Damm algorithm: Difference between revisions
Added uBasic/4tH version
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112946: Checksum digit correct.</pre>
=={{header|uBasic/4tH}}==
{{trans|Visual Basic .NET}}
{{works with|v3.64}}
<lang>Push 0, 3, 1, 7, 5, 9, 8, 6, 4, 2: i = FUNC(_Data(0))
Push 7, 0, 9, 2, 1, 5, 4, 8, 6, 3: i = FUNC(_Data(i))
Push 4, 2, 0, 6, 8, 7, 1, 3, 5, 9: i = FUNC(_Data(i))
Push 1, 7, 5, 0, 9, 8, 3, 4, 2, 6: i = FUNC(_Data(i))
Push 6, 1, 2, 3, 0, 4, 5, 9, 7, 8: i = FUNC(_Data(i))
Push 3, 6, 7, 4, 2, 0, 9, 5, 8, 1: i = FUNC(_Data(i))
Push 5, 8, 6, 9, 7, 2, 0, 1, 3, 4: i = FUNC(_Data(i))
Push 8, 9, 4, 5, 3, 6, 2, 0, 1, 7: i = FUNC(_Data(i))
Push 9, 4, 3, 8, 6, 1, 7, 2, 0, 5: i = FUNC(_Data(i))
Push 2, 5, 8, 1, 4, 3, 6, 7, 9, 0: i = FUNC(_Data(i))
' Read the table
Push 112949, 112946, 5727, 5724 ' Put numbers on the stack
For i = 1 To Used() ' Read up to the number of stack items
Print Using "______"; Tos();" is "; ' Print the header
If FUNC(_Damm (Str(Pop()))) Then Print "in";
Print "valid" ' invalid only if Damm() returns TRUE
Next ' Next stack item
End
_Data Param (1) ' Reads data in reverse order,
Local (2) ' starting with A@
c@ = a@ + Used() ' Calculate next offset
For b@ = c@-1 To a@ Step -1 ' Now place the elements
@(b@) = Pop() ' that are retrieved from the stack
Next b@ ' Next item
Return (c@) ' Return new offset
_Damm Param (1) ' Perform the Damm algorithm
Local (2)
c@ = 0 ' Reset the flag
For b@ = 0 To Len(a@) - 1 ' Check all characters in the string
c@ = @(c@*10 + peek(a@, b@) - ord("0"))
Next ' Next character
Return (c@) ' Return Flag</lang>
{{Out}}
<pre> 5724 is valid
5727 is invalid
112946 is valid
112949 is invalid
0 OK, 0:984</pre>
=={{header|Visual Basic .NET}}==
{{trans|C#}}
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