Catalan numbers: Difference between revisions
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This would also work with langur prior to 0.8 with smaller numbers. 0.8 uses arbitrary precision.
{{trans|Perl}}
{{works with|langur|0.8}}
<lang langur>val .factorial = f if(.x < 2: 1; .x x self(.x - 1))
val .catalan = f(.n) .factorial(2 x .n) / .factorial(.n+1) / .factorial(.n)
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