Apply a digital filter (direct form II transposed): Difference between revisions

Line 738:
0.9619 0.6957 0.4244 0.1963 -0.0278 -0.2117 -0.1747 0.0693 0.3854 0.6518
</pre>
 
=={{header|Nim}}==
{{trans|Kotlin}}
<lang Nim>
import strformat
 
func filter(a, b, signal: openArray[float]): seq[float] =
 
result.setLen(signal.len)
 
for i in 0..signal.high:
var tmp = 0.0
for j in 0..min(i, b.high):
tmp += b[j] * signal[i - j]
for j in 1..min(i, a.high):
tmp -= a[j] * result[i - j]
tmp /= a[0]
result[i] = tmp
 
#———————————————————————————————————————————————————————————————————————————————————————————————————
 
let a = [1.00000000, -2.77555756e-16, 3.33333333e-01, -1.85037171e-17]
let b = [0.16666667, 0.5, 0.5, 0.16666667]
 
let signal = [-0.917843918645, 0.141984778794, 1.20536903482, 0.190286794412,
-0.662370894973, -1.00700480494, -0.404707073677, 0.800482325044,
0.743500089861, 1.01090520172, 0.741527555207, 0.277841675195,
0.400833448236, -0.2085993586, -0.172842103641, -0.134316096293,
0.0259303398477, 0.490105989562, 0.549391221511, 0.9047198589]
 
let result = filter(a, b, signal)
for i in 0..result.high:
stdout.write fmt"{result[i]: .8f}"
stdout.write if (i + 1) mod 5 != 0: ", " else: "\n"</lang>
 
{{out}}
<pre>-0.15297399, -0.43525783, -0.13604340, 0.69750333, 0.65644469
-0.43548245, -1.08923946, -0.53767655, 0.51704999, 1.05224975
0.96185430, 0.69569009, 0.42435630, 0.19626223, -0.02783512
-0.21172192, -0.17474556, 0.06925841, 0.38544587, 0.65177084</pre>
 
=={{header|Objeck}}==
Anonymous user