Cyclops numbers
Cyclops numbers is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.
A cyclops number is a number with an odd number of digits that has a zero in the center, but nowhere else. They are named so in tribute to the one eyed giants Cyclops from Greek mythology.
Cyclops numbers can be found in any base. This task strictly is looking for cyclops numbers in base 10.
There are many different classifications of cyclops numbers with minor differences in characteristics. In an effort to head off a whole series of tasks with tiny variations, we will cover several variants here.
- Task
- Find and display here on this page the first 50 cyclops numbers in base 10 (all of the sub tasks are restricted to base 10).
- Find and display here on this page the first 50 prime cyclops numbers. (cyclops numbers that are prime.)
- Find and display here on this page the first 50 blind prime cyclops numbers. (prime cyclops numbers that remain prime when "blinded"; the zero is removed from the center.)
- Find and display here on this page the first 50 palindromic prime cyclops numbers. (prime cyclops numbers that are palindromes.)
- Stretch
- Find and display the first cyclops number greater than ten million (10,000,000) and the index (place) in the series where it is found.
- Find and display the first prime cyclops number greater than ten million (10,000,000) and the index (place) in the series where it is found.
- Find and display the first blind prime cyclops number greater than ten million (10,000,000) and the index (place) in the series where it is found.
- Find and display the first palindromic prime cyclops number greater than ten million (10,000,000) and the index (place) in the series where it is found.
(Note: there are no cyclops numbers between ten million and one hundred million, they need to have an odd number of digits)
- See also
ALGOL 68
Generates the sequence. <lang algol68>BEGIN # show cyclops numbers - numbers with a 0 in the middle and no other 0 digits #
INT max prime = 100 000;
# sieve the primes to max prime #
[ 1 : max prime ]BOOL prime;
prime[ 1 ] := FALSE; prime[ 2 ] := TRUE;
FOR i FROM 3 BY 2 TO UPB prime DO prime[ i ] := TRUE OD;
FOR i FROM 4 BY 2 TO UPB prime DO prime[ i ] := FALSE OD;
FOR i FROM 3 BY 2 TO ENTIER sqrt( max prime ) DO
IF prime[ i ] THEN FOR s FROM i * i BY i + i TO UPB prime DO prime[ s ] := FALSE OD FI
OD;
# returns TRUE if c is prime, FALSE otherwise #
PROC have a prime = ( INT c )BOOL:
IF c < 2 THEN FALSE
ELIF c < max prime
THEN prime[ c ]
ELSE # the cyclops number is too large for the sieve, use trial division #
BOOL possibly prime := c MOD 2 = 0;
FOR d FROM 3 BY 2 TO c OVER 2 WHILE possibly prime := c MOD d /= 0 DO SKIP OD;
possibly prime
FI # have a prime # ;
# arrays of the cyclops numbers we must show #
[ 1 : 50 ]INT first cyclops; INT cyclops count := 0;
[ 1 : 50 ]INT first prime cyclops; INT prime cyclops count := 0;
[ 1 : 50 ]INT first palindromic prime cyclops; INT palindromic prime cyclops count := 0;
[ 1 : 50 ]INT first blind prime cyclops; INT blind prime cyclops count := 0;
# notes c is a cyclops number, palindromic indicates whether it is palindromic or not #
# bc should be c c with the middle 0 removed #
# if c is one of the first 50 of various classifications, #
# it is stored in the appropriate array #
PROC have cyclops = ( INT c, BOOL palindromic, INT bc )VOID:
BEGIN
cyclops count +:= 1;
IF cyclops count <= UPB first cyclops THEN first cyclops[ cyclops count ] := c FI;
IF prime cyclops count < UPB first prime cyclops
OR ( palindromic prime cyclops count < UPB first palindromic prime cyclops AND palindromic )
OR blind prime cyclops count < UPB first blind prime cyclops
THEN
IF have a prime( c ) THEN
# have a prime cyclops #
IF prime cyclops count < UPB first prime cyclops THEN
first prime cyclops[ prime cyclops count +:= 1 ] := c
FI;
IF palindromic prime cyclops count < UPB first palindromic prime cyclops AND palindromic THEN
first palindromic prime cyclops[ palindromic prime cyclops count +:= 1 ] := c
FI;
IF blind prime cyclops count < UPB first blind prime cyclops THEN
IF have a prime( bc ) THEN
first blind prime cyclops[ blind prime cyclops count +:= 1 ] := c
FI
FI
FI
FI
END # have cyclops # ;
# generate the cyclops numbers #
# 0 is the first and only cyclops number with less than three digits #
have cyclops( 0, TRUE, 0 );
# generate the 3 digit cyclops numbers #
FOR f TO 9 DO
FOR b TO 9 DO
have cyclops( ( f * 100 ) + b
, f = b
, ( f * 10 ) + b
)
OD
OD;
# generate the 5 digit cyclops numbers #
FOR d1 TO 9 DO
FOR d2 TO 9 DO
INT d1200 = ( ( d1 * 10 ) + d2 ) * 100;
INT d12000 = d1200 * 10;
FOR d4 TO 9 DO
INT d40 = d4 * 10;
FOR d5 TO 9 DO
INT d45 = d40 + d5;
have cyclops( d12000 + d45
, d1 = d5 AND d2 = d4
, d1200 + d45
)
OD
OD
OD
OD;
# generate the 7 digit cyclops numbers #
FOR d1 TO 9 DO
FOR d2 TO 9 DO
FOR d3 TO 9 DO
INT d123000 = ( ( ( ( d1 * 10 ) + d2 ) * 10 ) + d3 ) * 1000;
INT d1230000 = d123000 * 10;
FOR d5 TO 9 DO
INT d500 = d5 * 100;
FOR d6 TO 9 DO
INT d560 = d500 + ( d6 * 10 );
FOR d7 TO 9 DO
INT d567 = d560 + d7;
have cyclops( d1230000 + d567
, d1 = d7 AND d2 = d6 AND d3 = d5
, d123000 + d567
)
OD
OD
OD
OD
OD
OD;
# show parts of the sequence #
print( ( "The first 50 cyclops numbers:", newline, " " ) );
FOR i TO 50 DO
print( ( " ", whole( first cyclops[ i ], -7 ) ) );
IF i MOD 10 = 0 THEN print( ( newline, " " ) ) FI
OD;
print( ( newline, "The first 50 prime cyclops numbers:", newline, " " ) );
FOR i TO 50 DO
print( ( " ", whole( first prime cyclops[ i ], -7 ) ) );
IF i MOD 10 = 0 THEN print( ( newline, " " ) ) FI
OD;
print( ( newline, "The first 50 palindromic prime cyclops numbers:", newline, " " ) );
FOR i TO 50 DO
print( ( " ", whole( first palindromic prime cyclops[ i ], -7 ) ) );
IF i MOD 10 = 0 THEN print( ( newline, " " ) ) FI
OD;
print( ( newline, "The first 50 blind prime cyclops numbers:", newline, " " ) );
FOR i TO 50 DO
print( ( " ", whole( first blind prime cyclops[ i ], -7 ) ) );
IF i MOD 10 = 0 THEN print( ( newline, " " ) ) FI
OD
END</lang>
- Output:
The first 50 cyclops numbers:
0 101 102 103 104 105 106 107 108 109
201 202 203 204 205 206 207 208 209 301
302 303 304 305 306 307 308 309 401 402
403 404 405 406 407 408 409 501 502 503
504 505 506 507 508 509 601 602 603 604
The first 50 prime cyclops numbers:
101 103 107 109 307 401 409 503 509 601
607 701 709 809 907 11027 11047 11057 11059 11069
11071 11083 11087 11093 12011 12037 12041 12043 12049 12071
12073 12097 13033 13037 13043 13049 13063 13093 13099 14011
14029 14033 14051 14057 14071 14081 14083 14087 15013 15017
The first 50 palindromic prime cyclops numbers:
101 16061 31013 35053 38083 73037 74047 91019 94049 1120211
1150511 1160611 1180811 1190911 1250521 1280821 1360631 1390931 1490941 1520251
1550551 1580851 1630361 1640461 1660661 1670761 1730371 1820281 1880881 1930391
1970791 3140413 3160613 3260623 3310133 3380833 3460643 3470743 3590953 3670763
3680863 3970793 7190917 7250527 7310137 7540457 7630367 7690967 7750577 7820287
The first 50 blind prime cyclops numbers:
101 103 107 109 307 401 503 509 601 607
701 709 809 907 11071 11087 11093 12037 12049 12097
13099 14029 14033 14051 14071 14081 14083 14087 15031 15053
15083 16057 16063 16067 16069 16097 17021 17033 17041 17047
17053 17077 18047 18061 18077 18089 19013 19031 19051 19073
Factor
An attempt to make it fast has resulted in a lot of code, but here's the basic idea. Cyclops numbers are stored in four parts: an integer representing whatever is to the left of the 0, a right integer, the number of digits in either side, and the maximum number with that many digits. For example, T{ cyclops f 33 34 2 99 } represents the number 33034. The left and right are zeroless; that is, they are not allowed to have any zeros.
In order to find the successor to a given cyclops number:
- Increment the right integer to the next zeroless integer using the following formula (from OEIS):
a(n+1) = f(a(n)) with f(x) = 1 + if x mod 10 < 9 then x else 10*f([x/10])
- Unless right = max, in which case increment the left integer instead in the same manner, and reset the right integer back to
max / 9. - Unless left = max, in which case we move up to the next order of magnitude by adding
max/9 + 1to both sides, adding1to the number of digits, and setting the new max asmax := max * 10 + 9
Cyclops numbers in this form can be converted to integers (as late as possible) with int(c) = 10^(c.n + 1) * c.left + c.right
where n is the number of digits in either side.
Cyclops numbers can be converted to blind form with the same formula without the + 1.
<lang factor>USING: accessors formatting grouping io kernel lists lists.lazy math math.functions math.primes prettyprint sequences tools.memory.private tools.time ;
! ==========={[ Cyclops data type and operations ]}=============
TUPLE: cyclops left right n max ;
- <cyclops> ( -- cyclops ) 1 1 1 9 cyclops boa ;
- >cyclops< ( cyclops -- right left n )
[ right>> ] [ left>> ] [ n>> ] tri ;
M: cyclops >integer >cyclops< 1 + 10^ * + ;
- >blind ( cyclops -- n ) >cyclops< 10^ * + ;
- next-zeroless ( 9199 -- 9211 )
dup 10 mod 9 < [ 10 /i next-zeroless 10 * ] unless 1 + ;
- right++ ( cyclops -- cyclops' )
[ next-zeroless ] change-right ; inline
- left++ ( cyclops -- cyclops' )
[ next-zeroless ] change-left [ 9 /i ] change-right ;
- n++ ( cyclops -- cyclops' )
[ 1 + ] change-n [ 10 * 9 + ] change-max ;
- change-both ( cyclops quot -- cyclops' )
[ change-left ] keep change-right ; inline
- expand ( cyclops -- cyclops' )
dup max>> 9 /i 1 + '[ _ + ] change-both n++ ;
- carry ( cyclops -- cyclops' )
dup [ left>> ] [ max>> ] bi < [ left++ ] [ expand ] if ;
- succ ( cyclops -- next-cyclops )
dup [ right>> ] [ max>> ] bi < [ right++ ] [ carry ] if ;
! ============{[ List definitions & operations ]}===============
- lcyclops ( -- list ) <cyclops> [ succ ] lfrom-by ;
- lcyclops-int ( -- list ) lcyclops [ >integer ] lmap-lazy ;
- lprime-cyclops ( -- list )
lcyclops-int [ prime? ] lfilter ;
- lblind-prime-cyclops ( -- list )
lcyclops [ >integer prime? ] lfilter [ >blind prime? ] lfilter ;
- reverse-digits ( 123 -- 321 )
0 swap [ 10 /mod rot 10 * + swap ] until-zero ;
- lpalindromic-prime-cyclops ( -- list )
lcyclops [ [ left>> ] [ right>> ] bi reverse-digits = ] lfilter [ >integer prime? ] lfilter ;
- first>1e7 ( list -- elt index )
0 lfrom lzip [ first >integer 10,000,000 > ] lfilter car first2 [ >integer ] dip [ commas ] bi@ ;
! ====================={[ OUTPUT ]}=============================
- first50 ( list -- )
50 swap ltake [ >integer ] lmap list>array 10 group simple-table. ;
- show ( desc list -- )
desc desc "First 50 %s numbers:\n" printf
list [ first50 nl ] [
first>1e7
"First %s number > 10,000,000: %s - at (zero based) index: %s.\n\n\n" printf
] bi ;
"cyclops" lcyclops-int show "prime cyclops" lprime-cyclops show "blind prime cyclops" lblind-prime-cyclops show "palindromic prime cyclops" lpalindromic-prime-cyclops show
! Extra stretch? "One billionth cyclops number:" print 999,999,999 lcyclops lnth >integer commas print</lang>
- Output:
First 50 cyclops numbers: 101 102 103 104 105 106 107 108 109 201 202 203 204 205 206 207 208 209 301 302 303 304 305 306 307 308 309 401 402 403 404 405 406 407 408 409 501 502 503 504 505 506 507 508 509 601 602 603 604 605 First cyclops number > 10,000,000: 111,101,111 - at (zero based) index: 538,083. First 50 prime cyclops numbers: 101 103 107 109 307 401 409 503 509 601 607 701 709 809 907 11027 11047 11057 11059 11069 11071 11083 11087 11093 12011 12037 12041 12043 12049 12071 12073 12097 13033 13037 13043 13049 13063 13093 13099 14011 14029 14033 14051 14057 14071 14081 14083 14087 15013 15017 First prime cyclops number > 10,000,000: 111,101,129 - at (zero based) index: 39,319. First 50 blind prime cyclops numbers: 101 103 107 109 307 401 503 509 601 607 701 709 809 907 11071 11087 11093 12037 12049 12097 13099 14029 14033 14051 14071 14081 14083 14087 15031 15053 15083 16057 16063 16067 16069 16097 17021 17033 17041 17047 17053 17077 18047 18061 18077 18089 19013 19031 19051 19073 First blind prime cyclops number > 10,000,000: 111,101,161 - at (zero based) index: 11,393. First 50 palindromic prime cyclops numbers: 101 16061 31013 35053 38083 73037 74047 91019 94049 1120211 1150511 1160611 1180811 1190911 1250521 1280821 1360631 1390931 1490941 1520251 1550551 1580851 1630361 1640461 1660661 1670761 1730371 1820281 1880881 1930391 1970791 3140413 3160613 3260623 3310133 3380833 3460643 3470743 3590953 3670763 3680863 3970793 7190917 7250527 7310137 7540457 7630367 7690967 7750577 7820287 First palindromic prime cyclops number > 10,000,000: 114,808,411 - at (zero based) index: 66. One billionth cyclops number: 35,296,098,111
Go
<lang go>package main
import (
"fmt" "rcu" "strconv" "strings"
)
func findFirst(list []int) (int, int) {
for i, n := range list {
if n > 1e7 {
return n, i
}
}
return -1, -1
}
func reverse(s string) string {
chars := []rune(s)
for i, j := 0, len(chars)-1; i < j; i, j = i+1, j-1 {
chars[i], chars[j] = chars[j], chars[i]
}
return string(chars)
}
func main() {
ranges := [][2]int{
{0, 0}, {101, 909}, {11011, 99099}, {1110111, 9990999}, {111101111, 119101111},
}
var cyclops []int
for _, r := range ranges {
numDigits := len(fmt.Sprint(r[0]))
center := numDigits / 2
for i := r[0]; i <= r[1]; i++ {
digits := rcu.Digits(i, 10)
if digits[center] == 0 {
count := 0
for _, d := range digits {
if d == 0 {
count++
}
}
if count == 1 {
cyclops = append(cyclops, i)
}
}
}
}
fmt.Println("The first 50 cyclops numbers are:")
for i, n := range cyclops[0:50] {
fmt.Printf("%6s ", rcu.Commatize(n))
if (i+1)%10 == 0 {
fmt.Println()
}
}
n, i := findFirst(cyclops)
ns, is := rcu.Commatize(n), rcu.Commatize(i)
fmt.Printf("\nFirst such number > 10 million is %s at zero-based index %s\n", ns, is)
var primes []int
for _, n := range cyclops {
if rcu.IsPrime(n) {
primes = append(primes, n)
}
}
fmt.Println("\n\nThe first 50 prime cyclops numbers are:")
for i, n := range primes[0:50] {
fmt.Printf("%6s ", rcu.Commatize(n))
if (i+1)%10 == 0 {
fmt.Println()
}
}
n, i = findFirst(primes)
ns, is = rcu.Commatize(n), rcu.Commatize(i)
fmt.Printf("\nFirst such number > 10 million is %s at zero-based index %s\n", ns, is)
var bpcyclops []int
var ppcyclops []int
for _, p := range primes {
ps := fmt.Sprint(p)
split := strings.Split(ps, "0")
noMiddle, _ := strconv.Atoi(split[0] + split[1])
if rcu.IsPrime(noMiddle) {
bpcyclops = append(bpcyclops, p)
}
if ps == reverse(ps) {
ppcyclops = append(ppcyclops, p)
}
}
fmt.Println("\n\nThe first 50 blind prime cyclops numbers are:")
for i, n := range bpcyclops[0:50] {
fmt.Printf("%6s ", rcu.Commatize(n))
if (i+1)%10 == 0 {
fmt.Println()
}
}
n, i = findFirst(bpcyclops)
ns, is = rcu.Commatize(n), rcu.Commatize(i)
fmt.Printf("\nFirst such number > 10 million is %s at zero-based index %s\n", ns, is)
fmt.Println("\n\nThe first 50 palindromic prime cyclops numbers are:\n")
for i, n := range ppcyclops[0:50] {
fmt.Printf("%9s ", rcu.Commatize(n))
if (i+1)%8 == 0 {
fmt.Println()
}
}
n, i = findFirst(ppcyclops)
ns, is = rcu.Commatize(n), rcu.Commatize(i)
fmt.Printf("\n\nFirst such number > 10 million is %s at zero-based index %s\n", ns, is)
}</lang>
- Output:
The first 50 cyclops numbers are:
0 101 102 103 104 105 106 107 108 109
201 202 203 204 205 206 207 208 209 301
302 303 304 305 306 307 308 309 401 402
403 404 405 406 407 408 409 501 502 503
504 505 506 507 508 509 601 602 603 604
First such number > 10 million is 111,101,111 at zero-based index 538,084
The first 50 prime cyclops numbers are:
101 103 107 109 307 401 409 503 509 601
607 701 709 809 907 11,027 11,047 11,057 11,059 11,069
11,071 11,083 11,087 11,093 12,011 12,037 12,041 12,043 12,049 12,071
12,073 12,097 13,033 13,037 13,043 13,049 13,063 13,093 13,099 14,011
14,029 14,033 14,051 14,057 14,071 14,081 14,083 14,087 15,013 15,017
First such number > 10 million is 111,101,129 at zero-based index 39,319
The first 50 blind prime cyclops numbers are:
101 103 107 109 307 401 503 509 601 607
701 709 809 907 11,071 11,087 11,093 12,037 12,049 12,097
13,099 14,029 14,033 14,051 14,071 14,081 14,083 14,087 15,031 15,053
15,083 16,057 16,063 16,067 16,069 16,097 17,021 17,033 17,041 17,047
17,053 17,077 18,047 18,061 18,077 18,089 19,013 19,031 19,051 19,073
First such number > 10 million is 111,101,161 at zero-based index 11,393
The first 50 palindromic prime cyclops numbers are:
101 16,061 31,013 35,053 38,083 73,037 74,047 91,019
94,049 1,120,211 1,150,511 1,160,611 1,180,811 1,190,911 1,250,521 1,280,821
1,360,631 1,390,931 1,490,941 1,520,251 1,550,551 1,580,851 1,630,361 1,640,461
1,660,661 1,670,761 1,730,371 1,820,281 1,880,881 1,930,391 1,970,791 3,140,413
3,160,613 3,260,623 3,310,133 3,380,833 3,460,643 3,470,743 3,590,953 3,670,763
3,680,863 3,970,793 7,190,917 7,250,527 7,310,137 7,540,457 7,630,367 7,690,967
7,750,577 7,820,287
First such number > 10 million is 114,808,411 at zero-based index 66
Julia
Julia's indexes are 1 based, hence one greater than those of 0 based indices. <lang julia>using Primes
print5x10(a, w = 8) = for i in 0:4, j in 1:10 print(lpad(a[10i + j], w), j == 10 ? "\n" : "") end
function iscyclops(n)
d = digits(n) l = length(d) return isodd(l) && d[l ÷ 2 + 1] == 0 && count(x -> x == 0, d) == 1
end
function isblindprimecyclops(n)
d = digits(n) l = length(d) m = l ÷ 2 + 1 (iseven(l) || d[m] != 0 || count(x -> x == 0, d) != 1) && return false return isprime(evalpoly(10, [d[1:m-1]; d[m+1:end]]))
end
function ispalindromicprimecyclops(n)
d = digits(n) l = length(d) return isodd(l) && d[l ÷ 2 + 1] == 0 && count(x -> x == 0, d) == 1 && d == reverse(d)
end
function findcyclops(N, iscycs, nextcandidate)
i, list = 1, Int[]
while length(list) < N
iscycs(i) && push!(list, i)
i = nextcandidate(i)
end
return list
end
function nthcyclopsfirstafter(lowerlimit, iscycs, nextcandidate)
i, found = 1, 0
while true
if iscycs(i)
found += 1
i >= lowerlimit && break
end
i = nextcandidate(i)
end
return i, found
end
function testcyclops()
println("The first 50 cyclops numbers are:")
print5x10(findcyclops(50, iscyclops, x -> x + 1))
n, c = nthcyclopsfirstafter(10000000, iscyclops, x -> x + 1)
println("\nThe next cyclops number after 10,000,000 is $n at position $c.")
println("\nThe first 50 prime cyclops numbers are:")
print5x10(findcyclops(50, iscyclops, x -> nextprime(x + 1)))
n, c = nthcyclopsfirstafter(10000000, iscyclops, x -> nextprime(x + 1))
println("\nThe next prime cyclops number after 10,000,000 is $n at position $c.")
println("\nThe first 50 blind prime cyclops numbers are:")
print5x10(findcyclops(50, isblindprimecyclops, x -> nextprime(x + 1)))
n, c = nthcyclopsfirstafter(10000000, isblindprimecyclops, x -> nextprime(x + 1))
println("\nThe next prime cyclops number after 10,000,000 is $n at position $c.")
println("\nThe first 50 palindromic prime cyclops numbers are:")
print5x10(findcyclops(50, ispalindromicprimecyclops, x -> nextprime(x + 1)))
n, c = nthcyclopsfirstafter(10000000, ispalindromicprimecyclops, x -> nextprime(x + 1))
println("\nThe next prime cyclops number after 10,000,000 is $n at position $c.")
end
testcyclops()
</lang>
- Output:
The first 50 cyclops numbers are:
101 102 103 104 105 106 107 108 109 201
202 203 204 205 206 207 208 209 301 302
303 304 305 306 307 308 309 401 402 403
404 405 406 407 408 409 501 502 503 504
505 506 507 508 509 601 602 603 604 605
The next cyclops number after 10,000,000 is 111101111 at position 538084.
The first 50 prime cyclops numbers are:
101 103 107 109 307 401 409 503 509 601
607 701 709 809 907 11027 11047 11057 11059 11069
11071 11083 11087 11093 12011 12037 12041 12043 12049 12071
12073 12097 13033 13037 13043 13049 13063 13093 13099 14011
14029 14033 14051 14057 14071 14081 14083 14087 15013 15017
The next prime cyclops number after 10,000,000 is 111101129 at position 39320.
The first 50 blind prime cyclops numbers are:
101 103 107 109 307 401 503 509 601 607
701 709 809 907 11071 11087 11093 12037 12049 12097
13099 14029 14033 14051 14071 14081 14083 14087 15031 15053
15083 16057 16063 16067 16069 16097 17021 17033 17041 17047
17053 17077 18047 18061 18077 18089 19013 19031 19051 19073
The next prime cyclops number after 10,000,000 is 111101161 at position 11394.
The first 50 palindromic prime cyclops numbers are:
101 16061 31013 35053 38083 73037 74047 91019 94049 1120211
1150511 1160611 1180811 1190911 1250521 1280821 1360631 1390931 1490941 1520251
1550551 1580851 1630361 1640461 1660661 1670761 1730371 1820281 1880881 1930391
1970791 3140413 3160613 3260623 3310133 3380833 3460643 3470743 3590953 3670763
3680863 3970793 7190917 7250527 7310137 7540457 7630367 7690967 7750577 7820287
The next prime cyclops number after 10,000,000 is 114808411 at position 67.
Phix
You can run this online here (however it is about 5x slower than desktop/Phix, so expect a blank screen for about 45s).
with javascript_semantics function bump(sequence s) sequence res = {} for i=1 to length(s) do integer si = s[i]*10 for j=1 to 9 do res &= si+j end for end for return res end function procedure cyclops(string s="") sequence res = {}, half = {0} integer l = 1, r = 0, h = 1, p = 10, pb = 1, n = 0 bool valid = false, bPrime = match("prime",s), bBlind = match("blind",s), bPalin = match("palindromic",s) while length(res)<50 or n<=1e7 or not valid do r += 1 if r>h then r = 1 l += 1 if l>h then half = bump(half) h *= 9 p *= 10 pb *= 10 l = 1 end if end if integer lh = half[l], rh = half[r] n = lh*p+rh valid = not bPrime or is_prime(n) if valid and bBlind then valid = is_prime(lh*pb+rh) end if if valid and bPalin then valid = sprintf("%d",lh) == reverse(sprintf("%d",rh)) end if if valid then res = append(res,sprintf("%7d",n)) end if end while printf(1,"First 50 %scyclops numbers:\n%s\n",{s,join_by(res[1..50],1,10)}) printf(1,"First %scyclops number > 10,000,000: %s at (one based) index: %d\n\n", {s,res[$],length(res)}) end procedure cyclops() cyclops("prime ") cyclops("blind prime ") cyclops("palindromic prime ")
- Output:
First 50 cyclops numbers:
0 101 102 103 104 105 106 107 108 109
201 202 203 204 205 206 207 208 209 301
302 303 304 305 306 307 308 309 401 402
403 404 405 406 407 408 409 501 502 503
504 505 506 507 508 509 601 602 603 604
First cyclops number > 10,000,000: 111101111 at (one based) index: 538085
First 50 prime cyclops numbers:
101 103 107 109 307 401 409 503 509 601
607 701 709 809 907 11027 11047 11057 11059 11069
11071 11083 11087 11093 12011 12037 12041 12043 12049 12071
12073 12097 13033 13037 13043 13049 13063 13093 13099 14011
14029 14033 14051 14057 14071 14081 14083 14087 15013 15017
First prime cyclops number > 10,000,000: 111101129 at (one based) index: 39320
First 50 blind prime cyclops numbers:
101 103 107 109 307 401 503 509 601 607
701 709 809 907 11071 11087 11093 12037 12049 12097
13099 14029 14033 14051 14071 14081 14083 14087 15031 15053
15083 16057 16063 16067 16069 16097 17021 17033 17041 17047
17053 17077 18047 18061 18077 18089 19013 19031 19051 19073
First blind prime cyclops number > 10,000,000: 111101161 at (one based) index: 11394
First 50 palindromic prime cyclops numbers:
101 16061 31013 35053 38083 73037 74047 91019 94049 1120211
1150511 1160611 1180811 1190911 1250521 1280821 1360631 1390931 1490941 1520251
1550551 1580851 1630361 1640461 1660661 1670761 1730371 1820281 1880881 1930391
1970791 3140413 3160613 3260623 3310133 3380833 3460643 3470743 3590953 3670763
3680863 3970793 7190917 7250527 7310137 7540457 7630367 7690967 7750577 7820287
First palindromic prime cyclops number > 10,000,000: 114808411 at (one based) index: 67
Raku
<lang perl6>use Lingua::EN::Numbers;
my @cyclops = 0, |flat lazy ^∞ .map: -> $exp {
my @oom = (exp($exp, 10) ..^ exp($exp + 1, 10)).grep: { !.contains: 0 }
|@oom.hyper.map: { $_ ~ 0 «~« @oom }
}
my @prime-cyclops = @cyclops.grep: { .is-prime };
for , @cyclops,
'prime ', @prime-cyclops,
'blind prime ', @prime-cyclops.grep( { .trans('0' => ).is-prime } ),
'palindromic prime ', @prime-cyclops.grep( { $_ eq .flip } )
-> $type, $iterator {
say "\n\nFirst 50 {$type}cyclops numbers:\n" ~ $iterator[^50].batch(10)».fmt("%7d").join("\n") ~
"\n\nFirst {$type}cyclops number > 10,000,000: " ~ comma($iterator.first: * > 1e7 ) ~
" - at (zero based) index: " ~ comma $iterator.first: * > 1e7, :k;
}</lang>
- Output:
First 50 cyclops numbers:
0 101 102 103 104 105 106 107 108 109
201 202 203 204 205 206 207 208 209 301
302 303 304 305 306 307 308 309 401 402
403 404 405 406 407 408 409 501 502 503
504 505 506 507 508 509 601 602 603 604
First cyclops number > 10,000,000: 111,101,111 - at (zero based) index: 538,084
First 50 prime cyclops numbers:
101 103 107 109 307 401 409 503 509 601
607 701 709 809 907 11027 11047 11057 11059 11069
11071 11083 11087 11093 12011 12037 12041 12043 12049 12071
12073 12097 13033 13037 13043 13049 13063 13093 13099 14011
14029 14033 14051 14057 14071 14081 14083 14087 15013 15017
First prime cyclops number > 10,000,000: 111,101,129 - at (zero based) index: 39,319
First 50 blind prime cyclops numbers:
101 103 107 109 307 401 503 509 601 607
701 709 809 907 11071 11087 11093 12037 12049 12097
13099 14029 14033 14051 14071 14081 14083 14087 15031 15053
15083 16057 16063 16067 16069 16097 17021 17033 17041 17047
17053 17077 18047 18061 18077 18089 19013 19031 19051 19073
First blind prime cyclops number > 10,000,000: 111,101,161 - at (zero based) index: 11,393
First 50 palindromic prime cyclops numbers:
101 16061 31013 35053 38083 73037 74047 91019 94049 1120211
1150511 1160611 1180811 1190911 1250521 1280821 1360631 1390931 1490941 1520251
1550551 1580851 1630361 1640461 1660661 1670761 1730371 1820281 1880881 1930391
1970791 3140413 3160613 3260623 3310133 3380833 3460643 3470743 3590953 3670763
3680863 3970793 7190917 7250527 7310137 7540457 7630367 7690967 7750577 7820287
First palindromic prime cyclops number > 10,000,000: 114,808,411 - at (zero based) index: 66
REXX
<lang rexx>/*REXX pprogram finds and displays the first fifty cyclops numbers, cyclops primes,*/ /*─────────────────────────────── blind cyclops primes, and palindromic cyclops primes.*/ parse arg n cols . /*obtain optional argument from the CL.*/ if n== | n=="," then n= 50 /*Not specified? Then use the default.*/ if cols== | cols=="," then cols= 10 /* " " " " " " */ call genP /*build array of semaphores for primes.*/ w= max(10, length( commas(@.#) ) ) /*max width of a number in any column. */
first= ' the first '
isPri= 0; isBli= 0; isPal= 0; call 0 first commas(n) " cyclops numbers" isPri= 1; isBli= 0; isPal= 0; call 0 first commas(n) " prime cyclops numbers" isPri= 1; isBli= 1; isPal= 0; call 0 first commas(n) " blind prime cyclops numbers" isPri= 1; isBli= 0; isPal= 1; call 0 first commas(n) " palindromic prime cyclops numbers" exit 0 /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ commas: parse arg ?; do jc=length(?)-3 to 1 by -3; ?=insert(',', ?, jc); end; return ? /*──────────────────────────────────────────────────────────────────────────────────────*/ 0: parse arg title /*get the title of this output section.*/
say ' index │'center(title, 1 + cols*(w+1) )
say '───────┼'center("" , 1 + cols*(w+1), '─')
finds= 0; idx= 1 /*define # of a type of cyclops # & idx*/
$= /*$: list of the numbers found (so far)*/
do j=0 until finds== n; L= length(j) /*$: list of the numbers found (so far)*/
if L//2==0 then do; j= left(1, L+1, 0) /*Is J an even # of digits? Yes, bump J*/
iterate /*use a new J that has odd # of digits.*/
end
z= pos(0, j); if z\==(L+1)%2 then iterate /* " " " " (zero in mid)? " */
if pos(0, j, z+1)>0 then iterate /* " " " " (has two 0's)? " */
if isPri then if \!.j then iterate /*Need a cyclops prime? Then skip.*/
if isBli then do; ?= space(translate(j,,0), 0) /*Need a blind cyclops prime ? */
if \!.? then iterate /*Not a blind cyclops prime? Then skip.*/
end
if isPal then do; r= reverse(j) /*Need a palindromic cyclops prime? */
if r\==j then iterate /*Cyclops number not palindromic? Skip.*/
if \!.r then iterate /*Cyclops palindromic not prime? Skip.*/
end
finds= finds + 1 /*bump the number of palindromic primes*/
if cols<0 then iterate /*Build the list (to be shown later)? */
$= $ right( commas(j), w) /*add a palindromic prime ──► $ list.*/
if finds//cols\==0 then iterate /*have we populated a line of output? */
say center(idx, 7)'│' substr($, 2); $= /*display what we have so far (cols). */
idx= idx + cols /*bump the index count for the output*/
end /*j*/
if $\== then say center(idx, 7)"│" substr($, 2) /*possible show residual output.*/
say '───────┴'center("" , 1 + cols*(w+1), '─'); say
return
/*──────────────────────────────────────────────────────────────────────────────────────*/ genP: !.= 0; hip= 8000000 - 1 /*placeholders for primes (semaphores).*/
@.1=2; @.2=3; @.3=5; @.4=7; @.5=11 /*define some low primes. */
!.2=1; !.3=1; !.5=1; !.7=1; !.11=1 /* " " " " flags. */
#=5; s.#= @.# **2 /*number of primes so far; prime². */
do j=@.#+2 by 2 to hip /*find odd primes from here on. */
parse var j -1 _; if _==5 then iterate /*J divisible by 5? (right dig)*/
if j// 3==0 then iterate /*" " " 3? */
if j// 7==0 then iterate /*" " " 7? */
do k=5 while s.k<=j /* [↓] divide by the known odd primes.*/
if j // @.k == 0 then iterate j /*Is J ÷ X? Then not prime. ___ */
end /*k*/ /* [↑] only process numbers ≤ √ J */
#= #+1; @.#= j; s.#= j*j; !.j= 1 /*bump # of Ps; assign next P; P²; P# */
end /*j*/; return</lang>
- output when using the default inputs:
index │ the first 50 cyclops numbers ───────┼─────────────────────────────────────────────────────────────────────────────────────────────────────────────── 1 │ 0 101 102 103 104 105 106 107 108 109 11 │ 201 202 203 204 205 206 207 208 209 301 21 │ 302 303 304 305 306 307 308 309 401 402 31 │ 403 404 405 406 407 408 409 501 502 503 41 │ 504 505 506 507 508 509 601 602 603 604 ───────┴─────────────────────────────────────────────────────────────────────────────────────────────────────────────── index │ the first 50 prime cyclops numbers ───────┼─────────────────────────────────────────────────────────────────────────────────────────────────────────────── 1 │ 101 103 107 109 307 401 409 503 509 601 11 │ 607 701 709 809 907 11,027 11,047 11,057 11,059 11,069 21 │ 11,071 11,083 11,087 11,093 12,011 12,037 12,041 12,043 12,049 12,071 31 │ 12,073 12,097 13,033 13,037 13,043 13,049 13,063 13,093 13,099 14,011 41 │ 14,029 14,033 14,051 14,057 14,071 14,081 14,083 14,087 15,013 15,017 ───────┴─────────────────────────────────────────────────────────────────────────────────────────────────────────────── index │ the first 50 blind prime cyclops numbers ───────┼─────────────────────────────────────────────────────────────────────────────────────────────────────────────── 1 │ 101 103 107 109 307 401 503 509 601 607 11 │ 701 709 809 907 11,071 11,087 11,093 12,037 12,049 12,097 21 │ 13,099 14,029 14,033 14,051 14,071 14,081 14,083 14,087 15,031 15,053 31 │ 15,083 16,057 16,063 16,067 16,069 16,097 17,021 17,033 17,041 17,047 41 │ 17,053 17,077 18,047 18,061 18,077 18,089 19,013 19,031 19,051 19,073 ───────┴─────────────────────────────────────────────────────────────────────────────────────────────────────────────── index │ the first 50 palindromic prime cyclops numbers ───────┼─────────────────────────────────────────────────────────────────────────────────────────────────────────────── 1 │ 101 16,061 31,013 35,053 38,083 73,037 74,047 91,019 94,049 1,120,211 11 │ 1,150,511 1,160,611 1,180,811 1,190,911 1,250,521 1,280,821 1,360,631 1,390,931 1,490,941 1,520,251 21 │ 1,550,551 1,580,851 1,630,361 1,640,461 1,660,661 1,670,761 1,730,371 1,820,281 1,880,881 1,930,391 31 │ 1,970,791 3,140,413 3,160,613 3,260,623 3,310,133 3,380,833 3,460,643 3,470,743 3,590,953 3,670,763 41 │ 3,680,863 3,970,793 7,190,917 7,250,527 7,310,137 7,540,457 7,630,367 7,690,967 7,750,577 7,820,287 ───────┴───────────────────────────────────────────────────────────────────────────────────────────────────────────────
Wren
<lang ecmascript>import "/math" for Int import "/seq" for Lst import "/fmt" for Fmt import "/str" for Str
var findFirst = Fn.new { |list|
var i = 0
for (n in list) {
if (n > 1e7) return [n, i]
i = i + 1
}
}
var ranges = [0..0, 101..909, 11011..99099, 1110111..9990999, 111101111..119101111] var cyclops = [] for (r in ranges) {
var numDigits = r.from.toString.count
var center = (numDigits / 2).floor
for (i in r) {
var digits = Int.digits(i)
if (digits[center] == 0 && digits.count { |d| d == 0 } == 1) cyclops.add(i)
}
}
System.print("The first 50 cyclops numbers are:") var candidates = cyclops[0...50] var ni = findFirst.call(cyclops) for (chunk in Lst.chunks(candidates, 10)) Fmt.print("$,6d", chunk) Fmt.print("\nFirst such number > 10 million is $,d at zero-based index $,d", ni[0], ni[1])
System.print("\n\nThe first 50 prime cyclops numbers are:") var primes = cyclops.where { |n| Int.isPrime(n) } candidates = primes.take(50).toList ni = findFirst.call(primes) for (chunk in Lst.chunks(candidates, 10)) Fmt.print("$,6d", chunk) Fmt.print("\nFirst such number > 10 million is $,d at zero-based index $,d", ni[0], ni[1])
System.print("\n\nThe first 50 blind prime cyclops numbers are:") var bpcyclops = [] var ppcyclops = [] for (p in primes) {
var ps = p.toString var numDigits = ps.count var center = (numDigits/2).floor var noMiddle = Num.fromString(Str.delete(ps, center)) if (Int.isPrime(noMiddle)) bpcyclops.add(p) if (ps == ps[-1..0]) ppcyclops.add(p)
} candidates = bpcyclops[0...50] ni = findFirst.call(bpcyclops) for (chunk in Lst.chunks(candidates, 10)) Fmt.print("$,6d", chunk) Fmt.print("\nFirst such number > 10 million is $,d at zero-based index $,d", ni[0], ni[1])
System.print("\n\nThe first 50 palindromic prime cyclops numbers are:") candidates = ppcyclops[0...50] ni = findFirst.call(ppcyclops) for (chunk in Lst.chunks(candidates, 8)) Fmt.print("$,9d", chunk) Fmt.print("\nFirst such number > 10 million is $,d at zero-based index $,d", ni[0], ni[1])</lang>
- Output:
The first 50 cyclops numbers are:
0 101 102 103 104 105 106 107 108 109
201 202 203 204 205 206 207 208 209 301
302 303 304 305 306 307 308 309 401 402
403 404 405 406 407 408 409 501 502 503
504 505 506 507 508 509 601 602 603 604
First such number > 10 million is 111,101,111 at zero-based index 538,084
The first 50 prime cyclops numbers are:
101 103 107 109 307 401 409 503 509 601
607 701 709 809 907 11,027 11,047 11,057 11,059 11,069
11,071 11,083 11,087 11,093 12,011 12,037 12,041 12,043 12,049 12,071
12,073 12,097 13,033 13,037 13,043 13,049 13,063 13,093 13,099 14,011
14,029 14,033 14,051 14,057 14,071 14,081 14,083 14,087 15,013 15,017
First such number > 10 million is 111,101,129 at zero-based index 39,319
The first 50 blind prime cyclops numbers are:
101 103 107 109 307 401 503 509 601 607
701 709 809 907 11,071 11,087 11,093 12,037 12,049 12,097
13,099 14,029 14,033 14,051 14,071 14,081 14,083 14,087 15,031 15,053
15,083 16,057 16,063 16,067 16,069 16,097 17,021 17,033 17,041 17,047
17,053 17,077 18,047 18,061 18,077 18,089 19,013 19,031 19,051 19,073
First such number > 10 million is 111,101,161 at zero-based index 11,393
The first 50 palindromic prime cyclops numbers are:
101 16,061 31,013 35,053 38,083 73,037 74,047 91,019
94,049 1,120,211 1,150,511 1,160,611 1,180,811 1,190,911 1,250,521 1,280,821
1,360,631 1,390,931 1,490,941 1,520,251 1,550,551 1,580,851 1,630,361 1,640,461
1,660,661 1,670,761 1,730,371 1,820,281 1,880,881 1,930,391 1,970,791 3,140,413
3,160,613 3,260,623 3,310,133 3,380,833 3,460,643 3,470,743 3,590,953 3,670,763
3,680,863 3,970,793 7,190,917 7,250,527 7,310,137 7,540,457 7,630,367 7,690,967
7,750,577 7,820,287
First such number > 10 million is 114,808,411 at zero-based index 66