA 2022, 1, 1
260 END</syntaxhighlight>
==={{header|MSX Basic}}===
The [[#GW-BASIC|GW-BASIC]] solution works without any changes.
==={{header|QBasic}}===
{{works with|QBasic|1.1}}
{{works with|QuickBasic|4.5}}
<syntaxhighlight lang="qbasic">DIM d$(6)
FOR i = 0 TO 6: READ d$(i): NEXT i
FOR i = 1 TO 2
READ y, m, d
PRINT USING "##/##/#### is a "; m; d; y;
IF m <= 2 THEN m = m + 12: y = y - 1
J = y \ 100
K = y MOD 100
d = (d + ((m + 1) * 26) \ 10 + K + K \ 4 + J \ 4 + 5 * J) MOD 7
PRINT d$(d)
NEXT i
DATA Saturday, Sunday, Monday, Tuesday, Wednesday, Thursday, Friday
DATA 2021, 12, 25
DATA 2022, 1, 1
END</syntaxhighlight>
==={{header|True BASIC}}===
<syntaxhighlight lang="qbasic">OPTION BASE 0
DIM d$(6)
FOR i = 0 TO 6
READ d$(i)
NEXT i
FOR i = 1 TO 2
READ y, m, d
PRINT USING "##/##/#### is a ": m, d, y;
IF m <= 2 THEN
LET m = m+12
LET y = y-1
END IF
LET j = IP(round(y)/100)
LET k = REMAINDER(ROUND(y),100)
LET d = REMAINDER(ROUND((d+IP(ROUND(((m+1)*26))/10)+k+IP(ROUND(k)/4)+IP(ROUND(j)/4)+5*j)),7)
PRINT d$(d)
NEXT i
DATA Saturday, Sunday, Monday, Tuesday, Wednesday, Thursday, Friday
DATA 2021, 12, 25
DATA 2022, 1, 1
END</syntaxhighlight>
==={{header|XBasic}}===
{{works with|Windows XBasic}}
<syntaxhighlight lang="xbasic">PROGRAM "progname"
VERSION "0.0000"
DECLARE FUNCTION Entry ()
FUNCTION Entry ()
DIM d$[6]
d$[0] = "Saturday"
d$[1] = "Sunday"
d$[2] = "Monday"
d$[3] = "Tuesday"
d$[4] = "Wednesday"
d$[5] = "Thursday"
d$[6] = "Friday"
y = 2021: m = 12: d = 25
FOR i = 1 TO 2
PRINT d; " /"; m; " /"; y; " is a ";
IF m <= 2 THEN m = m + 12: y = y - 1
J = y \ 100
K = y MOD 100
d = (d + ((m + 1) * 26) \ 10 + K + K \ 4 + J \ 4 + 5 * J) MOD 7
PRINT d$[d]
y = 2022: m = 1: d = 1
NEXT i
END FUNCTION
END PROGRAM</syntaxhighlight>
==={{header|Yabasic}}===
<syntaxhighlight lang="yabasic">dim nombre$(6)
nombre$(0) = "Saturday"
nombre$(1) = "Sunday"
nombre$(2) = "Monday"
nombre$(3) = "Tuesday"
nombre$(4) = "Wednesday"
nombre$(5) = "Thursday"
nombre$(6) = "Friday"
print "Christmas Day 2021 is on a ", diasemana$(2021, 12, 25)
print "New Year's Day 2022 is on a ", diasemana$(2022, 1, 1)
end
sub diasemana$(anno, mes, dia)
if mes <= 2 then
mes = mes + 12
anno = anno - 1
fi
dia = mod((dia-1 + int(((mes+1)*26)/10) + anno + int(anno/4) + int(anno/400) + int(anno*6/100)), 7)
return nombre$(dia)
end sub</syntaxhighlight>
=={{header|BCPL}}==
<syntaxhighlight lang="bcpl">get "libhdr"
let dayofweek(y,m,d) = valof
$( let j, k = ?, ?
if m<=2
$( m := m+12
y := y-1
$)
j := y/100
k := y rem 100
d := (d + ((m+1)*26)/10 + k + k/4 + j/4 + 5*j) rem 7
switchon d into
$( case 0: resultis "Saturday"
case 1: resultis "Sunday"
case 2: resultis "Monday"
case 3: resultis "Tuesday"
case 4: resultis "Wednesday"
case 5: resultis "Thursday"
case 6: resultis "Friday"
$)
$)
let show(y,m,d) be
writef("%N/%N/%N is a %S*N", m, d, y, dayofweek(y, m, d))
let start() be
$( show(2021,12,25)
show(2022,1,1)
$)</syntaxhighlight>
{{out}}
<pre>12/25/2021 is a Saturday
1/1/2022 is a Saturday</pre>
=={{header|C}}==
<syntaxhighlight lang="c">#define _XOPEN_SOURCE
#include <stdio.h>
#include <time.h>
int main() {
struct tm t[2];
strptime("2021-12-25", "%F", &t[0]);
strptime("2022-01-01", "%F", &t[1]);
for (int i=0; i<2; i++) {
char buf[32];
strftime(buf, 32, "%F is a %A", &t[i]);
puts(buf);
}
return 0;
}</syntaxhighlight>
{{out}}
<pre>2021-12-25 is a Saturday
2022-01-01 is a Saturday</pre>
=={{header|CLU}}==
<syntaxhighlight lang="clu">day_of_week = proc (d: date) returns (string)
own days: array[string] := array[string]$
[0:"Saturday", "Sunday", "Monday", "Tuesday",
"Wednesday", "Thursday", "Friday"]
m: int := d.month
y: int := d.year
if m <= 2 then
m := m + 12
y := y - 1
end
j: int := y/100
k: int := y//100
dn: int := (d.day + ((m+1)*26)/10 + k + k/4 + j/4 + 5*j)//7
return(days[dn])
end day_of_week
start_up = proc ()
po: stream := stream$primary_output()
days: array[date] := array[date]$
[date$create(25, 12, 2021, 0, 0, 0),
date$create( 1, 1, 2022, 0, 0, 0)]
for d: date in array[date]$elements(days) do
stream$putl(po, date$unparse_date(d) || " is a " || day_of_week(d))
end
end start_up</syntaxhighlight>
{{out}}
<pre>25 December 2021 is a Saturday
1 January 2022 is a Saturday</pre>
=={{header|COBOL}}==
<syntaxhighlight lang="cobol"> IDENTIFICATION DIVISION.
PROGRAM-ID. XMASNY.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 WEEKDAYS.
03 DAY-NAMES.
05 FILLER PIC X(9) VALUE "Saturday ".
05 FILLER PIC X(9) VALUE "Sunday ".
05 FILLER PIC X(9) VALUE "Monday ".
05 FILLER PIC X(9) VALUE "Tuesday ".
05 FILLER PIC X(9) VALUE "Wednesday".
05 FILLER PIC X(9) VALUE "Thursday ".
05 FILLER PIC X(9) VALUE "Friday ".
03 DAYS PIC X(9) OCCURS 7 TIMES,
REDEFINES DAY-NAMES.
01 OUT-FMT.
03 OUT-MONTH PIC 99.
03 FILLER PIC X VALUE "/".
03 OUT-DAY PIC 99.
03 FILLER PIC X VALUE "/".
03 OUT-YEAR PIC 9(4).
03 FILLER PIC X(6) VALUE " is a ".
03 OUT-DAYNAME PIC X(9).
01 VARIABLES.
03 CDATE.
05 D-MONTH PIC 99.
05 D-DAY PIC 99.
05 D-YEAR PIC 9999.
03 ZELLER-DATA.
05 M PIC 99.
05 Y PIC 99.
05 D PIC 999.
05 D7 PIC 999.
05 J PIC 99.
05 K PIC 99.
05 DAY-NAME PIC X(9).
PROCEDURE DIVISION.
BEGIN.
MOVE "25122021" TO CDATE.
PERFORM SHOW-WEEKDAY.
MOVE "01012022" TO CDATE.
PERFORM SHOW-WEEKDAY.
STOP RUN.
SHOW-WEEKDAY.
MOVE D-MONTH TO OUT-MONTH.
MOVE D-DAY TO OUT-DAY.
MOVE D-YEAR TO OUT-YEAR.
PERFORM ZELLER.
MOVE DAY-NAME TO OUT-DAYNAME.
DISPLAY OUT-FMT.
ZELLER.
MOVE D-MONTH TO M.
MOVE D-YEAR TO Y.
IF M IS NOT GREATER THAN 2,
ADD 12 TO M,
SUBTRACT 1 FROM Y.
DIVIDE Y BY 100 GIVING J.
COMPUTE K = Y - J * 100.
COMPUTE D = (M + 1) * 26.
DIVIDE 10 INTO D.
ADD K TO D.
DIVIDE 4 INTO K.
ADD K TO D.
COMPUTE D = D + 5 * J.
DIVIDE 4 INTO J.
COMPUTE D = D + J + D-DAY.
DIVIDE D BY 7 GIVING D7.
MULTIPLY 7 BY D7.
COMPUTE D = D - D7 + 1.
MOVE DAYS(D) TO DAY-NAME.</syntaxhighlight>
{{out}}
<pre>25/12/2021 is a Saturday
01/01/2022 is a Saturday</pre>
=={{header|Cowgol}}==
<syntaxhighlight lang="cowgol">include "cowgol.coh";
record Date is
year: uint16;
month: uint8;
day: uint8;
end record;
sub DayName(date: [Date]): (name: [uint8]) is
var days: [uint8][] := {
"Saturday", "Sunday", "Monday", "Tuesday",
"Wednesday", "Thursday", "Friday"
};
var m := date.month as uint16;
var y := date.year;
var d := date.day as uint16;
if m <= 2 then
m := m + 12;
y := y - 1;
end if;
var j := y / 100;
var k := y % 100;
d := (d + ((m+1)*26)/10 + k + k/4 + j/4 + 5*j) % 7;
name := days[d as @indexof days];
end sub;
sub printDate(date: [Date]) is
print_i8(date.month);
print_char('/');
print_i8(date.day);
print_char('/');
print_i16(date.year);
end sub;
var dates: Date[] := {
{2021, 25, 12},
{2022, 1, 1}
};
var i: @indexof dates := 0;
while i < @sizeof dates loop
printDate(&dates[i]);
print(" is a ");
print(DayName(&dates[i]));
print_nl();
i := i + 1;
end loop;</syntaxhighlight>
{{out}}
<pre>25/12/2021 is a Saturday
1/1/2022 is a Saturday</pre>
=={{header|Delphi}}==
{{works with|Delphi|6.0}}
{{libheader|Controls,SysUtils,StdCtrls}}
Delphi libraries make this easy.
<syntaxhighlight lang="Delphi">
procedure DoChristmasNewYear(Memo: TMemo);
var D: TDate;
begin
D:=EncodeDate(2021,12,25);
Memo.Lines.Add(FormatDateTime('"Christmas Day, 2021 is on: " dddd ', D));
D:=EncodeDate(2022,1,1);
Memo.Lines.Add(FormatDateTime('"New Years Day, 2022 is on: " dddd ', D));
end;
</syntaxhighlight>
{{out}}
<pre>
Christmas Day, 2021 is on: Saturday
New Years Day, 2022 is on: Saturday
</pre>
=={{header|Draco}}==
<syntaxhighlight lang="draco">type Date = struct {
word year;
byte month, day
};
proc nonrec day_name(Date date) *char:
word m, y, d, j, k;
m := date.month;
y := date.year;
d := date.day;
if m <= 2 then
m := m + 12;
y := y - 1
fi;
j := y / 100;
k := y % 100;
d := (d + ((m+1)*26)/10 + k + (k>>2) + (j>>2) + 5*j) % 7;
case d
incase 0: "Saturday"
incase 1: "Sunday"
incase 2: "Monday"
incase 3: "Tuesday"
incase 4: "Wednesday"
incase 5: "Thursday"
incase 6: "Friday"
esac
corp
proc nonrec print_date(Date d) void:
write(d.month, '/', d.day, '/', d.year)
corp
proc nonrec main() void:
[2] Date dates = ((2021, 12, 25), (2022, 1, 1));
byte i;
for i from 0 upto 1 do
print_date(dates[i]);
writeln(" is a ", day_name(dates[i]))
od
corp</syntaxhighlight>
{{out}}
<pre>12/25/2021 is a Saturday
1/1/2022 is a Saturday</pre>
=={{header|EasyLang}}==
<syntaxhighlight lang="easylang">
func dayOfTheWeek year month day .
# Based on Conway's doomsday algorithm
century = floor (year / 100)
if century mod 4 = 0
centuryDoomsday = 2
elif century mod 4 = 1
centuryDoomsday = 0
elif century mod 4 = 2
centuryDoomsday = 5
elif century mod 4 = 3
centuryDoomsday = 3
.
mainYear = year mod 100
yearDoomsday = (floor (mainYear / 12) + mainYear mod 12 + floor (mainYear mod 12 / 4) + centuryDoomsday) mod 7
if mainYear = 0
if century mod 4 = 0
leap = 1
else
leap = 0
.
else
if mainYear mod 4 = 0
leap = 1
else
leap = 0
.
.
if leap = 1
januaryOne = (yearDoomsday + 4) mod 7
else
januaryOne = (yearDoomsday + 5) mod 7
.
monthDays[] = [ 0 31 59 90 120 151 181 212 243 273 304 334 ]
nthDay = monthDays[month]
if month > 2
nthDay += leap
.
nthDay += day
return (januaryOne + nthDay - 1) mod 7 + 1
.
days$[] = [ "Sunday" "Monday" "Tuesday" "Wednesday" "Thursday" "Friday" "Saturday" ]
#
print "2021-12-25 is on " & days$[dayOfTheWeek 2021 12 25]
print "2022-1-1 is on " & days$[dayOfTheWeek 2022 1 1]
</syntaxhighlight>
{{out}}
<pre>
2021-12-25 is on Saturday
2022-1-1 is on Saturday
</pre>
=={{header|F_Sharp|F#}}==
<
// Show day of week for Christmas Day, 2021 and New Year's Day, 2022. Nigel Galloway: December 1st., 2021
printfn $"Christmas Day 2021 is a %s{string(System.DateTime(2021,12,25).DayOfWeek)}. New Years Day 2022 is a %s{string(System.DateTime(2022,1,1).DayOfWeek)}."
</syntaxhighlight>
{{out}}
<pre>
Christmas Day 2021 is a Saturday. New Years Day 2022 is a Saturday.
</pre>
=={{header|Factor}}==
{{works with|Factor|0.99 2021-06-02}}
<
kernel sequences ;
Line 80 ⟶ 694:
: .holidays ( seq -- ) [ dup holidays msg printf ] each ;
{ 1578 1590 1642 1957 2020 2021 2022 2242 2245 2393 } .holidays</
{{out}}
<pre>
Line 94 ⟶ 708:
In 2393, New Years is on a Friday, and Christmas is on a Saturday.
</pre>
=={{header|FreeBASIC}}==
<syntaxhighlight lang="freebasic">#include "vbcompat.bi" 'contains functions for dealing with dates and times
#include "string.bi" 'contains functions for formatting text strings
dim as double christmas = DateSerial(2021, 12, 25) 'enter the dates of the two holidays
dim as double newyears = DateSerial(2022, 01, 01)
print "Christmas Day 2021 is on a "; format(christmas,"dddd")
print "New Year's Day 2022 is on a "; format(newyears, "dddd")</syntaxhighlight>
{{out}}<pre>
Christmas Day 2021 is on a Saturday
New Year's Day 2022 is on a Saturday
</pre>
=={{header|J}}==
<syntaxhighlight lang="j"> (weekday 2021 12 25){::;:'Sun Mon Tue Wed Thu Fri Sat'
Sat
(weekday 2022 01 01){::;:'Sun Mon Tue Wed Thu Fri Sat'
Sat</syntaxhighlight>
=={{header|jq}}==
{{works with|jq}}
'''Works with gojq, the Go implementation of jq'''
Years, output format, and output are exactly as for [[#Wren|Wren]].
<syntaxhighlight lang="jq">def weekdaynames:
["Sunday", "Monday","Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"];
# example: weekday(1999; 12; 25)
def weekday($year; $month; $day):
"\($year)-\($month)-\($day)" | strptime("%Y-%m-%d") | weekdaynames[.[-2]];
1578, 1590, 1642, 1957, 2020, 2021, 2022, 2242, 2245, 2393
| "In \(.), New year's day is on a \(weekday(.;1;1)), and Christmas day on \(weekday(.;12;25))."</syntaxhighlight>
{{out}}
As for [[#Wren]]
=={{header|Julia}}==
See also https://docs.julialang.org/en/v1/stdlib/Dates/#Dates.format-Tuple{TimeType,%20AbstractString}
<
for year in [1578, 1590, 1642, 1957, 2020, 2021, 2022, 2242, 2245, 2393]
Line 103 ⟶ 754:
" and Christmas: ", Dates.format(DateTime(year, 12, 25), "E, U d, Y"))
end
</
<pre>
Year 1578, New Years's Day: Sunday, January 1, 1578 and Christmas: Monday, December 25, 1578
Line 115 ⟶ 766:
Year 2245, New Years's Day: Wednesday, January 1, 2245 and Christmas: Thursday, December 25, 2245
Year 2393, New Years's Day: Friday, January 1, 2393 and Christmas: Saturday, December 25, 2393
</pre>
=={{header|Nim}}==
<syntaxhighlight lang="Nim">
import std/times
echo "25th of December 2021 is a ", getDayOfWeek(25, mDec, 2021)
echo "1st of January 2022 is a ", getDayOfWeek(1, mJan, 2022)
</syntaxhighlight>
{{out}}
<pre>25th of December 2021 is a Saturday
1st of January 2022 is a Saturday
</pre>
=={{header|ooRexx}}==
<
Call wkd 2021,12,25
Call wkd 2022,01,01
Line 127 ⟶ 791:
dt=.DateTime~new(y,m,d)
say d'.'m'.'y 'is a' wd[dt~weekday]
Return</
<pre>25.12.2021 is a Saturday
01.01.2022 is a Saturday<</pre>
=={{header|Pascal}}==
==={{header|Free Pascal}}===
<syntaxhighlight lang="pascal">
Program daysofweek;
Uses sysutils;
Const Years : array Of integer = (1578, 1590, 1642, 1957, 2020, 2021, 2022, 2242, 2245, 2393);
Var christmasday, newyearsday : tdatetime;
year : integer;
Begin
For year In years Do
Begin
christmasday := encodeDate(year,12,25);
newyearsday := encodeDate(year,1,1);
writeln('in ',year,' New Years day is on ',DefaultFormatSettings.LongDayNames[DayOfWeek(
newyearsday)],', and Christmas day on a ',DefaultFormatSettings.LongDayNames[DayOfWeek(
christmasday
)]);
End;
End.
</syntaxhighlight>
{{out}}
<pre>
in 1578 New Years day is on Sunday, and Christmas day on a Monday
in 1590 New Years day is on Monday, and Christmas day on a Tuesday
in 1642 New Years day is on Wednesday, and Christmas day on a Thursday
in 1957 New Years day is on Tuesday, and Christmas day on a Wednesday
in 2020 New Years day is on Wednesday, and Christmas day on a Friday
in 2021 New Years day is on Friday, and Christmas day on a Saturday
in 2022 New Years day is on Saturday, and Christmas day on a Sunday
in 2242 New Years day is on Saturday, and Christmas day on a Sunday
in 2245 New Years day is on Wednesday, and Christmas day on a Thursday
in 2393 New Years day is on Friday, and Christmas day on a Saturday
</pre>
=={{header|Perl}}==
<
use strict; # https://rosettacode.org/wiki/What_weekdays_will_Christmas_and_New_Year
Line 145 ⟶ 846:
print "$_->[0] ", qw( Sunday Monday Tuesday Wednesday Thursday Fridat Saturday )
[(localtime timelocal(0, 0, 12, @{$_}[1..3]))[6]], "\n";
}</
{{out}}
<pre>
Line 153 ⟶ 854:
=={{header|Phix}}==
<!--<
<span style="color: #008080;">with</span> <span style="color: #008080;">javascript_semantics</span>
<span style="color: #008080;">include</span> <span style="color: #004080;">timedate</span><span style="color: #0000FF;">.</span><span style="color: #000000;">e</span>
Line 162 ⟶ 863:
<span style="color: #008080;">end</span> <span style="color: #008080;">procedure</span>
<span style="color: #7060A8;">papply</span><span style="color: #0000FF;">({</span><span style="color: #000000;">1578</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">1590</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">1642</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">1957</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">2020</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">2021</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">2022</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">2242</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">2245</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">2393</span><span style="color: #0000FF;">},</span><span style="color: #000000;">nyc</span><span style="color: #0000FF;">)</span>
<!--</
<small>Note the builtin timedate type does not officially support dates prior to ''1752''... the fact that the first three lines agree with other entries on this page is pure luck.</small>
{{out}}
Line 177 ⟶ 878:
In 2393, New year's day is on a Friday, and Christmas day on a Saturday.
</pre>
=={{header|PL/I}}==
<syntaxhighlight lang="pli">xmas_and_newyear: procedure options(main);
day_name: procedure(year,month,day) returns(char(9) varying);
declare days(0:6) char(9) varying;
declare (year, month, day) fixed;
declare (y, m, d, j, k) fixed;
days(0) = 'Saturday';
days(1) = 'Sunday';
days(2) = 'Monday';
days(3) = 'Tuesday';
days(4) = 'Wednesday';
days(5) = 'Thursday';
days(6) = 'Friday';
m = month;
y = year;
if m <= 2 then do;
m = m + 12;
y = y -1;
end;
j = y/100;
k = mod(y,100);
d = mod((day + ((m+1)*26)/10 + k + k/4 + j/4 + 5*j),7);
return(days(d));
end day_name;
declare years(2) fixed static initial(2021, 2022);
declare months(2) fixed static initial( 12, 1);
declare days(2) fixed static initial( 25, 1);
declare i fixed;
do i=1 to 2;
put skip edit(months(i),'/',days(i),'/',years(i),
' is a ',
day_name(years(i),months(i),days(i)))
(F(2),A,F(2),A,F(4),A,A);
end;
end xmas_and_newyear;</syntaxhighlight>
{{out}}
<pre>12/25/2021 is a Saturday
1/ 1/2022 is a Saturday</pre>
=={{header|PL/M}}==
<syntaxhighlight lang="pli">100H:
BDOS: PROCEDURE(F,A); DECLARE F BYTE, A ADDRESS; GO TO 5; END BDOS;
EXIT: PROCEDURE; GO TO 0; END EXIT;
PR$CH: PROCEDURE(C); DECLARE C BYTE; CALL BDOS(2,C); END PR$CH;
PR$STR: PROCEDURE(S); DECLARE S ADDRESS; CALL BDOS(9,S); END PR$STR;
PR$NUM: PROCEDURE(N);
DECLARE S(6) BYTE INITIAL ('.....$');
DECLARE (N, P) ADDRESS, D BASED P BYTE;
P = .S(5);
DIGIT:
P = P-1;
D = '0' + N MOD 10;
IF (N := N/10) > 0 THEN GO TO DIGIT;
CALL PR$STR(P);
END PR$NUM;
DAY$NAME: PROCEDURE(Y,M,D) ADDRESS;
DECLARE (Y,M,D,J,K) ADDRESS;
IF M <= 2 THEN DO;
M = M + 12;
Y = Y - 1;
END;
J = Y / 100;
K = Y MOD 100;
D = (D + ((M+1)*26)/10 + K + SHR(K,2) + SHR(J,2) + 5*6) MOD 7;
DO CASE D;
RETURN .'SATURDAY$';
RETURN .'SUNDAY$';
RETURN .'MONDAY$';
RETURN .'TUESDAY$';
RETURN .'WEDNESDAY$';
RETURN .'THURSDAY$';
RETURN .'FRIDAY$';
END;
END DAY$NAME;
PR$DATE: PROCEDURE(Y,M,D);
DECLARE Y ADDRESS, (M, D) BYTE;
CALL PR$NUM(M);
CALL PR$CH('/');
CALL PR$NUM(D);
CALL PR$CH('/');
CALL PR$NUM(Y);
END PR$DATE;
DECLARE YEARS(2) ADDRESS INITIAL (2021, 2022);
DECLARE MONTHS(2) BYTE INITIAL ( 12, 1);
DECLARE DAYS(2) BYTE INITIAL ( 25, 1);
DECLARE I BYTE;
DO I=0 TO 1;
CALL PR$DATE(YEARS(I),MONTHS(I),DAYS(I));
CALL PR$STR(.' IS A $');
CALL PR$STR(DAY$NAME(YEARS(I),MONTHS(I),DAYS(I)));
CALL PR$STR(.(13,10,'$'));
END;
CALL EXIT;
EOF</syntaxhighlight>
{{out}}
<pre>12/25/2021 IS A SATURDAY
1/1/2022 IS A SATURDAY</pre>
=={{header|Python}}==
<
weekDays = ("Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","Sunday")
Line 192 ⟶ 998:
nextNewYearDayAsString = weekDays[nextNewYearDay]
print("Next new year is on a {}".format(nextNewYearDayAsString))
</syntaxhighlight>
{{out}}
<pre>
This year's Christmas is on a Saturday
Next new year is on a Saturday
</pre>
=={{header|Quackery}}==
<code>dayofweek</code> is defined at [[Day of the week#Quackery]].
<syntaxhighlight lang="quackery"> [ [ table
$ "Sun" $ "Mon"
$ "Tues" $ "Wednes"
$ "Thurs" $ "Fri"
$ "Satur" ]
do $ "day" join ] is day ( n --> $ )
[ 25 12 rot dayofweek ] is christmas ( n --> $ )
[ 1 1 rot dayofweek ] is newyear's ( n --> $ )
2021 christmas day echo$ cr
2022 newyear's day echo$ cr</syntaxhighlight>
{{out}}
<pre>Saturday
Saturday
</pre>
=={{header|Raku}}==
<syntaxhighlight lang="raku"
.say for (flat 2020..2022, (1500 .. 2500).roll(7)).sort.map: {
"In {$_}, New Years is on a { @d-o-w[Date.new($_, 1, 1).day-of-week % 7] }, " ~
"and Christmas on a { @d-o-w[Date.new($_, 12, 25).day-of-week % 7] }."
}</
{{out|Sample output}}
<pre>In 1578, New Years is on a Sunday, and Christmas on a Monday.
Line 219 ⟶ 1,048:
=={{header|Ring}}==
<
weekdays = ["Mon","Tues","Wednes","Thurs","Fri","Satur","Sun"]
dow = timelist()[15]
Line 238 ⟶ 1,067:
func nameof day
return weekdays[((day + today - 1) % 7) + 1] + "day"</
{{out}}
<pre>working...
Line 245 ⟶ 1,074:
done...</pre>
=={{header|
{{
≪ 1000000 / 25.12 + 0
TSTR 1 3 SUB
"X-MAS: " OVER +
"NEW YEAR: " ROT +
≫ '<span style="color:blue">TASK</span>' STO
2021 <span style="color:blue">TASK</span>
{{out}}
<pre>
2: "X-MAS: SAT"
1: "NEW YEAR: SAT"
</pre>
=={{header|Ruby}}==
This uses the same years as the Raku example. The Ruby Date class does however take the calendar reform (default 1582) into account, so the days for 1578 differ from all other languages so far.
<syntaxhighlight lang="ruby">require 'date'
years = [1578, 1590, 1642, 1957, 2020, 2021, 2022, 2242, 2245, 2393]
years.each do |year|
xmas = Date.new(year,12,25).strftime("%A")
ny = Date.new(year, 1, 1).strftime("%A")
puts "In #{year}, New year's day is on a #{ny}, and Christmas day on #{xmas}."
end
</syntaxhighlight>
{{out}}
<pre>In 1578, New year's day is on a Wednesday, and Christmas day on Thursday.
In 1590, New year's day is on a Monday, and Christmas day on Tuesday.
In 1642, New year's day is on a Wednesday, and Christmas day on Thursday.
Line 271 ⟶ 1,111:
In 2245, New year's day is on a Wednesday, and Christmas day on Thursday.
In 2393, New year's day is on a Friday, and Christmas day on Saturday.
</pre>
=={{header|Wren}}==
{{libheader|Wren-date}}
This uses the same years as the Raku example.
The above module uses the Gregorian Proleptic calendar and therefore gives the wrong days of the week for 1578 as the earliest year for the adoption of the Gregorian calendar was 1582 when 10 days (from 5th until 14th October inclusive) were omitted. To get the correct days for 1578 (and agree with the Ruby entry) we therefore need to add 10 days to the Gregorian date which the ''Date.fromJulian'' method does automatically.
<syntaxhighlight lang="wren">import "./date" for Date
System.print("Days of week per Gregorian Proleptic calendar:")
var years = [1578, 1590, 1642, 1957, 2020, 2021, 2022, 2242, 2245, 2393]
for (year in years) {
var newYear = Date.new(year, 1, 1).weekDay
var xmas = Date.new(year, 12, 25).weekDay
System.print(" In %(year), New year's day is on a %(newYear), and Christmas day on %(xmas).")
}
System.print("\nActual days for 1578 (Julian calendar) were 10 days later:")
System.print(" New Year's day was on %(Date.fromJulian(1578, 1, 1).weekDay), and Christmas day on %(Date.fromJulian(1578, 12, 25).weekDay).")</syntaxhighlight>
{{out}}
<pre>
Days of week per Gregorian Proleptic calendar:
In 1578, New year's day is on a Sunday, and Christmas day on Monday.
In 1590, New year's day is on a Monday, and Christmas day on Tuesday.
In 1642, New year's day is on a Wednesday, and Christmas day on Thursday.
In 1957, New year's day is on a Tuesday, and Christmas day on Wednesday.
In 2020, New year's day is on a Wednesday, and Christmas day on Friday.
In 2021, New year's day is on a Friday, and Christmas day on Saturday.
In 2022, New year's day is on a Saturday, and Christmas day on Sunday.
In 2242, New year's day is on a Saturday, and Christmas day on Sunday.
In 2245, New year's day is on a Wednesday, and Christmas day on Thursday.
In 2393, New year's day is on a Friday, and Christmas day on Saturday.
Actual days for 1578 (Julian calendar) were 10 days later:
New Year's day was on Wednesday, and Christmas day on Thursday.
</pre>
=={{header|XPL0}}==
<
int Year, Month, Day; \Works for years 1583 onward
int DayOfWeek, Names;
Line 287 ⟶ 1,162:
Text(0, "This New Year's Day is on a ");
Text(0, WeekDay(2022, 1, 1)); CrLf(0);
]</
{{out}}
| |||