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Chowla numbers: Difference between revisions
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chowla(<big>'''n'''</big>) = sigmaProperDivisiors(<big>'''n'''</big>) <big>'''- 1''' </big>
chowla(<big>'''a'''*'''b'''</big>) = <big>'''a
if chowla(<big>'''n'''</big>) = <big>'''0'''</big>,
if chowla(<big>'''n'''</big>) = <big>'''n - 1'''</big>, and <big>'''n > 1'''</big>, then <big>'''n'''</big> is a perfect number
</big>
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