Continued fraction: Difference between revisions
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m (→{{header|Perl 6}}: forgot to remove 'take') |
(→{{header|Perl 6}}: on second thought it's cleaner to return functions) |
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<lang Perl 6>sub infix:<⚬>(&f, &g) { -> $x { &f(&g($x)) } } |
<lang Perl 6>sub infix:<⚬>(&f, &g) { -> $x { &f(&g($x)) } } |
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sub continued-fraction(@a, @b) { |
sub continued-fraction(@a, @b) { |
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[\⚬] map { @a[$_] + @b[$_] / * }, 0 .. * |
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} |
} |
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printf "√2 ≈ %.9f\n", continued-fraction((1, 2 xx *), (1 xx *))[10]; |
printf "√2 ≈ %.9f\n", continued-fraction((1, 2 xx *), (1 xx *))[10](Inf); |
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printf "e ≈ %.9f\n", continued-fraction((2, 1 .. *), (1, 1 .. *))[10]; |
printf "e ≈ %.9f\n", continued-fraction((2, 1 .. *), (1, 1 .. *))[10](Inf); |
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printf "π ≈ %.9f\n", continued-fraction((3, 6 xx *), ((1, 3, 5 ... *) X** 2))[1000];</lang> |
printf "π ≈ %.9f\n", continued-fraction((3, 6 xx *), ((1, 3, 5 ... *) X** 2))[1000](Inf);</lang> |
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The main advantage is that the definition of the function does not need to know for which rank n it is computed. This is arguably closer to the mathematical definition. |
The main advantage is that the definition of the function does not need to know for which rank n it is computed. This is arguably closer to the mathematical definition. |
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