Arbitrary-precision integers (included): Difference between revisions

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5^4^3^2 = 62060698786608744707...92256259918212890625 and has 183231 digits
5^4^3^2 = 62060698786608744707...92256259918212890625 and has 183231 digits
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</pre>

=={{header|Lambdatalk}}==
Just using Javascript's BigInt
<syntaxhighlight lang="Scheme">

{def N {BI.** 5 {BI.** 4 {BI.** 3 2}}}} -> N
length: {def L {W.length {N}}} -> L = 183231
20 first digits: {W.slice 0 20 {N}} -> 62060698786608744707
20 last digits: {W.slice -20 {L} {N}} -> 92256259918212890625

</syntaxhighlight>


=={{header|langur}}==
=={{header|langur}}==