Convert seconds to compound duration: Difference between revisions
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Line 768:
86400: 1 d
6000000: 9 wk, 6 d, 10 hr, 40 min</lang>
=={{header|Lua}}==
<lang Lua>function duration (secs)
local units, dur = {"wk", "d", "hr", "min"}, ""
for i, v in ipairs({604800, 86400, 3600, 60}) do
if secs >= v then
dur = dur .. math.floor(secs / v) .. " " .. units[i] .. ", "
secs = secs % v
end
end
if secs == 0 then
return dur:sub(1, -3)
else
return dur .. secs .. " sec"
end
end
print(duration(7259))
print(duration(86400))
print(duration(6000000))</lang>
=={{header|Mathematica}}==
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