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Combinations with repetitions: Difference between revisions
→{{header|Julia}}: added Julia example
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["plain","plain"]
There are 220 ways to pick 3 objects with replacement from 10.</pre>
=={{header|Julia}}==
(Based on [http://stackoverflow.com/questions/26313868/julia-unique-sets-of-n-elements-with-replacement this StackOverflow discussion].)
<lang julia>function combos_with_replacement(list, k)
n = length(list)
[[list[c[i]-i+1] for i=1:length(c)] for c in combinations([1:(n+k-1)],k)]
end</lang>
{{out}}
<pre>julia> combos_with_replacement(["iced","jam","plain"], 2)
6-element Array{Array{ASCIIString,1},1}:
ASCIIString["iced","iced"]
ASCIIString["iced","jam"]
ASCIIString["iced","plain"]
ASCIIString["jam","jam"]
ASCIIString["jam","plain"]
ASCIIString["plain","plain"]
julia> length(combos_with_replacement(1:10, 3))
220</pre>
=={{header|Lua}}==
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