Array concatenation: Difference between revisions

=={{header|S-lang}}==

<lang S-lang>variable a = [1, 2, 3];

variable b = [4, 5, 6];</lang>

a+b is perfectly valid in S-Lang, but instead of the problem's desired

effect, it gives you a new array with each cooresponding element from

a and b added. Instead:

<lang S-lang>variable la = length(a), c = _typeof(a)[la+length(b)];

c[ [:la-1] ] = a;

c[ [la:] ] = b;</lang>

If you can make do with using lists not arrays for a and b, it's trivial:

<lang S-lang>a = {1, 2, 3};

b = {4, 5, 6};

variable c = list_concat(a, b);</lang>

behaves as in the array concatination above. Then, if you need an array:

<lang S-lang>c = list_to_array(c);</lang>

As an alternative:

<lang S-lang>list_join(a, b);</lang>

adds the elements of b onto a.