Averages/Root mean square: Difference between revisions

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===Not using a loop===
===Avoiding a loop===
Using these equations:<br>
Using these equations:<br>
<math>\sum_{i=1}^n i^2 = \frac{n(n+1)(2n+1)}{6}</math> See [[wp:List of mathematical series]]<br><br>
<math>\sum_{i=1}^n i^2 = \frac{n(n+1)(2n+1)}{6}</math> See [[wp:List of mathematical series]]<br><br>