Count the coins: Difference between revisions

m
Line 1,216:
break 1
.
call count sum - val[kind] kind r2
call count sum kind - 1 r1
r = r1 + r2
cache[chind] = r
.
call count 100 4 r
print r
call count 10000 6 r
print r
call count 100000 6 r
# this is not exact, since numbers
# are doubles and r > 2^53
1,969

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