Count in octal: Difference between revisions
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→{{header|Haskell}}: added Haskell solution |
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Line 389:
print(string.format("%o",l))
end</lang>
=={{header|Mathematica}}==
<lang Mathematica>x=0;
While[True,Print[BaseForm[x,8];x++]</lang>
=={{header|Modula-2}}==
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