Chowla numbers: Difference between revisions
Content added Content deleted
Drkameleon (talk | contribs) (Added Arturo implementation) |
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| Line 963: | Line 963: | ||
while i * i <= n { |
while i * i <= n { |
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if n % i == 0 { |
if n % i == 0 { |
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var app = if i == (j |
var app = if i == (j: n / i) { |
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0 |
0 |
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} else { |
} else { |
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| Line 974: | Line 974: | ||
return sum |
return sum |
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} |
} |
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func sieve(limit) { |
func sieve(limit) { |
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var c = Array.empty(limit) |
var c = Array.empty(limit) |
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| Line 990: | Line 990: | ||
return c |
return c |
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} |
} |
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for i in 1..37 { |
for i in 1..37 { |
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print("chowla(\(i)) = \(chowla(i))") |
print("chowla(\(i)) = \(chowla(i))") |
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} |
} |
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var count = 1 |
var count = 1 |
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var limit = 10000000 |
var limit = 10000000 |
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var power = 100 |
var power = 100 |
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var c = sieve(limit) |
var c = sieve(limit) |
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var i = 3 |
var i = 3 |
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while i < limit { |
while i < limit { |
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| Line 1,011: | Line 1,011: | ||
i += 2 |
i += 2 |
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} |
} |
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count = 0 |
count = 0 |
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limit = 35000000 |
limit = 35000000 |
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var k = 2 |
var k = 2 |
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var kk = 3 |
var kk = 3 |
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var p |
var p |
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i = 2 |
i = 2 |
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while true { |
while true { |
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if (p |
if (p: k * kk) > limit { |
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break |
break |
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} |
} |
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| Line 1,030: | Line 1,030: | ||
kk += k |
kk += k |
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} |
} |
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print("There are \(count) perfect numbers <= 35,000,000")</lang> |
print("There are \(count) perfect numbers <= 35,000,000")</lang> |
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