Common list elements: Difference between revisions

{{libheader|Wren-seq}}

As we're dealing here with lists rather than sets, some guidance is needed on how to deal with duplicates in each list in the general case. A drastic solution would be to remove all duplicates from the result. Instead, the following matches duplicates - so if List A contains 2 'a's and List B contains 3 'a's, there would be 2 'a's in the result.

 

var common2 = Fn.new { |l1, l2|

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Since the above was written, we can also now offer a library based solution.

 

var lls = [