Cramer's rule: Difference between revisions
Added XPL0 example.
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(Added XPL0 example.) |
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<pre>
Solution is [2, -12, -4, 1]
</pre>
=={{header|XPL0}}==
<lang XPL0>
func Det(A, N); \Return value of determinate A, order N
int A, N;
int B, Sum, I, K, L, Term;
[if N = 1 then return A(0, 0);
B:= Reserve((N-1)*4\IntSize\);
Sum:= 0;
for I:= 0 to N-1 do
[L:= 0;
for K:= 0 to N-1 do
if K # I then
[B(L):= @A(K, 1); L:= L+1];
Term:= A(I, 0) * Det(B, N-1);
if I & 1 then Term:= -Term;
Sum:= Sum + Term;
];
return Sum;
];
real D;
[D:= float(Det([[2,-1,5,1], [3,2,2,-6], [1,3,3,-1], [5,-2,-3,3]], 4));
RlOut(0, float(Det([[-3,-1,5,1], [-32,2,2,-6], [-47,3,3,-1], [49,-2,-3,3]], 4)) / D);
RlOut(0, float(Det([[2,-3,5,1], [3,-32,2,-6], [1,-47,3,-1], [5,49,-3,3]], 4)) / D);
RlOut(0, float(Det([[2,-1,-3,1], [3,2,-32,-6], [1,3,-47,-1], [5,-2,49,3]], 4)) / D);
RlOut(0, float(Det([[2,-1,5,-3], [3,2,2,-32], [1,3,3,-47], [5,-2,-3,49]], 4)) / D);
]</lang>
{{out}}
<pre>
2.00000 -12.00000 -4.00000 1.00000
</pre>
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