Count occurrences of a substring: Difference between revisions
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puts count_substring3("a*b", "abaabba*bbaba*bbab") # ==> 2
</lang>
=={{header|Nanoquery}}==
{{trans|Java}}
<lang Nanoquery>def countSubstring(subStr, str)
return int((len(str) - len(str.replace(subStr, ""))) / len(subStr))
end</lang>
=={{header|Nemerle}}==
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