Babbage problem: Difference between revisions
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</pre>
=={{header|Phix}}==
We can omit anything odd, as any odd number squared is obviously always odd.
<lang Phix>for i=2 to 99736 by 2 do
if remainder(i*i,1000000)=269696 then ?i exit end if
end for</lang>
{{out}}
<pre>
25264
</pre>
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