Arithmetic derivative: Difference between revisions
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;*[[wp:Arithmetic_derivative|Wikipedia: Arithmetic Derivative]]
=={{header|Go}}==
{{libheader|Go-rcu}}
Using ''float64'' (finessed a little) to avoid the unpleasantness of ''math/big'' for the stretch goal.
Assumes that ''int'' type is 64 bit.
<lang go>package main
import (
"fmt"
"rcu"
)
func D(n float64) float64 {
if n < 0 {
return -D(-n)
}
if n < 2 {
return 0
}
var f []int
if n < 1e19 {
f = rcu.PrimeFactors(int(n))
} else {
g := int(n / 100)
f = rcu.PrimeFactors(g)
f = append(f, []int{2, 2, 5, 5}...)
}
c := len(f)
if c == 1 {
return 1
}
if c == 2 {
return float64(f[0] + f[1])
}
d := n / float64(f[0])
return D(d)*float64(f[0]) + d
}
func main() {
ad := make([]int, 200)
for n := -99; n < 101; n++ {
ad[n+99] = int(D(float64(n)))
}
rcu.PrintTable(ad, 10, 4, false)
fmt.Println()
pow := 1.0
for m := 1; m < 21; m++ {
pow *= 10
fmt.Printf("D(10^%-2d) / 7 = %.0f\n", m, D(pow)/7)
}
}</lang>
{{out}}
<pre>
-75 -77 -1 -272 -24 -49 -34 -96 -20 -123
-1 -140 -32 -45 -22 -124 -1 -43 -108 -176
-1 -71 -18 -80 -55 -39 -1 -156 -1 -59
-26 -72 -1 -61 -18 -192 -51 -33 -1 -92
-1 -31 -22 -92 -16 -81 -1 -56 -20 -45
-14 -112 -1 -25 -39 -48 -1 -41 -1 -68
-16 -21 -1 -60 -12 -19 -14 -80 -1 -31
-1 -32 -27 -15 -10 -44 -1 -13 -10 -24
-1 -21 -1 -32 -8 -9 -1 -16 -1 -7
-6 -12 -1 -5 -1 -4 -1 -1 0 0
0 1 1 4 1 5 1 12 6 7
1 16 1 9 8 32 1 21 1 24
10 13 1 44 10 15 27 32 1 31
1 80 14 19 12 60 1 21 16 68
1 41 1 48 39 25 1 112 14 45
20 56 1 81 16 92 22 31 1 92
1 33 51 192 18 61 1 72 26 59
1 156 1 39 55 80 18 71 1 176
108 43 1 124 22 45 32 140 1 123
20 96 34 49 24 272 1 77 75 140
D(10^1 ) / 7 = 1
D(10^2 ) / 7 = 20
D(10^3 ) / 7 = 300
D(10^4 ) / 7 = 4000
D(10^5 ) / 7 = 50000
D(10^6 ) / 7 = 600000
D(10^7 ) / 7 = 7000000
D(10^8 ) / 7 = 80000000
D(10^9 ) / 7 = 900000000
D(10^10) / 7 = 10000000000
D(10^11) / 7 = 110000000000
D(10^12) / 7 = 1200000000000
D(10^13) / 7 = 13000000000000
D(10^14) / 7 = 140000000000000
D(10^15) / 7 = 1500000000000000
D(10^16) / 7 = 16000000000000000
D(10^17) / 7 = 170000000000000000
D(10^18) / 7 = 1800000000000000000
D(10^19) / 7 = 19000000000000000000
D(10^20) / 7 = 200000000000000000000
</pre>
=={{header|J}}==
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