Count in octal: Difference between revisions

Content added Content deleted
(added Fortran)
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} while(i != 0);
} while(i != 0);
}</lang>
}</lang>

=={{header|Fortran}}==
{{works with|Fortran|95 and later}}
<lang fortran>program Octal
implicit none
integer, parameter :: i64 = selected_int_kind(18)
integer(i64) :: n = 0
! Will stop when n overflows from
! 9223372036854775807 to -92233720368547758078 (1000000000000000000000 octal)
do while(n >= 0)
write(*, "(o0)") n
n = n + 1
end do
end program</lang>


=={{header|Icon}} and {{header|Unicon}}==
=={{header|Icon}} and {{header|Unicon}}==