Arbitrary-precision integers (included): Difference between revisions
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n digits = 183231 |
n digits = 183231 |
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Iterative elasped: 2412.5477 milliseconds.</pre>'''Remarks:''' Not much difference in execution times for three methods. But the exponents are relatively small. If one does need to evaluate an exponent greater than '''Int32.MaxValue''', the execution time will be measured in hours. |
Iterative elasped: 2412.5477 milliseconds.</pre>'''Remarks:''' Not much difference in execution times for three methods. But the exponents are relatively small. If one does need to evaluate an exponent greater than '''Int32.MaxValue''', the execution time will be measured in hours. |
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=={{header|Vlang}}== |
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<lang vlang>import math.big |
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import math |
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fn main() { |
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mut x := u32(math.pow(3,2)) |
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x = u32(math.pow(4,x)) |
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mut y := big.integer_from_int(5) |
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y = y.pow(x) |
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str := y.str() |
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println("5^(4^(3^2)) has $str.len digits: ${str[..20]} ... ${str[str.len-20..]}") |
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}</lang> |
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{{out}} |
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<pre> |
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5^(4^(3^2)) has 183231 digits: 62060698786608744707 ... 9225625991821289062 |
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</pre> |
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=={{header|Wren}}== |
=={{header|Wren}}== |
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