Compare length of two strings: Difference between revisions

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lengths and classification as the longest, shortest or average length.

Note that for N > 0 such objects (e.g., strings, ~~byte strings~~, lists) it is

Note that for N > 0 such objects (e.g., strings, bytes, lists) it is

possible that exactly M > 0 of them will be of the maximum length, K > 0 of

them will be of the minimum length. In particular, it is possible that all

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# Longer phrases make translation into other natural languages easier.

#

has_length = _('has length')

if all(isinstance(obj, str) for obj in objects):

predicate_max = _('is the longest string')

predicate_max = _('and is the longest string')

predicate_min = _('is the shortest string')

predicate_min = _('and is the shortest string')

predicate_ave = _('is neither the longest nor the shortest string')

predicate_ave = _('and is neither the longest nor the shortest string')

else:

predicate_max = _('is the longest object')

predicate_max = _('and is the longest object')

predicate_min = _('is the shortest object')

predicate_min = _('and is the shortest object')

predicate_ave = _('is neither the longest nor the shortest object')

predicate_ave = _('and is neither the longest nor the shortest object')

if sorted_:

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else:

predicate = predicate_ave

print(~~f'"{~~obj}" ~~has~~ length ~~{length} and {~~predicate}')

print(obj, has_length, length, predicate)

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print()

compare_and_report_length(*LIST)

print()~~</lang>~~

print()

</lang>