Chinese remainder theorem: Difference between revisions

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@@ Line 1,144: / Line 1,144: @@
 {{trans|C}}
 <syntaxhighlight lang="text">
-func mul_inv a b . x1 .
+proc mul_inv a b . x1 .
   b0 = b
   x1 = 1
@@ Line 1,162: / Line 1,162: @@
   .
 .
-func remainder . n[] a[] r .
+proc remainder . n[] a[] r .
   prod = 1
   sum = 0