Benford's law: Difference between revisions

Added Easylang
m (→‎{{header|Fōrmulæ}}: fixing typos)
(Added Easylang)
Line 1,090:
=={{header|Delphi}}==
See [[Benford's law#Pascal|Pascal]].
 
=={{header|EasyLang}}==
<syntaxhighlight lang=easylang>
func$ add a$ b$ .
for i to higher len a$ len b$
a = number substr a$ i 1
b = number substr b$ i 1
r = a + b + c
c = r div 10
r$ &= r mod 10
.
if c > 0
r$ &= c
.
return r$
.
#
len fibdist[] 9
proc mkfibdist . .
# generate 1000 fibonacci numbers as
# (reversed) strings, because 53 bit
# integers are too small
#
n = 1000
prev$ = 0
val$ = 1
fibdist[1] = 1
for i = 2 to n
h$ = add prev$ val$
prev$ = val$
val$ = h$
ind = number substr val$ len val$ 1
fibdist[ind] += 1
.
for i to len fibdist[]
fibdist[i] = fibdist[i] / n
.
.
mkfibdist
#
func log10 x .
return logn x / logn 10
.
len benfdist[] 9
proc mkbenfdist . .
for i to 9
benfdist[i] = log10 (1 + 1.0 / i)
.
.
mkbenfdist
#
numfmt 3 0
print "Actual Expected"
for i to 9
print fibdist[i] & " " & benfdist[i]
.
</syntaxhighlight>
{{out}}
<pre>
Actual Expected
0.301 0.301
0.177 0.176
0.125 0.125
0.096 0.097
0.080 0.079
0.067 0.067
0.056 0.058
0.053 0.051
0.045 0.046
</pre>
 
=={{header|Elixir}}==
Line 1,124 ⟶ 1,194:
9 0.045 0.04575749056067514
</pre>
 
=={{header|Erlang}}==
<syntaxhighlight lang="erlang">
2,068

edits