Compare length of two strings: Difference between revisions
Add Scala implementation
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"e" has length 1 and is the shortest
</pre>
=={{header|Scala}}==
{{trans|Java}}
<syntaxhighlight lang="Scala">
object Example extends App {
val strings = Array("abcd", "123456789", "abcdef", "1234567")
compareAndReportStringsLength(strings)
def compareAndReportStringsLength(strings: Array[String]): Unit = {
if (strings.nonEmpty) {
val Q = '"'
val hasLength = " has length "
val predicateMax = " and is the longest string"
val predicateMin = " and is the shortest string"
val predicateAve = " and is neither the longest nor the shortest string"
val sortedStrings = strings.sortBy(-_.length)
val maxLength = sortedStrings.head.length
val minLength = sortedStrings.last.length
sortedStrings.foreach { str =>
val length = str.length
val predicate = length match {
case `maxLength` => predicateMax
case `minLength` => predicateMin
case _ => predicateAve
}
println(s"$Q$str$Q$hasLength$length$predicate")
}
}
}
}
</syntaxhighlight>
{{out}}
<pre>
"123456789" has length 9 and is the longest string
"1234567" has length 7 and is neither the longest nor the shortest string
"abcdef" has length 6 and is neither the longest nor the shortest string
"abcd" has length 4 and is the shortest string
</pre>
=={{header|Transd}}==
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